Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 281-290 of 600 questions.
What is the value of \(3.5^2-2.5^2\)?
B. (6)
(a-2-b-2=(a-b)(a+b)) से ((3.5-2.5)(3.5+2.5)=1\cdot6=6)। पहचान दशमलव में भी लागू होती है। / Using (a-2-b-2=(a-b)(a+b)), ((3.5-2.5)(3.5+2.5)=1\cdot6=6). Identities also work with decimals.
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If (a=2) and (b=5), what is the value of \(a^2b+ab^2\)?
B. (70)
(a-2b+ab-2=ab(a+b)) है। इसलिए \(2\cdot5\cdot7=70\) है। / (a-2b+ab-2=ab(a+b)). Thus \(2\cdot5\cdot7=70\).
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What is obtained by taking the common factor from \(4x^5+12x^4\)?
A. (4x-4(x+3))
दोनों पदों में सामान्य गुणनखंड \(4x^4\) है। इसलिए रूप (4x-4(x+3)) है। / The common factor in both terms is \(4x^4\). Hence the form is (4x-4(x+3)).
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What is the product of (\(6x^2y\)\(3xy^4\))?
A. \(18x^3y^5\)
गुणांक (18), \(x^{2+1}=x^3\) और \(y^{1+4}=y^5\) है। समान आधार की घातें जोड़ें। / The coefficient is (18), \(x^{2+1}=x^3\), and \(y^{1+4}=y^5\). Add exponents of like bases.
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If (x=4), what is the value of \(x^3-3x^2+2x\)?
C. (24)
मान रखने पर (64-3(16)+8=64-48+8=24)। पहले घात निकालना सही क्रम है। / Substituting gives (64-3(16)+8=64-48+8=24). Calculating powers first is the correct order.
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If (x=-4), what is the value of \(x^4+x^3\)?
B. (192)
((-4)4=256) और ((-4)3=-64) है। इसलिए (256-64=192) है। / ((-4)4=256) and ((-4)3=-64). Hence (256-64=192).
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What is the simplified form of \(\frac{x^8y^{-4}}{x^5y^{-6}}\) if \(x\neq0\) and \(y\neq0\)?
A. \(x^3y^2\)
(x) की घात (8-5=3) और (y) की घात (-4-(-6)=2) है। इसलिए \(x^3y^2\) है। / The exponent of (x) is (8-5=3), and that of (y) is (-4-(-6)=2). Hence it is \(x^3y^2\).
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D. \(\frac{a^2}{b^4}\)
अंदर \(\frac{a^{-2}}{b^{-4}}=a^{-2}b^4\) है। बाहरी (-1) घात से \(\frac{a^2}{b^4}\) मिलता है। / Inside, \(\frac{a^{-2}}{b^{-4}}=a^{-2}b^4\). The outside power (-1) gives \(\frac{a^2}{b^4}\).
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What is the value of (\left\(5^2\right\)0+2^{-3})?
B. \(\frac{9}{8}\)
(\left\(5^2\right\)0=1) और \(2^{-3}=\frac{1}{8}\) है। इसलिए योग \(\frac{9}{8}\) है। / (\left\(5^2\right\)0=1) and \(2^{-3}=\frac{1}{8}\). Therefore the sum is \(\frac{9}{8}\).
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What is the value of \(16^{-1}+4^{-2}\)?
A. \(\frac{1}{8}\)
\(16^{-1}=\frac{1}{16}\) और \(4^{-2}=\frac{1}{16}\) है। इसलिए योग \(\frac{1}{8}\) है। / \(16^{-1}=\frac{1}{16}\) and \(4^{-2}=\frac{1}{16}\). So the sum is \(\frac{1}{8}\).
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