असमानताओं \(x\ge 0\), \(y\ge 0\), \(x+2y\le 8\), \(x\le 6\) से बने क्षेत्र का कौन-सा शीर्ष संभव है?
Which vertex is possible for the region formed by \(x\ge 0\), \(y\ge 0\), \(x+2y\le 8\), and \(x\le 6\)?
Explanation opens after your attempt
Correct Answer
D. ((6,0))
Concept
The intersection of (x=6) and (y=0) is ((6,0)), and it satisfies \(x+2y\le 8\). Hence it is a vertex of the region.
Why this answer is correct
The correct answer is D. ((6,0)). The intersection of (x=6) and (y=0) is ((6,0)), and it satisfies \(x+2y\le 8\). Hence it is a vertex of the region.
Exam Tip
(x=6) और (y=0) मिलने पर ((6,0)) आता है और यह \(x+2y\le 8\) को संतुष्ट करता है। इसलिए यह क्षेत्र का शीर्ष है।
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