A. बिंदु (\left\(6,2\right\))/Point (\left\(6,2\right\))
Step 1
Concept
Subtracting the equations gives (2x=12), so (x=6) and (y=2). This is the intersection point on the graph.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(6,2\right\)) / Point (\left\(6,2\right\)). Subtracting the equations gives (2x=12), so (x=6) and (y=2). This is the intersection point on the graph.
Step 3
Exam Tip
दोनों समीकरण घटाने पर (2x=12), इसलिए (x=6) और (y=2)। ग्राफ पर यही प्रतिच्छेद बिंदु है।
A. बिंदु (\left\(6,\frac{11}{3}\right\))/Point (\left\(6,\frac{11}{3}\right\))
Step 1
Concept
Subtracting the equations gives (x=6), then (6+3y=17) gives \(y=\frac{11}{3}\). Fraction coordinates can also be graphical solutions.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(6,\frac{11}{3}\right\)) / Point (\left\(6,\frac{11}{3}\right\)). Subtracting the equations gives (x=6), then (6+3y=17) gives \(y=\frac{11}{3}\). Fraction coordinates can also be graphical solutions.
Step 3
Exam Tip
दोनों समीकरण घटाने पर (x=6), फिर (6+3y=17) से \(y=\frac{11}{3}\)। भिन्न निर्देशांक भी ग्राफीय हल हो सकते हैं।
A. बिंदु (\left\(5,6\right\))/Point (\left\(5,6\right\))
Step 1
Concept
Subtracting the equations gives (2x=10), so (x=5) and (y=6). On the graph this is where the paths meet.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(5,6\right\)) / Point (\left\(5,6\right\)). Subtracting the equations gives (2x=10), so (x=5) and (y=6). On the graph this is where the paths meet.
Step 3
Exam Tip
दोनों समीकरण घटाने पर (2x=10), इसलिए (x=5) और (y=6)। ग्राफ पर यही पथों का मिलन बिंदु है।
A. बिंदु (\left\(4,4\right\))/Point (\left\(4,4\right\))
Step 1
Concept
Subtracting the equations gives (x=4), then (4+y=8) gives (y=4). In a real situation, the meeting point is the intersection.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(4,4\right\)) / Point (\left\(4,4\right\)). Subtracting the equations gives (x=4), then (4+y=8) gives (y=4). In a real situation, the meeting point is the intersection.
Step 3
Exam Tip
दोनों समीकरण घटाने पर (x=4), फिर (4+y=8) से (y=4)। वास्तविक स्थिति में मिलन बिंदु ही प्रतिच्छेद है।
A. बिंदु (\left\(5,7\right\))/Point (\left\(5,7\right\))
Step 1
Concept
Putting (x=5) gives (2\left\(5\right\)+y=17), so (y=7). In a vertical line, (x) is already fixed.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(5,7\right\)) / Point (\left\(5,7\right\)). Putting (x=5) gives (2\left\(5\right\)+y=17), so (y=7). In a vertical line, (x) is already fixed.
Step 3
Exam Tip
(x=5) रखने पर (2\left\(5\right\)+y=17), इसलिए (y=7)। ऊर्ध्वाधर रेखा में (x) पहले से तय रहता है।
A. बिंदु (\left\(3,3\right\))/Point (\left\(3,3\right\))
Step 1
Concept
At (\left\(3,3\right\)), (2\left\(3\right\)+5\left\(3\right\)=21) and (3+3=6). This is the common point of both lines.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(3,3\right\)) / Point (\left\(3,3\right\)). At (\left\(3,3\right\)), (2\left\(3\right\)+5\left\(3\right\)=21) and (3+3=6). This is the common point of both lines.
Step 3
Exam Tip
(\left\(3,3\right\)) पर (2\left\(3\right\)+5\left\(3\right\)=21) और (3+3=6)। यही दोनों रेखाओं का सामान्य बिंदु है।
B. बिंदु (\left\(3,6\right\))/Point (\left\(3,6\right\))
Step 1
Concept
Subtracting the equations gives (3x=9), so (x=3) and (y=6). This is the meeting point on the graph.
Step 2
Why this answer is correct
The correct answer is B. बिंदु (\left\(3,6\right\)) / Point (\left\(3,6\right\)). Subtracting the equations gives (3x=9), so (x=3) and (y=6). This is the meeting point on the graph.
Step 3
Exam Tip
दोनों समीकरण घटाने पर (3x=9), इसलिए (x=3) और (y=6)। ग्राफ पर यही मिलन बिंदु है।
A. बिंदु (\left\(\frac{22}{5},\frac{13}{5}\right\))/Point (\left\(\frac{22}{5},\frac{13}{5}\right\))
Step 1
Concept
Using (y=7-x) from (x+y=7), we get (2x-3\left\(7-x\right\)=1). Thus \(x=\frac{22}{5}\) and \(y=\frac{13}{5}\).
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(\frac{22}{5},\frac{13}{5}\right\)) / Point (\left\(\frac{22}{5},\frac{13}{5}\right\)). Using (y=7-x) from (x+y=7), we get (2x-3\left\(7-x\right\)=1). Thus \(x=\frac{22}{5}\) and \(y=\frac{13}{5}\).
Step 3
Exam Tip
(x+y=7) से (y=7-x) रखकर (2x-3\left\(7-x\right\)=1) मिलता है। इससे \(x=\frac{22}{5}\) और \(y=\frac{13}{5}\) है।
A. बिंदु (\left\(4,2\right\))/Point (\left\(4,2\right\))
Step 1
Concept
At (\left\(4,2\right\)), (3\left\(4\right\)+2\left\(2\right\)=16) and (4+2=6). If both are true, the point is the intersection.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(4,2\right\)) / Point (\left\(4,2\right\)). At (\left\(4,2\right\)), (3\left\(4\right\)+2\left\(2\right\)=16) and (4+2=6). If both are true, the point is the intersection.
Step 3
Exam Tip
(\left\(4,2\right\)) पर (3\left\(4\right\)+2\left\(2\right\)=16) और (4+2=6)। दोनों सत्य हों तो बिंदु प्रतिच्छेद है।
A. बिंदु (\left\(\frac{24}{7},\frac{27}{7}\right\))/Point (\left\(\frac{24}{7},\frac{27}{7}\right\))
Step 1
Concept
From (2x-y=3), (y=2x-3), and substituting in the first equation gives \(x=\frac{24}{7}\). Then \(y=\frac{27}{7}\).
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(\frac{24}{7},\frac{27}{7}\right\)) / Point (\left\(\frac{24}{7},\frac{27}{7}\right\)). From (2x-y=3), (y=2x-3), and substituting in the first equation gives \(x=\frac{24}{7}\). Then \(y=\frac{27}{7}\).
Step 3
Exam Tip
(2x-y=3) से (y=2x-3) और पहले समीकरण में रखने पर \(x=\frac{24}{7}\) मिलता है। फिर \(y=\frac{27}{7}\) है।
A. बिंदु (\left\(5,3\right\))/Point (\left\(5,3\right\))
Step 1
Concept
Substituting (\left\(5,3\right\)) makes both equations true. In graphical method this common point is the solution.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(5,3\right\)) / Point (\left\(5,3\right\)). Substituting (\left\(5,3\right\)) makes both equations true. In graphical method this common point is the solution.
Step 3
Exam Tip
(\left\(5,3\right\)) रखने पर दोनों समीकरण सत्य होते हैं। ग्राफीय विधि में यही सामान्य बिंदु हल होता है।
Subtracting the equations gives (2x=8), so (x=4) and (y=8). In real life, the meeting point is the intersection point.
Step 2
Why this answer is correct
The correct answer is A. ( (4,8) ). Subtracting the equations gives (2x=8), so (x=4) and (y=8). In real life, the meeting point is the intersection point.
Step 3
Exam Tip
दोनों समीकरण घटाने पर (2x=8), इसलिए (x=4) और (y=8)। वास्तविक जीवन में मिलन बिंदु ही प्रतिच्छेद बिंदु होता है।
Subtracting the first equation from the second gives (x=3), then (3+5y=13) gives (y=2). This is the graphical solution.
Step 2
Why this answer is correct
The correct answer is A. ( (3,2) ). Subtracting the first equation from the second gives (x=3), then (3+5y=13) gives (y=2). This is the graphical solution.
Step 3
Exam Tip
दूसरे समीकरण से पहले को घटाने पर (x=3), फिर (3+5y=13) से (y=2)। यही ग्राफीय हल है।
Subtracting the equations gives (x=5), then (5+y=9) gives (y=4). In real life, the meeting point is the intersection.
Step 2
Why this answer is correct
The correct answer is B. ( (5,4) ). Subtracting the equations gives (x=5), then (5+y=9) gives (y=4). In real life, the meeting point is the intersection.
Step 3
Exam Tip
दोनों समीकरण घटाने पर (x=5), फिर (5+y=9) से (y=4)। वास्तविक जीवन में मिलन बिंदु ही प्रतिच्छेद है।
Adding the equations gives (2x=16), so (x=8) and (y=4). In a real problem, the meeting point is the graphical solution.
Step 2
Why this answer is correct
The correct answer is B. ( (8,4) ). Adding the equations gives (2x=16), so (x=8) and (y=4). In a real problem, the meeting point is the graphical solution.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (2x=16), इसलिए (x=8) और (y=4)। वास्तविक समस्या में मिलन बिंदु ही ग्राफीय हल है।
Substituting ( (3,5) ) gives (2(3)-5=1) and (3+5=8). If both equations are true, that point is the graphical solution.
Step 2
Why this answer is correct
The correct answer is B. ( (3,5) ). Substituting ( (3,5) ) gives (2(3)-5=1) and (3+5=8). If both equations are true, that point is the graphical solution.
Step 3
Exam Tip
( (3,5) ) रखने पर (2(3)-5=1) और (3+5=8)। दोनों समीकरण सत्य हों तो वही ग्राफीय हल है।
Substituting ( (4,2) ) makes both equations true. In graphical method, the common point of both lines is the solution.
Step 2
Why this answer is correct
The correct answer is A. ( (4,2) ). Substituting ( (4,2) ) makes both equations true. In graphical method, the common point of both lines is the solution.
Step 3
Exam Tip
( (4,2) ) रखने पर दोनों समीकरण सत्य होते हैं। ग्राफीय विधि में दोनों रेखाओं का सामान्य बिंदु ही हल होता है।
Adding both equations gives (2x=12), so (x=6) and (y=4). In a real situation, the meeting point is the graphical solution.
Step 2
Why this answer is correct
The correct answer is B. ( (6,4) ). Adding both equations gives (2x=12), so (x=6) and (y=4). In a real situation, the meeting point is the graphical solution.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (2x=12), इसलिए (x=6) और (y=4)। वास्तविक स्थिति में मिलन बिंदु ही ग्राफीय हल है।
