Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 261-270 of 600 questions.
If (p(x)=4x-2-5x+2), what is the value of (p(3))?
B. (23)
(p(3)=4(3)2-5(3)+2=36-15+2=23)। प्रतिस्थापन में पहले घात निकालें। / (p(3)=4(3)2-5(3)+2=36-15+2=23). Evaluate powers first while substituting.
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If (q(x)=x-3+2x-2-4x), what is the value of (q(-2))?
C. (8)
(q(-2)=(-2)3+2(-2)2-4(-2)=-8+8+8=8)। ऋणात्मक मान रखते समय कोष्ठक लगाएँ। / (q(-2)=(-2)3+2(-2)2-4(-2)=-8+8+8=8). Use parentheses for negative substitution.
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What is the simplified form of \(5x^2-3x^2+7x^2\)?
A. \(9x^2\)
समान पदों के गुणांक (5-3+7=9) हैं। इसलिए सरल रूप \(9x^2\) है। / The coefficients of like terms are (5-3+7=9). Thus the simplified form is \(9x^2\).
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What is the simplified form of ((3x+4)+(5x-9))?
A. (8x-5)
समान पद जोड़ने पर (3x+5x=8x) और (4-9=-5) है। इसलिए उत्तर (8x-5) है। / Combining like terms gives (3x+5x=8x) and (4-9=-5). So the answer is (8x-5).
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What is the simplified form of ((9x+2)-(4x-6))?
B. (5x+8)
ऋण चिह्न दूसरे कोष्ठक के दोनों पदों पर लगेगा। (9x+2-4x+6=5x+8) है। / The minus sign applies to both terms in the second bracket. (9x+2-4x+6=5x+8).
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What is the expansion of (4x\(3x^2-2x+5\))?
A. \(12x^3-8x^2+20x\)
(4x) को हर पद से गुणा करें। इससे \(12x^3-8x^2+20x\) मिलता है। / Multiply (4x) by every term. This gives \(12x^3-8x^2+20x\).
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What is the expansion of ((x+6)(x+4))?
A. \(x^2+10x+24\)
वितरण नियम से \(x^2+4x+6x+24=x^2+10x+24\) मिलता है। मध्य पद समान पद जोड़कर बनता है। / By distribution, \(x^2+4x+6x+24=x^2+10x+24\). The middle term forms by combining like terms.
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What is the expansion of ((x-7)(x+3))?
A. \(x^2-4x-21\)
गुणा करने पर \(x^2+3x-7x-21=x^2-4x-21\) है। चिह्नों पर ध्यान दें। / Multiplying gives \(x^2+3x-7x-21=x^2-4x-21\). Pay attention to signs.
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What is the expansion of ((4x+5)(x-3))?
A. \(4x^2-7x-15\)
वितरण से \(4x^2-12x+5x-15=4x^2-7x-15\) है। समान पदों को अंत में जोड़ें। / By distribution, \(4x^2-12x+5x-15=4x^2-7x-15\). Combine like terms at the end.
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What is the correct expansion of ((x+10)2)?
A. \(x^2+20x+100\)
((a+b)2=a-2+2ab+b-2) लगाएँ। यहाँ मध्य पद \(2\cdot x\cdot10=20x\) है। / Use ((a+b)2=a-2+2ab+b-2). Here the middle term is \(2\cdot x\cdot10=20x\).
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