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class 11 MCQ Questions for Class 11

class 11 se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

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2918 questions tagged with class 11.

Question 1741/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

यदि सीमा रेखा (x-y=0) है और शेडिंग उस ओर है जहां (y) का मान (x) से बड़ा है तो असमानता कौन-सी होगी?

If the boundary line is (x-y=0) and shading is on the side where (y) is greater than (x), which inequality is represented?

Explanation opens after your attempt
Correct Answer

D. \(y\ge x\)

Step 1

Concept

Where (y) is greater than or equal to (x), the inequality is \(y\ge x\). If the boundary (y=x) is included, equality is also used.

Step 2

Why this answer is correct

The correct answer is D. \(y\ge x\). Where (y) is greater than or equal to (x), the inequality is \(y\ge x\). If the boundary (y=x) is included, equality is also used.

Step 3

Exam Tip

जहां (y) का मान (x) से बड़ा या बराबर है वहां \(y\ge x\) होगा। सीमा रेखा (y=x) शामिल होने पर बराबरी भी आती है।

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Question 1742/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

असमानता \(x+5y\ge 15\) में कौन-सा बिंदु हल क्षेत्र में है?

Which point lies in the solution region of \(x+5y\ge 15\)?

Explanation opens after your attempt
Correct Answer

A. ((5,2))

Step 1

Concept

Substituting ((5,2)) gives (5+10=15), and equality is included in \(\ge\). Therefore it lies in the solution region.

Step 2

Why this answer is correct

The correct answer is A. ((5,2)). Substituting ((5,2)) gives (5+10=15), and equality is included in \(\ge\). Therefore it lies in the solution region.

Step 3

Exam Tip

((5,2)) रखने पर (5+10=15) मिलता है और \(\ge\) में बराबरी शामिल है। इसलिए यह हल क्षेत्र में है।

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Question 1743/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

असमानताओं \(x\ge 0\), \(y\ge 0\), \(x+3y\le 9\) से बने त्रिभुज का (x)-अवरोध कौन-सा है?

What is the (x)-intercept of the triangle formed by \(x\ge 0\), \(y\ge 0\), and \(x+3y\le 9\)?

Explanation opens after your attempt
Correct Answer

C. ((9,0))

Step 1

Concept

Putting (y=0) gives (x=9). Hence the vertex on the (x)-axis is ((9,0)).

Step 2

Why this answer is correct

The correct answer is C. ((9,0)). Putting (y=0) gives (x=9). Hence the vertex on the (x)-axis is ((9,0)).

Step 3

Exam Tip

(y=0) रखने पर (x=9) मिलता है। इसलिए (x)-अक्ष पर शीर्ष ((9,0)) है।

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Question 1744/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

सीमा रेखा (x+2y=4) पर कौन-सा बिंदु नहीं है?

Which point is not on the boundary line (x+2y=4)?

Explanation opens after your attempt
Correct Answer

B. ((1,2))

Step 1

Concept

Substituting ((1,2)) gives (1+4=5). Therefore it is not on the boundary line.

Step 2

Why this answer is correct

The correct answer is B. ((1,2)). Substituting ((1,2)) gives (1+4=5). Therefore it is not on the boundary line.

Step 3

Exam Tip

((1,2)) रखने पर (1+4=5) मिलता है। इसलिए यह सीमा रेखा पर नहीं है।

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Question 1745/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

असमानता \(-2x-y\le -6\) को सरल करने पर सही रूप कौन-सा है?

Which form is correct after simplifying \(-2x-y\le -6\)?

Explanation opens after your attempt
Correct Answer

D. \(2x+y\ge 6\)

Step 1

Concept

Multiplying the whole inequality by (-1) reverses the sign. Hence \(2x+y\ge 6\) is obtained.

Step 2

Why this answer is correct

The correct answer is D. \(2x+y\ge 6\). Multiplying the whole inequality by (-1) reverses the sign. Hence \(2x+y\ge 6\) is obtained.

Step 3

Exam Tip

पूरी असमानता को (-1) से गुणा करने पर चिन्ह पलटता है। इसलिए \(2x+y\ge 6\) मिलता है।

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Question 1746/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

असमानता \(3x+3y\ge 21\) को सरल करने पर कौन-सी असमानता मिलेगी?

Which inequality is obtained by simplifying \(3x+3y\ge 21\)?

Explanation opens after your attempt
Correct Answer

A. \(x+y\ge 7\)

Step 1

Concept

Dividing the whole inequality by (3) gives \(x+y\ge 7\). Dividing by a positive number does not change the sign.

Step 2

Why this answer is correct

The correct answer is A. \(x+y\ge 7\). Dividing the whole inequality by (3) gives \(x+y\ge 7\). Dividing by a positive number does not change the sign.

Step 3

Exam Tip

पूरी असमानता को (3) से भाग देने पर \(x+y\ge 7\) मिलता है। धनात्मक संख्या से भाग देने पर चिन्ह नहीं बदलता।

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Question 1747/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

असमानताओं (x+y<4) और (x+y>4) का संयुक्त हल क्या होगा?

What is the common solution of (x+y<4) and (x+y>4)?

Explanation opens after your attempt
Correct Answer

C. रिक्त समुच्चयempty set

Step 1

Concept

For the same point, (x+y) cannot be both less than (4) and greater than (4). Hence the common solution is empty.

Step 2

Why this answer is correct

The correct answer is C. रिक्त समुच्चय / empty set. For the same point, (x+y) cannot be both less than (4) and greater than (4). Hence the common solution is empty.

Step 3

Exam Tip

एक ही बिंदु के लिए (x+y) एक साथ (4) से कम और (4) से अधिक नहीं हो सकता। इसलिए संयुक्त हल रिक्त है।

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Question 1748/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

रेखाओं (2x+y=7) और (x-y=2) का प्रतिच्छेद बिंदु क्या है?

What is the intersection point of (2x+y=7) and (x-y=2)?

Explanation opens after your attempt
Correct Answer

D. ((3,1))

Step 1

Concept

Using (y=x-2) from (x-y=2), we get (2x+x-2=7). Hence (x=3) and (y=1).

Step 2

Why this answer is correct

The correct answer is D. ((3,1)). Using (y=x-2) from (x-y=2), we get (2x+x-2=7). Hence (x=3) and (y=1).

Step 3

Exam Tip

(x-y=2) से (y=x-2) रखकर (2x+x-2=7) मिलता है। इसलिए (x=3) और (y=1) हैं।

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Question 1749/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

असमानता \(2x-y\le 5\) के लिए कौन-सा बिंदु मूल बिंदु वाली ओर के बारे में सही परीक्षण देता है?

For \(2x-y\le 5\), which test correctly describes the side containing the origin?

Explanation opens after your attempt
Correct Answer

B. मूल बिंदु हल में है क्योंकि \(0\le 5\) सत्य हैorigin is in solution because \(0\le 5\) is true

Step 1

Concept

Substituting ((0,0)) gives \(0\le 5\), which is true. Therefore shade the side containing the origin.

Step 2

Why this answer is correct

The correct answer is B. मूल बिंदु हल में है क्योंकि \(0\le 5\) सत्य है / origin is in solution because \(0\le 5\) is true. Substituting ((0,0)) gives \(0\le 5\), which is true. Therefore shade the side containing the origin.

Step 3

Exam Tip

((0,0)) रखने पर \(0\le 5\) सत्य है। इसलिए मूल बिंदु वाली ओर शेड होगी।

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Question 1750/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

असमानताओं \(x\ge 1\), \(x\le 5\), \(y\ge 0\), \(y\le 4\) से बने क्षेत्र का आकार क्या है?

What is the shape of the region formed by \(x\ge 1\), \(x\le 5\), \(y\ge 0\), and \(y\le 4\)?

Explanation opens after your attempt
Correct Answer

C. आयतrectangle

Step 1

Concept

(x) lies between two vertical boundaries and (y) lies between two horizontal boundaries. Hence a closed rectangle is formed.

Step 2

Why this answer is correct

The correct answer is C. आयत / rectangle. (x) lies between two vertical boundaries and (y) lies between two horizontal boundaries. Hence a closed rectangle is formed.

Step 3

Exam Tip

(x) दो ऊर्ध्वाधर सीमाओं और (y) दो क्षैतिज सीमाओं के बीच है। इसलिए बंद आयत बनता है।

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Question 1751/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

असमानता (x< -2) का आलेख किस क्षेत्र को दर्शाता है?

Which region is represented by (x< -2)?

Explanation opens after your attempt
Correct Answer

A. रेखा (x=-2) के बाईं ओर और रेखा शामिल नहींleft of (x=-2) excluding the line

Step 1

Concept

In (x< -2), (x) is less than (-2). Hence shade the left side and draw a dashed boundary.

Step 2

Why this answer is correct

The correct answer is A. रेखा (x=-2) के बाईं ओर और रेखा शामिल नहीं / left of (x=-2) excluding the line. In (x< -2), (x) is less than (-2). Hence shade the left side and draw a dashed boundary.

Step 3

Exam Tip

(x< -2) में (x) का मान (-2) से कम है। इसलिए बाईं ओर शेड होगा और सीमा रेखा टूटी होगी।

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Question 1752/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

असमानता (y>-4) के आलेख में कौन-सा बिंदु हल क्षेत्र में है?

Which point lies in the solution region of (y>-4)?

Explanation opens after your attempt
Correct Answer

D. ((3,-3))

Step 1

Concept

For ((3,-3)), (y=-3), and (-3>-4) is true. In a strict inequality, boundary points are not included.

Step 2

Why this answer is correct

The correct answer is D. ((3,-3)). For ((3,-3)), (y=-3), and (-3>-4) is true. In a strict inequality, boundary points are not included.

Step 3

Exam Tip

((3,-3)) में (y=-3) है और (-3>-4) सत्य है। सख्त असमानता में सीमा रेखा के बिंदु शामिल नहीं होते।

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Question 1753/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

रेखा (6x+3y=18) का सरल सीमा रेखा रूप क्या है?

What is the simplified boundary-line form of (6x+3y=18)?

Explanation opens after your attempt
Correct Answer

B. (2x+y=6)

Step 1

Concept

Dividing the whole equation by (3) gives (2x+y=6). Simplify the equation before drawing the graph.

Step 2

Why this answer is correct

The correct answer is B. (2x+y=6). Dividing the whole equation by (3) gives (2x+y=6). Simplify the equation before drawing the graph.

Step 3

Exam Tip

पूरे समीकरण को (3) से भाग देने पर (2x+y=6) मिलता है। ग्राफ बनाने से पहले समीकरण सरल कर लेना चाहिए।

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Question 1754/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

असमानताओं \(x\ge 0\), \(y\ge 0\), \(x+y\le 8\), \(y\le 2\) से बने क्षेत्र में कौन-सा बिंदु नहीं है?

Which point is not in the region formed by \(x\ge 0\), \(y\ge 0\), \(x+y\le 8\), and \(y\le 2\)?

Explanation opens after your attempt
Correct Answer

C. ((3,3))

Step 1

Concept

For ((3,3)), the condition \(y\le 2\) is false. To lie in the common solution, all conditions must be true.

Step 2

Why this answer is correct

The correct answer is C. ((3,3)). For ((3,3)), the condition \(y\le 2\) is false. To lie in the common solution, all conditions must be true.

Step 3

Exam Tip

((3,3)) में \(y\le 2\) असत्य है। संयुक्त हल में आने के लिए सभी शर्तें सत्य होनी चाहिए।

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Question 1755/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

असमानता \(y\le 2x-1\) में बिंदु ((2,3)) की स्थिति क्या है?

What is the position of ((2,3)) with respect to \(y\le 2x-1\)?

Explanation opens after your attempt
Correct Answer

C. सीमा रेखा पर और हल मेंon boundary and in solution

Step 1

Concept

Substituting ((2,3)) gives \(3=2\times 2-1\). Equality places the point on the boundary and it is included because of \(\le\).

Step 2

Why this answer is correct

The correct answer is C. सीमा रेखा पर और हल में / on boundary and in solution. Substituting ((2,3)) gives \(3=2\times 2-1\). Equality places the point on the boundary and it is included because of \(\le\).

Step 3

Exam Tip

((2,3)) रखने पर \(3=2\times 2-1\) मिलता है। बराबरी होने से बिंदु सीमा पर है और \(\le\) के कारण हल में है।

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Question 1756/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

यदि किसी हल क्षेत्र में \(x\ge 0\), \(y\ge 0\), और \(x+y\le 0\) हैं तो हल क्षेत्र क्या होगा?

If a solution region has \(x\ge 0\), \(y\ge 0\), and \(x+y\le 0\), what is the solution region?

Explanation opens after your attempt
Correct Answer

B. केवल ((0,0))only ((0,0))

Step 1

Concept

In the first quadrant, both (x) and (y) are non-negative. The condition \(x+y\le 0\) is possible only when both are (0).

Step 2

Why this answer is correct

The correct answer is B. केवल ((0,0)) / only ((0,0)). In the first quadrant, both (x) and (y) are non-negative. The condition \(x+y\le 0\) is possible only when both are (0).

Step 3

Exam Tip

प्रथम चतुर्थांश में (x) और (y) दोनों गैर-ऋणात्मक हैं। \(x+y\le 0\) तभी संभव है जब दोनों (0) हों।

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Question 1757/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

असमानताओं \(x+2y\le 10\) और \(x+2y\ge 4\) का संयुक्त क्षेत्र क्या है?

What is the common region of \(x+2y\le 10\) and \(x+2y\ge 4\)?

Explanation opens after your attempt
Correct Answer

D. दो समानांतर रेखाओं के बीच की पट्टीstrip between two parallel lines

Step 1

Concept

The boundary lines (x+2y=10) and (x+2y=4) are parallel. The closed region between them is the common solution.

Step 2

Why this answer is correct

The correct answer is D. दो समानांतर रेखाओं के बीच की पट्टी / strip between two parallel lines. The boundary lines (x+2y=10) and (x+2y=4) are parallel. The closed region between them is the common solution.

Step 3

Exam Tip

सीमा रेखाएं (x+2y=10) और (x+2y=4) समानांतर हैं। इनके बीच का बंद क्षेत्र संयुक्त हल है।

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Question 1758/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

असमानता \(3x+y\le 9\) के आलेख में ((4,0)) किस स्थिति में है?

What is the position of ((4,0)) in the graph of \(3x+y\le 9\)?

Explanation opens after your attempt
Correct Answer

A. हल क्षेत्र के अंदरinside solution region

Step 1

Concept

Substituting ((4,0)) gives \(12\le 9\), which is false. Therefore it lies outside the solution region.

Step 2

Why this answer is correct

The correct answer is A. हल क्षेत्र के अंदर / inside solution region. Substituting ((4,0)) gives \(12\le 9\), which is false. Therefore it lies outside the solution region.

Step 3

Exam Tip

((4,0)) रखने पर \(12\le 9\) असत्य है। इसलिए यह हल क्षेत्र के बाहर है।

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Question 1759/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

असमानता \(y\ge -x+6\) की सीमा रेखा पर (x=2) होने पर (y) का मान क्या होगा?

On the boundary line of \(y\ge -x+6\), what is the value of (y) when (x=2)?

Explanation opens after your attempt
Correct Answer

C. (4)

Step 1

Concept

The boundary line is (y=-x+6). Substituting (x=2) gives (y=4).

Step 2

Why this answer is correct

The correct answer is C. (4). The boundary line is (y=-x+6). Substituting (x=2) gives (y=4).

Step 3

Exam Tip

सीमा रेखा (y=-x+6) है। (x=2) रखने पर (y=4) मिलता है।

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Question 1760/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

रेखा (x-y=4) को (y) के रूप में लिखने पर सीमा रेखा कौन-सी होगी?

What is the boundary line in terms of (y) for (x-y=4)?

Explanation opens after your attempt
Correct Answer

D. (y=x-4)

Step 1

Concept

From (x-y=4), (-y=4-x), so (y=x-4). This is the slope-intercept form of the boundary line.

Step 2

Why this answer is correct

The correct answer is D. (y=x-4). From (x-y=4), (-y=4-x), so (y=x-4). This is the slope-intercept form of the boundary line.

Step 3

Exam Tip

(x-y=4) से (-y=4-x) और (y=x-4) मिलता है। यह ढाल-अवरोध रूप में सीमा रेखा है।

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Question 1761/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

असमानताओं (1<x<5) और \(y\ge 0\) से बने क्षेत्र की (x=1) सीमा कैसी होगी?

For the region (1<x<5) and \(y\ge 0\), what type of boundary is (x=1)?

Explanation opens after your attempt
Correct Answer

B. टूटी रेखाdashed line

Step 1

Concept

Equality is not included in (1<x). Therefore the boundary (x=1) is shown by a dashed line.

Step 2

Why this answer is correct

The correct answer is B. टूटी रेखा / dashed line. Equality is not included in (1<x). Therefore the boundary (x=1) is shown by a dashed line.

Step 3

Exam Tip

(1<x) में बराबरी शामिल नहीं है। इसलिए (x=1) की सीमा टूटी रेखा से दिखाई जाएगी।

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Question 1762/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

असमानताओं \(2\le y\le 6\) का आलेख किस प्रकार का क्षेत्र है?

What type of region is represented by \(2\le y\le 6\)?

Explanation opens after your attempt
Correct Answer

C. दो क्षैतिज रेखाओं के बीच पट्टीstrip between two horizontal lines

Step 1

Concept

The lines (y=2) and (y=6) are horizontal. The closed region between them is the common solution.

Step 2

Why this answer is correct

The correct answer is C. दो क्षैतिज रेखाओं के बीच पट्टी / strip between two horizontal lines. The lines (y=2) and (y=6) are horizontal. The closed region between them is the common solution.

Step 3

Exam Tip

(y=2) और (y=6) क्षैतिज रेखाएं हैं। इनके बीच का बंद क्षेत्र संयुक्त हल है।

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Question 1763/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

असमानताओं \(x\le 1\) और \(x\ge 4\) का संयुक्त हल क्या है?

What is the common solution of \(x\le 1\) and \(x\ge 4\)?

Explanation opens after your attempt
Correct Answer

A. रिक्त समुच्चयempty set

Step 1

Concept

No (x) can be both less than or equal to (1) and greater than or equal to (4). Therefore there is no common solution.

Step 2

Why this answer is correct

The correct answer is A. रिक्त समुच्चय / empty set. No (x) can be both less than or equal to (1) and greater than or equal to (4). Therefore there is no common solution.

Step 3

Exam Tip

कोई (x) एक साथ (1) से छोटा या बराबर और (4) से बड़ा या बराबर नहीं हो सकता। इसलिए कोई संयुक्त हल नहीं है।

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Question 1764/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

असमानताओं \(x\ge 0\), \(y\ge 0\), \(x+2y\le 8\), \(x\le 6\) से बने क्षेत्र का कौन-सा शीर्ष संभव है?

Which vertex is possible for the region formed by \(x\ge 0\), \(y\ge 0\), \(x+2y\le 8\), and \(x\le 6\)?

Explanation opens after your attempt
Correct Answer

D. ((6,0))

Step 1

Concept

The intersection of (x=6) and (y=0) is ((6,0)), and it satisfies \(x+2y\le 8\). Hence it is a vertex of the region.

Step 2

Why this answer is correct

The correct answer is D. ((6,0)). The intersection of (x=6) and (y=0) is ((6,0)), and it satisfies \(x+2y\le 8\). Hence it is a vertex of the region.

Step 3

Exam Tip

(x=6) और (y=0) मिलने पर ((6,0)) आता है और यह \(x+2y\le 8\) को संतुष्ट करता है। इसलिए यह क्षेत्र का शीर्ष है।

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Question 1765/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

असमानता \(2x+y\ge 6\) में बिंदु ((1,4)) की स्थिति क्या है?

What is the position of ((1,4)) with respect to \(2x+y\ge 6\)?

Explanation opens after your attempt
Correct Answer

A. हल क्षेत्र में और सीमा परin solution region and on boundary

Step 1

Concept

Substituting ((1,4)) gives (2+4=6). Equality puts the point on the boundary and it is included because of \(\ge\).

Step 2

Why this answer is correct

The correct answer is A. हल क्षेत्र में और सीमा पर / in solution region and on boundary. Substituting ((1,4)) gives (2+4=6). Equality puts the point on the boundary and it is included because of \(\ge\).

Step 3

Exam Tip

((1,4)) रखने पर (2+4=6) मिलता है। बराबरी होने से बिंदु सीमा पर है और \(\ge\) के कारण शामिल है।

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Question 1766/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

असमानताओं \(y\ge x+1\) और \(y\le 5\) के संयुक्त क्षेत्र में कौन-सा बिंदु आता है?

Which point lies in the common region of \(y\ge x+1\) and \(y\le 5\)?

Explanation opens after your attempt
Correct Answer

C. ((2,4))

Step 1

Concept

At ((2,4)), both \(4\ge 3\) and \(4\le 5\) are true. For a common region, check all inequalities.

Step 2

Why this answer is correct

The correct answer is C. ((2,4)). At ((2,4)), both \(4\ge 3\) and \(4\le 5\) are true. For a common region, check all inequalities.

Step 3

Exam Tip

((2,4)) पर \(4\ge 3\) और \(4\le 5\) दोनों सत्य हैं। संयुक्त क्षेत्र के लिए सभी असमानताएं जांचें।

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Question 1767/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

रेखा (2x+5y=20) और (y=2) का प्रतिच्छेद बिंदु कौन-सा है?

Which is the intersection point of (2x+5y=20) and (y=2)?

Explanation opens after your attempt
Correct Answer

B. ((5,2))

Step 1

Concept

Putting (y=2) gives (2x+10=20), so (x=5). Hence the intersection is ((5,2)).

Step 2

Why this answer is correct

The correct answer is B. ((5,2)). Putting (y=2) gives (2x+10=20), so (x=5). Hence the intersection is ((5,2)).

Step 3

Exam Tip

(y=2) रखने पर (2x+10=20) इसलिए (x=5)। इसलिए प्रतिच्छेद ((5,2)) है।

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Question 1768/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

रेखा (3x+2y=18) और (x=4) का प्रतिच्छेद बिंदु क्या है?

What is the intersection point of (3x+2y=18) and (x=4)?

Explanation opens after your attempt
Correct Answer

D. ((4,3))

Step 1

Concept

Putting (x=4) gives (12+2y=18), so (y=3). The intersection is ((4,3)).

Step 2

Why this answer is correct

The correct answer is D. ((4,3)). Putting (x=4) gives (12+2y=18), so (y=3). The intersection is ((4,3)).

Step 3

Exam Tip

(x=4) रखने पर (12+2y=18) इसलिए (y=3)। प्रतिच्छेद ((4,3)) है।

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Question 1769/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

असमानताओं \(x+y\le 10\), \(x\ge 2\), \(y\ge 3\) से बने क्षेत्र का कौन-सा बिंदु शीर्ष है?

Which point is a vertex of the region formed by \(x+y\le 10\), \(x\ge 2\), and \(y\ge 3\)?

Explanation opens after your attempt
Correct Answer

C. ((2,3))

Step 1

Concept

The intersection of (x=2) and (y=3) is ((2,3)), and it satisfies \(x+y\le 10\). Therefore it is a vertex.

Step 2

Why this answer is correct

The correct answer is C. ((2,3)). The intersection of (x=2) and (y=3) is ((2,3)), and it satisfies \(x+y\le 10\). Therefore it is a vertex.

Step 3

Exam Tip

(x=2) और (y=3) का प्रतिच्छेद ((2,3)) है और यह \(x+y\le 10\) को संतुष्ट करता है। इसलिए यह एक शीर्ष है।

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Question 1770/2918 Medium Mathematics Linear Inequalities Graphical solution of linear inequalities in two variables Class 11 Level 50

असमानता \(4x+2y\le 16\) को सरल करने पर कौन-सी सीमा रेखा मिलेगी?

Which boundary line is obtained after simplifying \(4x+2y\le 16\)?

Explanation opens after your attempt
Correct Answer

A. (2x+y=8)

Step 1

Concept

Dividing the inequality by (2) gives \(2x+y\le 8\). Its boundary line is (2x+y=8).

Step 2

Why this answer is correct

The correct answer is A. (2x+y=8). Dividing the inequality by (2) gives \(2x+y\le 8\). Its boundary line is (2x+y=8).

Step 3

Exam Tip

असमानता को (2) से भाग देने पर \(2x+y\le 8\) मिलता है। इसकी सीमा रेखा (2x+y=8) होगी।

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