असमानताओं \(x+2y\le 10\) और \(x+2y\ge 4\) का संयुक्त क्षेत्र क्या है?

What is the common region of \(x+2y\le 10\) and \(x+2y\ge 4\)?

Explanation opens after your attempt
Correct Answer

D. दो समानांतर रेखाओं के बीच की पट्टीstrip between two parallel lines

Step 1

Concept

The boundary lines (x+2y=10) and (x+2y=4) are parallel. The closed region between them is the common solution.

Step 2

Why this answer is correct

The correct answer is D. दो समानांतर रेखाओं के बीच की पट्टी / strip between two parallel lines. The boundary lines (x+2y=10) and (x+2y=4) are parallel. The closed region between them is the common solution.

Step 3

Exam Tip

सीमा रेखाएं (x+2y=10) और (x+2y=4) समानांतर हैं। इनके बीच का बंद क्षेत्र संयुक्त हल है।

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Mathematics Answer, Explanation and Revision Hints

असमानताओं \(x+2y\le 10\) और \(x+2y\ge 4\) का संयुक्त क्षेत्र क्या है? / What is the common region of \(x+2y\le 10\) and \(x+2y\ge 4\)?

Correct Answer: D. दो समानांतर रेखाओं के बीच की पट्टी / strip between two parallel lines. Explanation: सीमा रेखाएं (x+2y=10) और (x+2y=4) समानांतर हैं। इनके बीच का बंद क्षेत्र संयुक्त हल है। / The boundary lines (x+2y=10) and (x+2y=4) are parallel. The closed region between them is the common solution.

Which concept should I revise for this Mathematics MCQ?

The boundary lines (x+2y=10) and (x+2y=4) are parallel. The closed region between them is the common solution.

What exam hint can help solve this Mathematics question?

सीमा रेखाएं (x+2y=10) और (x+2y=4) समानांतर हैं। इनके बीच का बंद क्षेत्र संयुक्त हल है।