असमानताओं \(x+y\le 10\), \(x\ge 2\), \(y\ge 3\) से बने क्षेत्र का कौन-सा बिंदु शीर्ष है?
Which point is a vertex of the region formed by \(x+y\le 10\), \(x\ge 2\), and \(y\ge 3\)?
Explanation opens after your attempt
Correct Answer
C. ((2,3))
Concept
The intersection of (x=2) and (y=3) is ((2,3)), and it satisfies \(x+y\le 10\). Therefore it is a vertex.
Why this answer is correct
The correct answer is C. ((2,3)). The intersection of (x=2) and (y=3) is ((2,3)), and it satisfies \(x+y\le 10\). Therefore it is a vertex.
Exam Tip
(x=2) और (y=3) का प्रतिच्छेद ((2,3)) है और यह \(x+y\le 10\) को संतुष्ट करता है। इसलिए यह एक शीर्ष है।
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