powers-of-three se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.
3 questions tagged with powers-of-three.
What is the value of \(3^5\cdot9^{-1}\)?
B. (27)
(9^{-1}=\(3^2\)^{-1}=3^{-2}). Hence \(3^5\cdot3^{-2}=3^3=27\).
The correct answer is B. (27). (9^{-1}=\(3^2\)^{-1}=3^{-2}). Hence \(3^5\cdot3^{-2}=3^3=27\).
(9^{-1}=\(3^2\)^{-1}=3^{-2}) है। इसलिए \(3^5\cdot3^{-2}=3^3=27\) है।
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What is the simplified form of \(\frac{27^2}{3^4}\)?
A. \(3^2\)
(272=\(3^3\)2=36). Therefore \(\frac{3^6}{3^4}=3^2\).
The correct answer is A. \(3^2\). (272=\(3^3\)2=36). Therefore \(\frac{3^6}{3^4}=3^2\).
(272=\(3^3\)2=36) होता है। इसलिए \(\frac{3^6}{3^4}=3^2\) है।
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After how many decimal places will \(\frac{243}{2^5\cdot 3^5\cdot 5^4}\) terminate?
B. (5)
Since \(243=3^5\), the reduced denominator is \(2^5\cdot 5^4\). The larger exponent is (5), so the decimal terminates after (5) places.
The correct answer is B. (5). Since \(243=3^5\), the reduced denominator is \(2^5\cdot 5^4\). The larger exponent is (5), so the decimal terminates after (5) places.
\(243=3^5\) कटने पर हर \(2^5\cdot 5^4\) बचेगा। बड़ी घात (5) है इसलिए दशमलव (5) स्थानों पर समाप्त होगा।
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