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What is the value of \(\left(5^2\right)^0+2^{-3}\)?\(\left(5^2\right)^0+2^{-3}\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\frac{9}{8}\)\(\frac{9}{8}\)
Since \(5^2\) is nonzero, \((5^2)^0=1\). Also, \(2^{-3}=1/2^3=1/8\). Therefore, the value is \(1+1/8=9/8\).चूँकि \(5^2\) शून्य नहीं है, इसलिए \((5^2)^0=1\)। साथ ही, \(2^{-3}=1/2^3=1/8\)। अतः मान \(1+1/8=9/8\) है।
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