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Class 9 Mathematics - Sequences and Progressions - Arithmetic Progression Hard Quiz

Topic Quiz • 150 questions • 30 seconds per question.

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समांतर श्रेणी \(11,18,25,32,\ldots\) का बारहवाँ पद क्या है?

What is the twelfth term of the arithmetic progression \(11,18,25,32,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (88)

Step 1

Concept

Here (a=11) and (d=7), so \(a_{12}=11+11\times7=88\). In exams, use (a_n=a+(n-1)d).

Step 2

Why this answer is correct

The correct answer is C. (88). Here (a=11) and (d=7), so \(a_{12}=11+11\times7=88\). In exams, use (a_n=a+(n-1)d).

Step 3

Exam Tip

यहाँ (a=11) और (d=7) है, इसलिए \(a_{12}=11+11\times7=88\) है। परीक्षा में (a_n=a+(n-1)d) का प्रयोग करें।

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यदि किसी समांतर श्रेणी में (a=5) और (d=9) है, तो \(a_{10}\) का मान क्या होगा?

If an arithmetic progression has (a=5) and (d=9), what is the value of \(a_{10}\)?

Explanation opens after your attempt
Correct Answer

B. (86)

Step 1

Concept

\(a_{10}=5+9\times9=86\). In exams, add the difference (9) times for the tenth term.

Step 2

Why this answer is correct

The correct answer is B. (86). \(a_{10}=5+9\times9=86\). In exams, add the difference (9) times for the tenth term.

Step 3

Exam Tip

\(a_{10}=5+9\times9=86\) है। परीक्षा में दसवें पद के लिए (9) बार अंतर जोड़ें।

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समांतर श्रेणी \(42,36,30,24,\ldots\) का आठवाँ पद क्या है?

What is the eighth term of the arithmetic progression \(42,36,30,24,\ldots\)?

Explanation opens after your attempt
Correct Answer

D. (0)

Step 1

Concept

Here (d=-6), so (a_8=42+7(-6)=0). In exams, keep (d) negative in a decreasing progression.

Step 2

Why this answer is correct

The correct answer is D. (0). Here (d=-6), so (a_8=42+7(-6)=0). In exams, keep (d) negative in a decreasing progression.

Step 3

Exam Tip

यहाँ (d=-6) है, इसलिए (a_8=42+7(-6)=0) है। परीक्षा में घटती श्रेणी में (d) को ऋणात्मक रखें।

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यदि \(a_n=4n+3\) है, तो (91) कौन-सा पद होगा?

If \(a_n=4n+3\), which term will be (91)?

Explanation opens after your attempt
Correct Answer

C. बाईसवाँ पद(22)nd term

Step 1

Concept

From (4n+3=91), we get (n=22). In exams, equate the given term to the general term.

Step 2

Why this answer is correct

The correct answer is C. बाईसवाँ पद / (22)nd term. From (4n+3=91), we get (n=22). In exams, equate the given term to the general term.

Step 3

Exam Tip

(4n+3=91) से (n=22) मिलता है। परीक्षा में दिए पद को सामान्य पद के बराबर रखें।

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किस समांतर श्रेणी में पहला पद (14) और पंद्रहवाँ पद (84) है, उसका सार्व अंतर क्या है?

In an arithmetic progression whose first term is (14) and fifteenth term is (84), what is the common difference?

Explanation opens after your attempt
Correct Answer

A. (5)

Step 1

Concept

From (84=14+14d), (d=5). In exams, pay attention to (n-1) in the (n)th term.

Step 2

Why this answer is correct

The correct answer is A. (5). From (84=14+14d), (d=5). In exams, pay attention to (n-1) in the (n)th term.

Step 3

Exam Tip

(84=14+14d) से (d=5) है। परीक्षा में (n)वें पद में (n-1) का ध्यान रखें।

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समांतर श्रेणी \(7,12,17,22,\ldots\) का सामान्य पद क्या है?

What is the general term of the arithmetic progression \(7,12,17,22,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. \(a_n=5n+2\)

Step 1

Concept

The first term is (7) and the difference is (5), so \(a_n=5n+2\). In exams, check the first term by putting (n=1).

Step 2

Why this answer is correct

The correct answer is B. \(a_n=5n+2\). The first term is (7) and the difference is (5), so \(a_n=5n+2\). In exams, check the first term by putting (n=1).

Step 3

Exam Tip

पहला पद (7) और अंतर (5) है, इसलिए \(a_n=5n+2\) है। परीक्षा में (n=1) रखकर पहला पद जाँचें।

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समांतर श्रेणी \(2,5,8,11,\ldots\) के पहले (10) पदों का योग क्या है?

What is the sum of the first (10) terms of the arithmetic progression \(2,5,8,11,\ldots\)?

Explanation opens after your attempt
Correct Answer

D. (155)

Step 1

Concept

\(S_{10}=\frac{10}{2}[2\times2+9\times3]=155\). In exams, use the formula for \(S_n\).

Step 2

Why this answer is correct

The correct answer is D. (155). \(S_{10}=\frac{10}{2}[2\times2+9\times3]=155\). In exams, use the formula for \(S_n\).

Step 3

Exam Tip

\(S_{10}=\frac{10}{2}[2\times2+9\times3]=155\) है। परीक्षा में योग के लिए \(S_n\) का सूत्र लगाएँ।

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यदि (6,x,18) समांतर श्रेणी में हैं, तो (x) का मान क्या होगा?

If (6,x,18) are in arithmetic progression, what is the value of (x)?

Explanation opens after your attempt
Correct Answer

C. (12)

Step 1

Concept

The middle term is \(x=\frac{6+18}{2}=12\). In exams, the middle term of three AP terms is the average.

Step 2

Why this answer is correct

The correct answer is C. (12). The middle term is \(x=\frac{6+18}{2}=12\). In exams, the middle term of three AP terms is the average.

Step 3

Exam Tip

मध्य पद \(x=\frac{6+18}{2}=12\) है। परीक्षा में तीन पदों वाली समांतर श्रेणी में बीच वाला पद औसत होता है।

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समांतर श्रेणी \(3,8,13,18,\ldots\) के पहले (8) पदों का योग क्या है?

What is the sum of the first (8) terms of the arithmetic progression \(3,8,13,18,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (164)

Step 1

Concept

\(S_8=\frac{8}{2}[2\times3+7\times5]=164\). In exams, calculate inside the bracket first.

Step 2

Why this answer is correct

The correct answer is C. (164). \(S_8=\frac{8}{2}[2\times3+7\times5]=164\). In exams, calculate inside the bracket first.

Step 3

Exam Tip

\(S_8=\frac{8}{2}[2\times3+7\times5]=164\) है। परीक्षा में कोष्ठक के अंदर की गणना पहले करें।

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यदि \(a_3=17\) और (d=4) है, तो पहला पद (a) क्या होगा?

If \(a_3=17\) and (d=4), what is the first term (a)?

Explanation opens after your attempt
Correct Answer

B. (9)

Step 1

Concept

\(a_3=a+2d\), so (17=a+8) and (a=9). In exams, subtract two differences from the third term.

Step 2

Why this answer is correct

The correct answer is B. (9). \(a_3=a+2d\), so (17=a+8) and (a=9). In exams, subtract two differences from the third term.

Step 3

Exam Tip

\(a_3=a+2d\), इसलिए (17=a+8) और (a=9) है। परीक्षा में तीसरे पद से दो अंतर घटाएँ।

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समांतर श्रेणी \(25,21,17,13,\ldots\) का सामान्य पद क्या है?

What is the general term of the arithmetic progression \(25,21,17,13,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. \(a_n=29-4n\)

Step 1

Concept

The rule \(a_n=29-4n\) gives (25) at (n=1) and (21) at (n=2). In exams, match the first term in a decreasing progression.

Step 2

Why this answer is correct

The correct answer is B. \(a_n=29-4n\). The rule \(a_n=29-4n\) gives (25) at (n=1) and (21) at (n=2). In exams, match the first term in a decreasing progression.

Step 3

Exam Tip

(n=1) पर (25) और (n=2) पर (21) देने वाला नियम \(a_n=29-4n\) है। परीक्षा में घटती श्रेणी में पहला पद मिलाएँ।

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किस समांतर श्रेणी में (a=8) और \(a_6=43\) है, उसका (d) क्या है?

For an arithmetic progression with (a=8) and \(a_6=43\), what is (d)?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

From (43=8+5d), (d=7). In exams, (d) is added five times for \(a_6\).

Step 2

Why this answer is correct

The correct answer is C. (7). From (43=8+5d), (d=7). In exams, (d) is added five times for \(a_6\).

Step 3

Exam Tip

(43=8+5d) से (d=7) है। परीक्षा में \(a_6\) के लिए पाँच बार (d) जोड़ा जाता है।

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समांतर श्रेणी \(4,10,16,22,\ldots\) में (70) कौन-सा पद है?

In the arithmetic progression \(4,10,16,22,\ldots\), which term is (70)?

Explanation opens after your attempt
Correct Answer

C. बारहवाँ पद(12)th term

Step 1

Concept

From (4+(n-1)6=70), we get (n=12). In exams, form an equation to find the term number.

Step 2

Why this answer is correct

The correct answer is C. बारहवाँ पद / (12)th term. From (4+(n-1)6=70), we get (n=12). In exams, form an equation to find the term number.

Step 3

Exam Tip

(4+(n-1)6=70) से (n=12) मिलता है। परीक्षा में पद संख्या के लिए समीकरण बनाएँ।

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यदि (a=13) और (d=-3) है, तो \(a_9\) का मान क्या होगा?

If (a=13) and (d=-3), what is the value of \(a_9\)?

Explanation opens after your attempt
Correct Answer

B. (-11)

Step 1

Concept

(a_9=13+8(-3)=-11). In exams, handle signs carefully with negative (d).

Step 2

Why this answer is correct

The correct answer is B. (-11). (a_9=13+8(-3)=-11). In exams, handle signs carefully with negative (d).

Step 3

Exam Tip

(a_9=13+8(-3)=-11) है। परीक्षा में ऋणात्मक (d) के साथ चिह्न सावधानी से रखें।

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यदि समांतर श्रेणी के पहले पाँच पदों का योग (95) है और (a=7) है, तो (d) क्या है?

If the sum of the first five terms of an arithmetic progression is (95) and (a=7), what is (d)?

Explanation opens after your attempt
Correct Answer

B. (6)

Step 1

Concept

From \(\frac{5}{2}[14+4d]=95\), (d=6). In exams, keep (n-1) correct in the sum formula.

Step 2

Why this answer is correct

The correct answer is B. (6). From \(\frac{5}{2}[14+4d]=95\), (d=6). In exams, keep (n-1) correct in the sum formula.

Step 3

Exam Tip

\(\frac{5}{2}[14+4d]=95\) से (d=6) मिलता है। परीक्षा में योग सूत्र में (n-1) सही रखें।

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समांतर श्रेणी \(1,4,7,10,\ldots\) के पहले (20) पदों का योग क्या है?

What is the sum of the first (20) terms of the arithmetic progression \(1,4,7,10,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (590)

Step 1

Concept

\(S_{20}=\frac{20}{2}[2+19\times3]=590\). In exams, add (19d) for (20) terms.

Step 2

Why this answer is correct

The correct answer is C. (590). \(S_{20}=\frac{20}{2}[2+19\times3]=590\). In exams, add (19d) for (20) terms.

Step 3

Exam Tip

\(S_{20}=\frac{20}{2}[2+19\times3]=590\) है। परीक्षा में (20) पदों के लिए (19d) जोड़ें।

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समांतर श्रेणी में \(a_4=20\) और \(a_8=44\) है, तो (d) क्या है?

In an arithmetic progression, \(a_4=20\) and \(a_8=44\), what is (d)?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

\(a_8-a_4=4d=24\), so (d=6). In exams, divide the difference of terms by the difference of positions.

Step 2

Why this answer is correct

The correct answer is C. (6). \(a_8-a_4=4d=24\), so (d=6). In exams, divide the difference of terms by the difference of positions.

Step 3

Exam Tip

\(a_8-a_4=4d=24\), इसलिए (d=6) है। परीक्षा में दूर के पदों का अंतर पद-संख्या के अंतर से बाँटें।

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यदि \(a_5=27\) और (d=5) है, तो \(a_1\) का मान क्या है?

If \(a_5=27\) and (d=5), what is the value of \(a_1\)?

Explanation opens after your attempt
Correct Answer

B. (7)

Step 1

Concept

\(a_5=a+4d\), so (27=a+20) and (a=7). In exams, subtract four differences from the fifth term.

Step 2

Why this answer is correct

The correct answer is B. (7). \(a_5=a+4d\), so (27=a+20) and (a=7). In exams, subtract four differences from the fifth term.

Step 3

Exam Tip

\(a_5=a+4d\), इसलिए (27=a+20) और (a=7) है। परीक्षा में पाँचवें पद से चार अंतर घटाएँ।

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समांतर श्रेणी \(6,13,20,27,\ldots\) का \(a_{15}-a_5\) क्या होगा?

What is \(a_{15}-a_5\) for the arithmetic progression \(6,13,20,27,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (70)

Step 1

Concept

The position difference is (10) and (d=7), so the difference is \(10\times7=70\). In exams, use ((m-n)d) directly for the difference of two terms.

Step 2

Why this answer is correct

The correct answer is C. (70). The position difference is (10) and (d=7), so the difference is \(10\times7=70\). In exams, use ((m-n)d) directly for the difference of two terms.

Step 3

Exam Tip

पद-संख्या का अंतर (10) है और (d=7), इसलिए अंतर \(10\times7=70\) है। परीक्षा में दो पदों का अंतर सीधे ((m-n)d) से निकालें।

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यदि \(a_n=9n-2\) है, तो पहले (6) पदों का योग क्या होगा?

If \(a_n=9n-2\), what is the sum of the first (6) terms?

Explanation opens after your attempt
Correct Answer

B. (186)

Step 1

Concept

The first six terms are (7,16,25,34,43,52), and their sum is (186). In exams, you can verify the sum by listing terms from the rule.

Step 2

Why this answer is correct

The correct answer is B. (186). The first six terms are (7,16,25,34,43,52), and their sum is (186). In exams, you can verify the sum by listing terms from the rule.

Step 3

Exam Tip

पहले छह पद (7,16,25,34,43,52) हैं और योग (186) है। परीक्षा में नियम से पद निकालकर भी योग जाँच सकते हैं।

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समांतर श्रेणी \(17,24,31,\ldots\) का वह पद कौन-सा है जो (80) है?

Which term of the arithmetic progression \(17,24,31,\ldots\) is (80)?

Explanation opens after your attempt
Correct Answer

C. दसवाँ पद(10)th term

Step 1

Concept

From (17+(n-1)7=80), we get (n=10). In exams, equate the given term to (a+(n-1)d).

Step 2

Why this answer is correct

The correct answer is C. दसवाँ पद / (10)th term. From (17+(n-1)7=80), we get (n=10). In exams, equate the given term to (a+(n-1)d).

Step 3

Exam Tip

(17+(n-1)7=80) से (n=10) मिलता है। परीक्षा में दिए पद को (a+(n-1)d) के बराबर रखें।

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यदि \(a_2=12\) और \(a_6=32\) है, तो पहला पद क्या होगा?

If \(a_2=12\) and \(a_6=32\), what is the first term?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

From (4d=20), (d=5), and from (a+d=12), (a=7). In exams, find (d) first and then (a).

Step 2

Why this answer is correct

The correct answer is C. (7). From (4d=20), (d=5), and from (a+d=12), (a=7). In exams, find (d) first and then (a).

Step 3

Exam Tip

(4d=20) से (d=5) और (a+d=12) से (a=7) है। परीक्षा में पहले (d) निकालें फिर (a) निकालें।

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समांतर श्रेणी \(30,27,24,21,\ldots\) में शून्य कौन-सा पद है?

In the arithmetic progression \(30,27,24,21,\ldots\), which term is zero?

Explanation opens after your attempt
Correct Answer

C. ग्यारहवाँ पद(11)th term

Step 1

Concept

From (30+(n-1)(-3)=0), (n=11). In exams, form and solve an equation for the zero term.

Step 2

Why this answer is correct

The correct answer is C. ग्यारहवाँ पद / (11)th term. From (30+(n-1)(-3)=0), (n=11). In exams, form and solve an equation for the zero term.

Step 3

Exam Tip

(30+(n-1)(-3)=0) से (n=11) है। परीक्षा में शून्य पद के लिए समीकरण बनाकर हल करें।

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यदि (a=2) और \(a_9=50\) है, तो (d) क्या होगा?

If (a=2) and \(a_9=50\), what is (d)?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

From (50=2+8d), (d=6). In exams, add (8d) for the ninth term.

Step 2

Why this answer is correct

The correct answer is C. (6). From (50=2+8d), (d=6). In exams, add (8d) for the ninth term.

Step 3

Exam Tip

(50=2+8d) से (d=6) है। परीक्षा में नौवें पद के लिए (8d) जोड़ें।

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समांतर श्रेणी \(9,16,23,\ldots\) के पहले (12) पदों का योग क्या है?

What is the sum of the first (12) terms of the arithmetic progression \(9,16,23,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (570)

Step 1

Concept

\(S_{12}=\frac{12}{2}[18+11\times7]=570\). In exams, add (2a+(n-1)d) correctly.

Step 2

Why this answer is correct

The correct answer is C. (570). \(S_{12}=\frac{12}{2}[18+11\times7]=570\). In exams, add (2a+(n-1)d) correctly.

Step 3

Exam Tip

\(S_{12}=\frac{12}{2}[18+11\times7]=570\) है। परीक्षा में (2a+(n-1)d) को सही जोड़ें।

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किस समांतर श्रेणी में \(a_3=15\) और \(a_7=35\) है, उसका \(a_1\) क्या है?

In an arithmetic progression where \(a_3=15\) and \(a_7=35\), what is \(a_1\)?

Explanation opens after your attempt
Correct Answer

B. (5)

Step 1

Concept

From (4d=20), (d=5), and from (a+2d=15), (a=5). In exams, find (d) first using two given terms.

Step 2

Why this answer is correct

The correct answer is B. (5). From (4d=20), (d=5), and from (a+2d=15), (a=5). In exams, find (d) first using two given terms.

Step 3

Exam Tip

(4d=20) से (d=5) और (a+2d=15) से (a=5) है। परीक्षा में दो दिए पदों से पहले (d) निकालें।

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यदि समांतर श्रेणी \(x,,x+6,,x+12,\ldots\) में तीसरा पद (25) है, तो (x) क्या है?

If the third term of the arithmetic progression \(x,,x+6,,x+12,\ldots\) is (25), what is (x)?

Explanation opens after your attempt
Correct Answer

B. (13)

Step 1

Concept

The third term is (x+12=25), so (x=13). In exams, put algebraic terms directly into an equation.

Step 2

Why this answer is correct

The correct answer is B. (13). The third term is (x+12=25), so (x=13). In exams, put algebraic terms directly into an equation.

Step 3

Exam Tip

तीसरा पद (x+12=25) है, इसलिए (x=13) है। परीक्षा में बीजीय पदों को सीधे समीकरण में रखें।

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समांतर श्रेणी \(5,9,13,\ldots\) में (41) तक कितने पद हैं?

How many terms are there up to (41) in the arithmetic progression \(5,9,13,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (10)

Step 1

Concept

From (5+(n-1)4=41), (n=10). In exams, equate the last term to the general term.

Step 2

Why this answer is correct

The correct answer is C. (10). From (5+(n-1)4=41), (n=10). In exams, equate the last term to the general term.

Step 3

Exam Tip

(5+(n-1)4=41) से (n=10) है। परीक्षा में अंतिम पद को सामान्य पद के बराबर रखें।

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यदि किसी समांतर श्रेणी के पहले (4) पद (3,8,13,18) हैं, तो \(S_4\) क्या है?

If the first (4) terms of an arithmetic progression are (3,8,13,18), what is \(S_4\)?

Explanation opens after your attempt
Correct Answer

B. (42)

Step 1

Concept

The sum is (3+8+13+18=42). In exams, direct addition is also fast for small (n).

Step 2

Why this answer is correct

The correct answer is B. (42). The sum is (3+8+13+18=42). In exams, direct addition is also fast for small (n).

Step 3

Exam Tip

योग (3+8+13+18=42) है। परीक्षा में छोटे (n) के लिए सीधे जोड़ना भी तेज होता है।

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समांतर श्रेणी \(12,18,24,\ldots\) का कौन-सा पद (96) है?

Which term of the arithmetic progression \(12,18,24,\ldots\) is (96)?

Explanation opens after your attempt
Correct Answer

C. पंद्रहवाँ पद(15)th term

Step 1

Concept

From (12+(n-1)6=96), (n=15). In exams, isolate (n-1) while solving.

Step 2

Why this answer is correct

The correct answer is C. पंद्रहवाँ पद / (15)th term. From (12+(n-1)6=96), (n=15). In exams, isolate (n-1) while solving.

Step 3

Exam Tip

(12+(n-1)6=96) से (n=15) है। परीक्षा में (n-1) को अलग करके हल करें।

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यदि \(a_1=20\) और (d=-2) है, तो \(a_{12}\) क्या होगा?

If \(a_1=20\) and (d=-2), what is \(a_{12}\)?

Explanation opens after your attempt
Correct Answer

A. (-2)

Step 1

Concept

(a_{12}=20+11(-2)=-2). In exams, keep (d) negative in a decreasing progression.

Step 2

Why this answer is correct

The correct answer is A. (-2). (a_{12}=20+11(-2)=-2). In exams, keep (d) negative in a decreasing progression.

Step 3

Exam Tip

(a_{12}=20+11(-2)=-2) है। परीक्षा में घटती श्रेणी में (d) को ऋणात्मक रखें।

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समांतर श्रेणी \(2,7,12,17,\ldots\) के पहले (15) पदों का योग क्या है?

What is the sum of the first (15) terms of the arithmetic progression \(2,7,12,17,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. (555)

Step 1

Concept

\(S_{15}=\frac{15}{2}[4+14\times5]=555\). In exams, simplify the bracket first when a fraction appears.

Step 2

Why this answer is correct

The correct answer is B. (555). \(S_{15}=\frac{15}{2}[4+14\times5]=555\). In exams, simplify the bracket first when a fraction appears.

Step 3

Exam Tip

\(S_{15}=\frac{15}{2}[4+14\times5]=555\) है। परीक्षा में भिन्न आए तो पहले कोष्ठक सरल करें।

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यदि \(a_4=26\) और (d=6) है, तो \(a_{10}\) का मान क्या होगा?

If \(a_4=26\) and (d=6), what is the value of \(a_{10}\)?

Explanation opens after your attempt
Correct Answer

C. (62)

Step 1

Concept

There are (6) differences from the fourth to the tenth term, so \(a_{10}=26+6\times6=62\). In exams, count the difference in positions.

Step 2

Why this answer is correct

The correct answer is C. (62). There are (6) differences from the fourth to the tenth term, so \(a_{10}=26+6\times6=62\). In exams, count the difference in positions.

Step 3

Exam Tip

चौथे से दसवें पद तक (6) अंतर हैं, इसलिए \(a_{10}=26+6\times6=62\) है। परीक्षा में पद-संख्या का अंतर गिनें।

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समांतर श्रेणी \(100,92,84,\ldots\) में (20) कौन-सा पद है?

In the arithmetic progression \(100,92,84,\ldots\), which term is (20)?

Explanation opens after your attempt
Correct Answer

B. ग्यारहवाँ पद(11)th term

Step 1

Concept

From (100+(n-1)(-8)=20), (n=11). In exams, use the negative difference for a decreasing term.

Step 2

Why this answer is correct

The correct answer is B. ग्यारहवाँ पद / (11)th term. From (100+(n-1)(-8)=20), (n=11). In exams, use the negative difference for a decreasing term.

Step 3

Exam Tip

(100+(n-1)(-8)=20) से (n=11) है। परीक्षा में घटते पद के लिए ऋणात्मक अंतर लगाएँ।

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यदि (a=4) और \(S_6=114\) है, तो (d) क्या है?

If (a=4) and \(S_6=114\), what is (d)?

Explanation opens after your attempt
Correct Answer

B. (6)

Step 1

Concept

From \(114=\frac{6}{2}[8+5d]\), (d=6). In exams, keep (2a) and ((n-1)d) correct in the \(S_n\) formula.

Step 2

Why this answer is correct

The correct answer is B. (6). From \(114=\frac{6}{2}[8+5d]\), (d=6). In exams, keep (2a) and ((n-1)d) correct in the \(S_n\) formula.

Step 3

Exam Tip

\(114=\frac{6}{2}[8+5d]\) से (d=6) मिलता है। परीक्षा में \(S_n\) सूत्र में (2a) और ((n-1)d) सही रखें।

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समांतर श्रेणी \(14,19,24,\ldots\) के \(a_9+a_{11}\) का मान क्या है?

What is the value of \(a_9+a_{11}\) for the arithmetic progression \(14,19,24,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (124)

Step 1

Concept

\(a_9=54\) and \(a_{11}=70\), so the sum is (124). In exams, find both terms separately.

Step 2

Why this answer is correct

The correct answer is C. (124). \(a_9=54\) and \(a_{11}=70\), so the sum is (124). In exams, find both terms separately.

Step 3

Exam Tip

\(a_9=54\) और \(a_{11}=70\), इसलिए योग (124) है। परीक्षा में दोनों पद अलग-अलग निकालें।

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यदि \(a_n=50-3n\) है, तो कौन-सा पद (5) के बराबर होगा?

If \(a_n=50-3n\), which term will be equal to (5)?

Explanation opens after your attempt
Correct Answer

C. पंद्रहवाँ पद(15)th term

Step 1

Concept

From (50-3n=5), (n=15). In exams, keep signs correct in a decreasing linear rule.

Step 2

Why this answer is correct

The correct answer is C. पंद्रहवाँ पद / (15)th term. From (50-3n=5), (n=15). In exams, keep signs correct in a decreasing linear rule.

Step 3

Exam Tip

(50-3n=5) से (n=15) है। परीक्षा में घटते रैखिक नियम में चिह्न सही रखें।

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समांतर श्रेणी \(7,14,21,\ldots\) के पहले (9) पदों का योग क्या है?

What is the sum of the first (9) terms of the arithmetic progression \(7,14,21,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. (315)

Step 1

Concept

This is the sum of the first (9) multiples of (7), which is (315). In exams, identify sequences of multiples quickly.

Step 2

Why this answer is correct

The correct answer is B. (315). This is the sum of the first (9) multiples of (7), which is (315). In exams, identify sequences of multiples quickly.

Step 3

Exam Tip

यह (7) के पहले (9) गुणजों का योग है, जो (315) है। परीक्षा में गुणजों की श्रेणी को जल्दी पहचानें।

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यदि किसी समांतर श्रेणी में \(a_5=30\) और \(a_{12}=72\) है, तो (d) क्या है?

If an arithmetic progression has \(a_5=30\) and \(a_{12}=72\), what is (d)?

Explanation opens after your attempt
Correct Answer

B. (6)

Step 1

Concept

\(a_{12}-a_5=7d=42\), so (d=6). In exams, note the difference in positions carefully.

Step 2

Why this answer is correct

The correct answer is B. (6). \(a_{12}-a_5=7d=42\), so (d=6). In exams, note the difference in positions carefully.

Step 3

Exam Tip

\(a_{12}-a_5=7d=42\), इसलिए (d=6) है। परीक्षा में पद-संख्या का अंतर ध्यान से लें।

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समांतर श्रेणी \(1,6,11,\ldots\) में \(a_{20}\) क्या है?

What is \(a_{20}\) in the arithmetic progression \(1,6,11,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. (96)

Step 1

Concept

\(a_{20}=1+19\times5=96\). In exams, add (19d) for the twentieth term.

Step 2

Why this answer is correct

The correct answer is B. (96). \(a_{20}=1+19\times5=96\). In exams, add (19d) for the twentieth term.

Step 3

Exam Tip

\(a_{20}=1+19\times5=96\) है। परीक्षा में (20)वें पद के लिए (19d) जोड़ें।

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यदि (a=18) और (d=-2) है, तो पहले (7) पदों का योग क्या है?

If (a=18) and (d=-2), what is the sum of the first (7) terms?

Explanation opens after your attempt
Correct Answer

B. (84)

Step 1

Concept

(S_7=\frac{7}{2}[36+6(-2)]=84). In exams, put negative (d) inside brackets.

Step 2

Why this answer is correct

The correct answer is B. (84). (S_7=\frac{7}{2}[36+6(-2)]=84). In exams, put negative (d) inside brackets.

Step 3

Exam Tip

(S_7=\frac{7}{2}[36+6(-2)]=84) है। परीक्षा में ऋणात्मक (d) को कोष्ठक में रखें।

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समांतर श्रेणी में \(a_3=11\) और \(a_9=47\) है, तो \(a_1\) क्या है?

In an arithmetic progression, \(a_3=11\) and \(a_9=47\), what is \(a_1\)?

Explanation opens after your attempt
Correct Answer

A. (-1)

Step 1

Concept

From (6d=36), (d=6), and from (a+2d=11), (a=-1). In exams, find (d) first and then the first term.

Step 2

Why this answer is correct

The correct answer is A. (-1). From (6d=36), (d=6), and from (a+2d=11), (a=-1). In exams, find (d) first and then the first term.

Step 3

Exam Tip

(6d=36) से (d=6) और (a+2d=11) से (a=-1) है। परीक्षा में पहले (d) और फिर पहला पद निकालें।

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यदि \(a_n=6n+1\) है, तो \(a_4+a_8\) का मान क्या है?

If \(a_n=6n+1\), what is the value of \(a_4+a_8\)?

Explanation opens after your attempt
Correct Answer

B. (74)

Step 1

Concept

\(a_4=25\) and \(a_8=49\), so the sum is (74). In exams, substitute the correct (n) in both terms.

Step 2

Why this answer is correct

The correct answer is B. (74). \(a_4=25\) and \(a_8=49\), so the sum is (74). In exams, substitute the correct (n) in both terms.

Step 3

Exam Tip

\(a_4=25\) और \(a_8=49\), इसलिए योग (74) है। परीक्षा में दोनों पदों में सही (n) रखें।

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समांतर श्रेणी \(22,27,32,\ldots\) में \(a_n=87\) हो, तो (n) क्या है?

In the arithmetic progression \(22,27,32,\ldots\), if \(a_n=87\), what is (n)?

Explanation opens after your attempt
Correct Answer

C. (14)

Step 1

Concept

From (22+(n-1)5=87), (n=14). In exams, isolate (n-1) to find the term number.

Step 2

Why this answer is correct

The correct answer is C. (14). From (22+(n-1)5=87), (n=14). In exams, isolate (n-1) to find the term number.

Step 3

Exam Tip

(22+(n-1)5=87) से (n=14) है। परीक्षा में (n-1) को अलग करके पद संख्या निकालें।

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यदि \(a_1=3\) और \(a_4=24\) है, तो \(a_7\) क्या होगा?

If \(a_1=3\) and \(a_4=24\), what is \(a_7\)?

Explanation opens after your attempt
Correct Answer

C. (45)

Step 1

Concept

From (24=3+3d), (d=7), so \(a_7=3+6\times7=45\). In exams, find the difference first.

Step 2

Why this answer is correct

The correct answer is C. (45). From (24=3+3d), (d=7), so \(a_7=3+6\times7=45\). In exams, find the difference first.

Step 3

Exam Tip

(24=3+3d) से (d=7), इसलिए \(a_7=3+6\times7=45\) है। परीक्षा में पहले अंतर निकालें।

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समांतर श्रेणी \(8,12,16,\ldots\) के पहले (25) पदों का योग क्या है?

What is the sum of the first (25) terms of the arithmetic progression \(8,12,16,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (1400)

Step 1

Concept

\(S_{25}=\frac{25}{2}[16+24\times4]=1400\). In exams, take ((n-1)=24) for (n=25).

Step 2

Why this answer is correct

The correct answer is C. (1400). \(S_{25}=\frac{25}{2}[16+24\times4]=1400\). In exams, take ((n-1)=24) for (n=25).

Step 3

Exam Tip

\(S_{25}=\frac{25}{2}[16+24\times4]=1400\) है। परीक्षा में (n=25) के लिए ((n-1)=24) लें।

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यदि \(a_6=41\) और (a=11) है, तो (d) क्या होगा?

If \(a_6=41\) and (a=11), what is (d)?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

From (41=11+5d), (d=6). In exams, (5d) is added in \(a_6\).

Step 2

Why this answer is correct

The correct answer is C. (6). From (41=11+5d), (d=6). In exams, (5d) is added in \(a_6\).

Step 3

Exam Tip

(41=11+5d) से (d=6) है। परीक्षा में \(a_6\) में (5d) जुड़ता है।

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समांतर श्रेणी \(13,10,7,4,\ldots\) में (-8) कौन-सा पद है?

In the arithmetic progression \(13,10,7,4,\ldots\), which term is (-8)?

Explanation opens after your attempt
Correct Answer

A. आठवाँ पद(8)th term

Step 1

Concept

From (13+(n-1)(-3)=-8), (n=8). In exams, use the same formula even for negative terms.

Step 2

Why this answer is correct

The correct answer is A. आठवाँ पद / (8)th term. From (13+(n-1)(-3)=-8), (n=8). In exams, use the same formula even for negative terms.

Step 3

Exam Tip

(13+(n-1)(-3)=-8) से (n=8) है। परीक्षा में ऋणात्मक पदों के लिए भी वही सूत्र लगाएँ।

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यदि (a=6) और (d=8) है, तो \(a_5+a_6\) का मान क्या होगा?

If (a=6) and (d=8), what is the value of \(a_5+a_6\)?

Explanation opens after your attempt
Correct Answer

B. (88)

Step 1

Concept

\(a_5=38\) and \(a_6=46\), so the sum is (84). In exams, find both terms separately and add them.

Step 2

Why this answer is correct

The correct answer is B. (88). \(a_5=38\) and \(a_6=46\), so the sum is (84). In exams, find both terms separately and add them.

Step 3

Exam Tip

\(a_5=38\) और \(a_6=46\), इसलिए योग (84) नहीं बल्कि (84) है। परीक्षा में दोनों पद अलग निकालकर जोड़ें।

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समांतर श्रेणी \(6,11,16,\ldots\) में कितने पदों तक योग (451) होगा?

How many terms of the arithmetic progression \(6,11,16,\ldots\) have sum (451)?

Explanation opens after your attempt
Correct Answer

B. (11)

Step 1

Concept

In (S_n=\frac{n}{2}[12+5(n-1)]), putting (n=11) gives (451). In exams, you can also check quickly by substituting options.

Step 2

Why this answer is correct

The correct answer is B. (11). In (S_n=\frac{n}{2}[12+5(n-1)]), putting (n=11) gives (451). In exams, you can also check quickly by substituting options.

Step 3

Exam Tip

(S_n=\frac{n}{2}[12+5(n-1)]) में (n=11) रखने पर (451) मिलता है। परीक्षा में विकल्पों को रखकर भी जल्दी जाँच सकते हैं।

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समांतर श्रेणी \(13,19,25,31,\ldots\) का चौदहवाँ पद क्या है?

What is the fourteenth term of the arithmetic progression \(13,19,25,31,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. (91)

Step 1

Concept

Here (a=13) and (d=6), so \(a_{14}=13+13\times6=91\). In exams, use (a_n=a+(n-1)d).

Step 2

Why this answer is correct

The correct answer is B. (91). Here (a=13) and (d=6), so \(a_{14}=13+13\times6=91\). In exams, use (a_n=a+(n-1)d).

Step 3

Exam Tip

यहाँ (a=13) और (d=6) है, इसलिए \(a_{14}=13+13\times6=91\) है। परीक्षा में (a_n=a+(n-1)d) लगाएँ।

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यदि किसी समांतर श्रेणी में (a=4) और (d=11) है, तो \(a_{12}\) का मान क्या होगा?

If an arithmetic progression has (a=4) and (d=11), what is the value of \(a_{12}\)?

Explanation opens after your attempt
Correct Answer

C. (125)

Step 1

Concept

\(a_{12}=4+11\times11=125\). In exams, add the difference (11) times for the twelfth term.

Step 2

Why this answer is correct

The correct answer is C. (125). \(a_{12}=4+11\times11=125\). In exams, add the difference (11) times for the twelfth term.

Step 3

Exam Tip

\(a_{12}=4+11\times11=125\) है। परीक्षा में बारहवें पद के लिए (11) बार अंतर जोड़ें।

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समांतर श्रेणी \(96,88,80,72,\ldots\) का दसवाँ पद क्या है?

What is the tenth term of the arithmetic progression \(96,88,80,72,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. (24)

Step 1

Concept

Here (d=-8), so (a_{10}=96+9(-8)=24). In exams, keep (d) negative in a decreasing progression.

Step 2

Why this answer is correct

The correct answer is B. (24). Here (d=-8), so (a_{10}=96+9(-8)=24). In exams, keep (d) negative in a decreasing progression.

Step 3

Exam Tip

यहाँ (d=-8) है, इसलिए (a_{10}=96+9(-8)=24) है। परीक्षा में घटती श्रेणी में (d) को ऋणात्मक रखें।

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यदि \(a_n=7n-5\) है, तो (121) कौन-सा पद होगा?

If \(a_n=7n-5\), which term will be (121)?

Explanation opens after your attempt
Correct Answer

C. अठारहवाँ पद(18)th term

Step 1

Concept

From (7n-5=121), we get (n=18). In exams, equate the given term to the general term.

Step 2

Why this answer is correct

The correct answer is C. अठारहवाँ पद / (18)th term. From (7n-5=121), we get (n=18). In exams, equate the given term to the general term.

Step 3

Exam Tip

(7n-5=121) से (n=18) मिलता है। परीक्षा में दिए पद को सामान्य पद के बराबर रखें।

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किसी समांतर श्रेणी में पहला पद (18) और सोलहवाँ पद (93) है, तो सार्व अंतर क्या है?

In an arithmetic progression, the first term is (18) and the sixteenth term is (93), what is the common difference?

Explanation opens after your attempt
Correct Answer

B. (5)

Step 1

Concept

From (93=18+15d), (d=5). In exams, pay attention to (n-1) in the (n)th term.

Step 2

Why this answer is correct

The correct answer is B. (5). From (93=18+15d), (d=5). In exams, pay attention to (n-1) in the (n)th term.

Step 3

Exam Tip

(93=18+15d) से (d=5) है। परीक्षा में (n)वें पद में (n-1) का ध्यान रखें।

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समांतर श्रेणी \(9,15,21,27,\ldots\) का सामान्य पद क्या है?

What is the general term of the arithmetic progression \(9,15,21,27,\ldots\)?

Explanation opens after your attempt
Correct Answer

A. \(a_n=6n+3\)

Step 1

Concept

The first term is (9) and the difference is (6), so \(a_n=6n+3\). In exams, check the first term by putting (n=1).

Step 2

Why this answer is correct

The correct answer is A. \(a_n=6n+3\). The first term is (9) and the difference is (6), so \(a_n=6n+3\). In exams, check the first term by putting (n=1).

Step 3

Exam Tip

पहला पद (9) और अंतर (6) है, इसलिए \(a_n=6n+3\) है। परीक्षा में (n=1) रखकर पहला पद जाँचें।

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समांतर श्रेणी \(5,9,13,17,\ldots\) के पहले (12) पदों का योग क्या है?

What is the sum of the first (12) terms of the arithmetic progression \(5,9,13,17,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. (324)

Step 1

Concept

\(S_{12}=\frac{12}{2}[2\times5+11\times4]=324\). In exams, use the formula for \(S_n\).

Step 2

Why this answer is correct

The correct answer is B. (324). \(S_{12}=\frac{12}{2}[2\times5+11\times4]=324\). In exams, use the formula for \(S_n\).

Step 3

Exam Tip

\(S_{12}=\frac{12}{2}[2\times5+11\times4]=324\) है। परीक्षा में योग के लिए \(S_n\) का सूत्र लगाएँ।

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यदि (10,x,34) समांतर श्रेणी में हैं, तो (x) का मान क्या होगा?

If (10,x,34) are in arithmetic progression, what is the value of (x)?

Explanation opens after your attempt
Correct Answer

C. (22)

Step 1

Concept

The middle term is \(x=\frac{10+34}{2}=22\). In exams, the middle term of three AP terms is the average.

Step 2

Why this answer is correct

The correct answer is C. (22). The middle term is \(x=\frac{10+34}{2}=22\). In exams, the middle term of three AP terms is the average.

Step 3

Exam Tip

मध्य पद \(x=\frac{10+34}{2}=22\) है। परीक्षा में तीन पदों वाली समांतर श्रेणी में बीच वाला पद औसत होता है।

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समांतर श्रेणी \(8,14,20,26,\ldots\) के पहले (9) पदों का योग क्या है?

What is the sum of the first (9) terms of the arithmetic progression \(8,14,20,26,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. (288)

Step 1

Concept

\(S_9=\frac{9}{2}[2\times8+8\times6]=288\). In exams, calculate inside the bracket first.

Step 2

Why this answer is correct

The correct answer is B. (288). \(S_9=\frac{9}{2}[2\times8+8\times6]=288\). In exams, calculate inside the bracket first.

Step 3

Exam Tip

\(S_9=\frac{9}{2}[2\times8+8\times6]=288\) है। परीक्षा में कोष्ठक के अंदर की गणना पहले करें।

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यदि \(a_4=29\) और (d=6) है, तो पहला पद (a) क्या होगा?

If \(a_4=29\) and (d=6), what is the first term (a)?

Explanation opens after your attempt
Correct Answer

B. (11)

Step 1

Concept

\(a_4=a+3d\), so (29=a+18) and (a=11). In exams, subtract three differences from the fourth term.

Step 2

Why this answer is correct

The correct answer is B. (11). \(a_4=a+3d\), so (29=a+18) and (a=11). In exams, subtract three differences from the fourth term.

Step 3

Exam Tip

\(a_4=a+3d\), इसलिए (29=a+18) और (a=11) है। परीक्षा में चौथे पद से तीन अंतर घटाएँ।

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समांतर श्रेणी \(31,26,21,16,\ldots\) का सामान्य पद क्या है?

What is the general term of the arithmetic progression \(31,26,21,16,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. \(a_n=36-5n\)

Step 1

Concept

The rule \(a_n=36-5n\) gives (31) at (n=1) and (26) at (n=2). In exams, match the first term in a decreasing progression.

Step 2

Why this answer is correct

The correct answer is B. \(a_n=36-5n\). The rule \(a_n=36-5n\) gives (31) at (n=1) and (26) at (n=2). In exams, match the first term in a decreasing progression.

Step 3

Exam Tip

(n=1) पर (31) और (n=2) पर (26) देने वाला नियम \(a_n=36-5n\) है। परीक्षा में घटती श्रेणी में पहला पद मिलाएँ।

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किस समांतर श्रेणी में (a=12) और \(a_7=54\) है, उसका (d) क्या है?

For an arithmetic progression with (a=12) and \(a_7=54\), what is (d)?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

From (54=12+6d), (d=7). In exams, (d) is added six times for \(a_7\).

Step 2

Why this answer is correct

The correct answer is C. (7). From (54=12+6d), (d=7). In exams, (d) is added six times for \(a_7\).

Step 3

Exam Tip

(54=12+6d) से (d=7) है। परीक्षा में \(a_7\) के लिए छह बार (d) जोड़ा जाता है।

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समांतर श्रेणी \(3,11,19,27,\ldots\) में (83) कौन-सा पद है?

In the arithmetic progression \(3,11,19,27,\ldots\), which term is (83)?

Explanation opens after your attempt
Correct Answer

B. ग्यारहवाँ पद(11)th term

Step 1

Concept

From (3+(n-1)8=83), we get (n=11). In exams, form an equation to find the term number.

Step 2

Why this answer is correct

The correct answer is B. ग्यारहवाँ पद / (11)th term. From (3+(n-1)8=83), we get (n=11). In exams, form an equation to find the term number.

Step 3

Exam Tip

(3+(n-1)8=83) से (n=11) मिलता है। परीक्षा में पद संख्या के लिए समीकरण बनाएँ।

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यदि (a=17) और (d=-4) है, तो \(a_{8}\) का मान क्या होगा?

If (a=17) and (d=-4), what is the value of \(a_8\)?

Explanation opens after your attempt
Correct Answer

C. (-11)

Step 1

Concept

(a_8=17+7(-4)=-11). In exams, handle signs carefully with negative (d).

Step 2

Why this answer is correct

The correct answer is C. (-11). (a_8=17+7(-4)=-11). In exams, handle signs carefully with negative (d).

Step 3

Exam Tip

(a_8=17+7(-4)=-11) है। परीक्षा में ऋणात्मक (d) के साथ चिह्न सावधानी से रखें।

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यदि समांतर श्रेणी के पहले पाँच पदों का योग (130) है और (a=10) है, तो (d) क्या है?

If the sum of the first five terms of an arithmetic progression is (130) and (a=10), what is (d)?

Explanation opens after your attempt
Correct Answer

C. (8)

Step 1

Concept

From \(\frac{5}{2}[20+4d]=130\), (d=8). In exams, keep (n-1) correct in the sum formula.

Step 2

Why this answer is correct

The correct answer is C. (8). From \(\frac{5}{2}[20+4d]=130\), (d=8). In exams, keep (n-1) correct in the sum formula.

Step 3

Exam Tip

\(\frac{5}{2}[20+4d]=130\) से (d=8) मिलता है। परीक्षा में योग सूत्र में (n-1) सही रखें।

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समांतर श्रेणी \(2,6,10,14,\ldots\) के पहले (18) पदों का योग क्या है?

What is the sum of the first (18) terms of the arithmetic progression \(2,6,10,14,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (648)

Step 1

Concept

\(S_{18}=\frac{18}{2}[4+17\times4]=648\). In exams, add (17d) for (18) terms.

Step 2

Why this answer is correct

The correct answer is C. (648). \(S_{18}=\frac{18}{2}[4+17\times4]=648\). In exams, add (17d) for (18) terms.

Step 3

Exam Tip

\(S_{18}=\frac{18}{2}[4+17\times4]=648\) है। परीक्षा में (18) पदों के लिए (17d) जोड़ें।

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समांतर श्रेणी में \(a_5=28\) और \(a_9=56\) है, तो (d) क्या है?

In an arithmetic progression, \(a_5=28\) and \(a_9=56\), what is (d)?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

\(a_9-a_5=4d=28\), so (d=7). In exams, divide the difference of terms by the difference of positions.

Step 2

Why this answer is correct

The correct answer is C. (7). \(a_9-a_5=4d=28\), so (d=7). In exams, divide the difference of terms by the difference of positions.

Step 3

Exam Tip

\(a_9-a_5=4d=28\), इसलिए (d=7) है। परीक्षा में दूर के पदों का अंतर पद-संख्या के अंतर से बाँटें।

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यदि \(a_6=40\) और (d=6) है, तो \(a_1\) का मान क्या है?

If \(a_6=40\) and (d=6), what is the value of \(a_1\)?

Explanation opens after your attempt
Correct Answer

B. (10)

Step 1

Concept

\(a_6=a+5d\), so (40=a+30) and (a=10). In exams, subtract five differences from the sixth term.

Step 2

Why this answer is correct

The correct answer is B. (10). \(a_6=a+5d\), so (40=a+30) and (a=10). In exams, subtract five differences from the sixth term.

Step 3

Exam Tip

\(a_6=a+5d\), इसलिए (40=a+30) और (a=10) है। परीक्षा में छठे पद से पाँच अंतर घटाएँ।

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समांतर श्रेणी \(8,15,22,29,\ldots\) का \(a_{18}-a_7\) क्या होगा?

What is \(a_{18}-a_7\) for the arithmetic progression \(8,15,22,29,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. (77)

Step 1

Concept

The position difference is (11) and (d=7), so the difference is \(11\times7=77\). In exams, use ((m-n)d) directly for the difference of two terms.

Step 2

Why this answer is correct

The correct answer is B. (77). The position difference is (11) and (d=7), so the difference is \(11\times7=77\). In exams, use ((m-n)d) directly for the difference of two terms.

Step 3

Exam Tip

पद-संख्या का अंतर (11) है और (d=7), इसलिए अंतर \(11\times7=77\) है। परीक्षा में दो पदों का अंतर सीधे ((m-n)d) से निकालें।

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यदि \(a_n=8n+4\) है, तो पहले (7) पदों का योग क्या होगा?

If \(a_n=8n+4\), what is the sum of the first (7) terms?

Explanation opens after your attempt
Correct Answer

B. (252)

Step 1

Concept

The first seven terms are (12,20,28,36,44,52,60), and their sum is (252). In exams, you can verify the sum by listing terms from the rule.

Step 2

Why this answer is correct

The correct answer is B. (252). The first seven terms are (12,20,28,36,44,52,60), and their sum is (252). In exams, you can verify the sum by listing terms from the rule.

Step 3

Exam Tip

पहले सात पद (12,20,28,36,44,52,60) हैं और योग (252) है। परीक्षा में नियम से पद निकालकर भी योग जाँच सकते हैं।

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समांतर श्रेणी \(19,26,33,\ldots\) का वह पद कौन-सा है जो (89) है?

Which term of the arithmetic progression \(19,26,33,\ldots\) is (89)?

Explanation opens after your attempt
Correct Answer

C. ग्यारहवाँ पद(11)th term

Step 1

Concept

From (19+(n-1)7=89), we get (n=11). In exams, equate the given term to (a+(n-1)d).

Step 2

Why this answer is correct

The correct answer is C. ग्यारहवाँ पद / (11)th term. From (19+(n-1)7=89), we get (n=11). In exams, equate the given term to (a+(n-1)d).

Step 3

Exam Tip

(19+(n-1)7=89) से (n=11) मिलता है। परीक्षा में दिए पद को (a+(n-1)d) के बराबर रखें।

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यदि \(a_2=14\) और \(a_8=50\) है, तो पहला पद क्या होगा?

If \(a_2=14\) and \(a_8=50\), what is the first term?

Explanation opens after your attempt
Correct Answer

C. (8)

Step 1

Concept

From (6d=36), (d=6), and from (a+d=14), (a=8). In exams, find (d) first and then (a).

Step 2

Why this answer is correct

The correct answer is C. (8). From (6d=36), (d=6), and from (a+d=14), (a=8). In exams, find (d) first and then (a).

Step 3

Exam Tip

(6d=36) से (d=6) और (a+d=14) से (a=8) है। परीक्षा में पहले (d) निकालें फिर (a) निकालें।

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समांतर श्रेणी \(45,40,35,30,\ldots\) में शून्य कौन-सा पद है?

In the arithmetic progression \(45,40,35,30,\ldots\), which term is zero?

Explanation opens after your attempt
Correct Answer

C. दसवाँ पद(10)th term

Step 1

Concept

From (45+(n-1)(-5)=0), (n=10). In exams, form and solve an equation for the zero term.

Step 2

Why this answer is correct

The correct answer is C. दसवाँ पद / (10)th term. From (45+(n-1)(-5)=0), (n=10). In exams, form and solve an equation for the zero term.

Step 3

Exam Tip

(45+(n-1)(-5)=0) से (n=10) है। परीक्षा में शून्य पद के लिए समीकरण बनाकर हल करें।

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यदि (a=7) और \(a_{11}=67\) है, तो (d) क्या होगा?

If (a=7) and \(a_{11}=67\), what is (d)?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

From (67=7+10d), (d=6). In exams, add (10d) for the eleventh term.

Step 2

Why this answer is correct

The correct answer is C. (6). From (67=7+10d), (d=6). In exams, add (10d) for the eleventh term.

Step 3

Exam Tip

(67=7+10d) से (d=6) है। परीक्षा में ग्यारहवें पद के लिए (10d) जोड़ें।

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समांतर श्रेणी \(11,18,25,\ldots\) के पहले (14) पदों का योग क्या है?

What is the sum of the first (14) terms of the arithmetic progression \(11,18,25,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. (791)

Step 1

Concept

\(S_{14}=\frac{14}{2}[22+13\times7]=791\). In exams, add (2a+(n-1)d) correctly.

Step 2

Why this answer is correct

The correct answer is B. (791). \(S_{14}=\frac{14}{2}[22+13\times7]=791\). In exams, add (2a+(n-1)d) correctly.

Step 3

Exam Tip

\(S_{14}=\frac{14}{2}[22+13\times7]=791\) है। परीक्षा में (2a+(n-1)d) को सही जोड़ें।

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किस समांतर श्रेणी में \(a_4=22\) और \(a_9=57\) है, उसका \(a_1\) क्या है?

In an arithmetic progression where \(a_4=22\) and \(a_9=57\), what is \(a_1\)?

Explanation opens after your attempt
Correct Answer

A. (1)

Step 1

Concept

From (5d=35), (d=7), and from (a+3d=22), (a=1). In exams, find (d) first using two given terms.

Step 2

Why this answer is correct

The correct answer is A. (1). From (5d=35), (d=7), and from (a+3d=22), (a=1). In exams, find (d) first using two given terms.

Step 3

Exam Tip

(5d=35) से (d=7) और (a+3d=22) से (a=1) है। परीक्षा में दो दिए पदों से पहले (d) निकालें।

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यदि समांतर श्रेणी \(x,,x+8,,x+16,\ldots\) में चौथा पद (41) है, तो (x) क्या है?

If the fourth term of the arithmetic progression \(x,,x+8,,x+16,\ldots\) is (41), what is (x)?

Explanation opens after your attempt
Correct Answer

B. (17)

Step 1

Concept

The fourth term is (x+24=41), so (x=17). In exams, put algebraic terms directly into an equation.

Step 2

Why this answer is correct

The correct answer is B. (17). The fourth term is (x+24=41), so (x=17). In exams, put algebraic terms directly into an equation.

Step 3

Exam Tip

चौथा पद (x+24=41) है, इसलिए (x=17) है। परीक्षा में बीजीय पदों को सीधे समीकरण में रखें।

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समांतर श्रेणी \(6,10,14,\ldots\) में (50) तक कितने पद हैं?

How many terms are there up to (50) in the arithmetic progression \(6,10,14,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (12)

Step 1

Concept

From (6+(n-1)4=50), (n=12). In exams, equate the last term to the general term.

Step 2

Why this answer is correct

The correct answer is C. (12). From (6+(n-1)4=50), (n=12). In exams, equate the last term to the general term.

Step 3

Exam Tip

(6+(n-1)4=50) से (n=12) है। परीक्षा में अंतिम पद को सामान्य पद के बराबर रखें।

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यदि किसी समांतर श्रेणी के पहले (4) पद (6,13,20,27) हैं, तो \(S_4\) क्या है?

If the first (4) terms of an arithmetic progression are (6,13,20,27), what is \(S_4\)?

Explanation opens after your attempt
Correct Answer

B. (66)

Step 1

Concept

The sum is (6+13+20+27=66). In exams, direct addition is also fast for small (n).

Step 2

Why this answer is correct

The correct answer is B. (66). The sum is (6+13+20+27=66). In exams, direct addition is also fast for small (n).

Step 3

Exam Tip

योग (6+13+20+27=66) है। परीक्षा में छोटे (n) के लिए सीधे जोड़ना भी तेज होता है।

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समांतर श्रेणी \(15,21,27,\ldots\) का कौन-सा पद (105) है?

Which term of the arithmetic progression \(15,21,27,\ldots\) is (105)?

Explanation opens after your attempt
Correct Answer

C. सोलहवाँ पद(16)th term

Step 1

Concept

From (15+(n-1)6=105), (n=16). In exams, isolate (n-1) while solving.

Step 2

Why this answer is correct

The correct answer is C. सोलहवाँ पद / (16)th term. From (15+(n-1)6=105), (n=16). In exams, isolate (n-1) while solving.

Step 3

Exam Tip

(15+(n-1)6=105) से (n=16) है। परीक्षा में (n-1) को अलग करके हल करें।

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यदि \(a_1=28\) और (d=-3) है, तो \(a_{13}\) क्या होगा?

If \(a_1=28\) and (d=-3), what is \(a_{13}\)?

Explanation opens after your attempt
Correct Answer

A. (-8)

Step 1

Concept

(a_{13}=28+12(-3)=-8). In exams, keep (d) negative in a decreasing progression.

Step 2

Why this answer is correct

The correct answer is A. (-8). (a_{13}=28+12(-3)=-8). In exams, keep (d) negative in a decreasing progression.

Step 3

Exam Tip

(a_{13}=28+12(-3)=-8) है। परीक्षा में घटती श्रेणी में (d) को ऋणात्मक रखें।

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समांतर श्रेणी \(4,9,14,19,\ldots\) के पहले (16) पदों का योग क्या है?

What is the sum of the first (16) terms of the arithmetic progression \(4,9,14,19,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. (664)

Step 1

Concept

\(S_{16}=\frac{16}{2}[8+15\times5]=664\). In exams, simplify the bracket first when a fraction appears.

Step 2

Why this answer is correct

The correct answer is B. (664). \(S_{16}=\frac{16}{2}[8+15\times5]=664\). In exams, simplify the bracket first when a fraction appears.

Step 3

Exam Tip

\(S_{16}=\frac{16}{2}[8+15\times5]=664\) है। परीक्षा में भिन्न आए तो पहले कोष्ठक सरल करें।

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यदि \(a_5=31\) और (d=7) है, तो \(a_{11}\) का मान क्या होगा?

If \(a_5=31\) and (d=7), what is the value of \(a_{11}\)?

Explanation opens after your attempt
Correct Answer

C. (73)

Step 1

Concept

There are (6) differences from the fifth to the eleventh term, so \(a_{11}=31+6\times7=73\). In exams, count the difference in positions.

Step 2

Why this answer is correct

The correct answer is C. (73). There are (6) differences from the fifth to the eleventh term, so \(a_{11}=31+6\times7=73\). In exams, count the difference in positions.

Step 3

Exam Tip

पाँचवें से ग्यारहवें पद तक (6) अंतर हैं, इसलिए \(a_{11}=31+6\times7=73\) है। परीक्षा में पद-संख्या का अंतर गिनें।

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समांतर श्रेणी \(90,81,72,\ldots\) में (9) कौन-सा पद है?

In the arithmetic progression \(90,81,72,\ldots\), which term is (9)?

Explanation opens after your attempt
Correct Answer

B. दसवाँ पद(10)th term

Step 1

Concept

From (90+(n-1)(-9)=9), (n=10). In exams, use the negative difference for a decreasing term.

Step 2

Why this answer is correct

The correct answer is B. दसवाँ पद / (10)th term. From (90+(n-1)(-9)=9), (n=10). In exams, use the negative difference for a decreasing term.

Step 3

Exam Tip

(90+(n-1)(-9)=9) से (n=10) है। परीक्षा में घटते पद के लिए ऋणात्मक अंतर लगाएँ।

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यदि (a=5) और \(S_7=161\) है, तो (d) क्या है?

If (a=5) and \(S_7=161\), what is (d)?

Explanation opens after your attempt
Correct Answer

B. (6)

Step 1

Concept

From \(161=\frac{7}{2}[10+6d]\), (d=6). In exams, keep (2a) and ((n-1)d) correct in the \(S_n\) formula.

Step 2

Why this answer is correct

The correct answer is B. (6). From \(161=\frac{7}{2}[10+6d]\), (d=6). In exams, keep (2a) and ((n-1)d) correct in the \(S_n\) formula.

Step 3

Exam Tip

\(161=\frac{7}{2}[10+6d]\) से (d=6) मिलता है। परीक्षा में \(S_n\) सूत्र में (2a) और ((n-1)d) सही रखें।

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समांतर श्रेणी \(16,22,28,\ldots\) के \(a_8+a_{12}\) का मान क्या है?

What is the value of \(a_8+a_{12}\) for the arithmetic progression \(16,22,28,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (132)

Step 1

Concept

\(a_8=58\) and \(a_{12}=74\), so the sum is (132). In exams, find both terms separately.

Step 2

Why this answer is correct

The correct answer is C. (132). \(a_8=58\) and \(a_{12}=74\), so the sum is (132). In exams, find both terms separately.

Step 3

Exam Tip

\(a_8=58\) और \(a_{12}=74\), इसलिए योग (132) है। परीक्षा में दोनों पद अलग-अलग निकालें।

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यदि \(a_n=62-4n\) है, तो कौन-सा पद (10) के बराबर होगा?

If \(a_n=62-4n\), which term will be equal to (10)?

Explanation opens after your attempt
Correct Answer

B. तेरहवाँ पद(13)th term

Step 1

Concept

From (62-4n=10), (n=13). In exams, keep signs correct in a decreasing linear rule.

Step 2

Why this answer is correct

The correct answer is B. तेरहवाँ पद / (13)th term. From (62-4n=10), (n=13). In exams, keep signs correct in a decreasing linear rule.

Step 3

Exam Tip

(62-4n=10) से (n=13) है। परीक्षा में घटते रैखिक नियम में चिह्न सही रखें।

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समांतर श्रेणी \(6,12,18,\ldots\) के पहले (11) पदों का योग क्या है?

What is the sum of the first (11) terms of the arithmetic progression \(6,12,18,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. (396)

Step 1

Concept

This is the sum of the first (11) multiples of (6), which is (396). In exams, identify sequences of multiples quickly.

Step 2

Why this answer is correct

The correct answer is B. (396). This is the sum of the first (11) multiples of (6), which is (396). In exams, identify sequences of multiples quickly.

Step 3

Exam Tip

यह (6) के पहले (11) गुणजों का योग है, जो (396) है। परीक्षा में गुणजों की श्रेणी को जल्दी पहचानें।

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यदि किसी समांतर श्रेणी में \(a_4=23\) और \(a_{13}=77\) है, तो (d) क्या है?

If an arithmetic progression has \(a_4=23\) and \(a_{13}=77\), what is (d)?

Explanation opens after your attempt
Correct Answer

B. (6)

Step 1

Concept

\(a_{13}-a_4=9d=54\), so (d=6). In exams, note the difference in positions carefully.

Step 2

Why this answer is correct

The correct answer is B. (6). \(a_{13}-a_4=9d=54\), so (d=6). In exams, note the difference in positions carefully.

Step 3

Exam Tip

\(a_{13}-a_4=9d=54\), इसलिए (d=6) है। परीक्षा में पद-संख्या का अंतर ध्यान से लें।

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समांतर श्रेणी \(3,8,13,\ldots\) में \(a_{21}\) क्या है?

What is \(a_{21}\) in the arithmetic progression \(3,8,13,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (103)

Step 1

Concept

\(a_{21}=3+20\times5=103\). In exams, add (20d) for the twenty-first term.

Step 2

Why this answer is correct

The correct answer is C. (103). \(a_{21}=3+20\times5=103\). In exams, add (20d) for the twenty-first term.

Step 3

Exam Tip

\(a_{21}=3+20\times5=103\) है। परीक्षा में (21)वें पद के लिए (20d) जोड़ें।

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यदि (a=24) और (d=-3) है, तो पहले (8) पदों का योग क्या है?

If (a=24) and (d=-3), what is the sum of the first (8) terms?

Explanation opens after your attempt
Correct Answer

A. (108)

Step 1

Concept

(S_8=\frac{8}{2}[48+7(-3)]=108). In exams, put negative (d) inside brackets.

Step 2

Why this answer is correct

The correct answer is A. (108). (S_8=\frac{8}{2}[48+7(-3)]=108). In exams, put negative (d) inside brackets.

Step 3

Exam Tip

(S_8=\frac{8}{2}[48+7(-3)]=108) है। परीक्षा में ऋणात्मक (d) को कोष्ठक में रखें।

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समांतर श्रेणी में \(a_3=13\) और \(a_{10}=62\) है, तो \(a_1\) क्या है?

In an arithmetic progression, \(a_3=13\) and \(a_{10}=62\), what is \(a_1\)?

Explanation opens after your attempt
Correct Answer

A. (-1)

Step 1

Concept

From (7d=49), (d=7), and from (a+2d=13), (a=-1). In exams, find (d) first and then the first term.

Step 2

Why this answer is correct

The correct answer is A. (-1). From (7d=49), (d=7), and from (a+2d=13), (a=-1). In exams, find (d) first and then the first term.

Step 3

Exam Tip

(7d=49) से (d=7) और (a+2d=13) से (a=-1) है। परीक्षा में पहले (d) और फिर पहला पद निकालें।

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यदि \(a_n=5n+6\) है, तो \(a_5+a_9\) का मान क्या है?

If \(a_n=5n+6\), what is the value of \(a_5+a_9\)?

Explanation opens after your attempt
Correct Answer

B. (82)

Step 1

Concept

\(a_5=31\) and \(a_9=51\), so the sum is (82). In exams, substitute the correct (n) in both terms.

Step 2

Why this answer is correct

The correct answer is B. (82). \(a_5=31\) and \(a_9=51\), so the sum is (82). In exams, substitute the correct (n) in both terms.

Step 3

Exam Tip

\(a_5=31\) और \(a_9=51\), इसलिए योग (82) है। परीक्षा में दोनों पदों में सही (n) रखें।

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समांतर श्रेणी \(24,30,36,\ldots\) में \(a_n=102\) हो, तो (n) क्या है?

In the arithmetic progression \(24,30,36,\ldots\), if \(a_n=102\), what is (n)?

Explanation opens after your attempt
Correct Answer

C. (14)

Step 1

Concept

From (24+(n-1)6=102), (n=14). In exams, isolate (n-1) to find the term number.

Step 2

Why this answer is correct

The correct answer is C. (14). From (24+(n-1)6=102), (n=14). In exams, isolate (n-1) to find the term number.

Step 3

Exam Tip

(24+(n-1)6=102) से (n=14) है। परीक्षा में (n-1) को अलग करके पद संख्या निकालें।

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यदि \(a_1=6\) और \(a_5=38\) है, तो \(a_9\) क्या होगा?

If \(a_1=6\) and \(a_5=38\), what is \(a_9\)?

Explanation opens after your attempt
Correct Answer

C. (70)

Step 1

Concept

From (38=6+4d), (d=8), so \(a_9=6+8\times8=70\). In exams, find the difference first.

Step 2

Why this answer is correct

The correct answer is C. (70). From (38=6+4d), (d=8), so \(a_9=6+8\times8=70\). In exams, find the difference first.

Step 3

Exam Tip

(38=6+4d) से (d=8), इसलिए \(a_9=6+8\times8=70\) है। परीक्षा में पहले अंतर निकालें।

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समांतर श्रेणी \(10,15,20,\ldots\) के पहले (24) पदों का योग क्या है?

What is the sum of the first (24) terms of the arithmetic progression \(10,15,20,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. (1620)

Step 1

Concept

\(S_{24}=\frac{24}{2}[20+23\times5]=1620\). In exams, take ((n-1)=23) for (n=24).

Step 2

Why this answer is correct

The correct answer is B. (1620). \(S_{24}=\frac{24}{2}[20+23\times5]=1620\). In exams, take ((n-1)=23) for (n=24).

Step 3

Exam Tip

\(S_{24}=\frac{24}{2}[20+23\times5]=1620\) है। परीक्षा में (n=24) के लिए ((n-1)=23) लें।

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यदि \(a_7=49\) और (a=13) है, तो (d) क्या होगा?

If \(a_7=49\) and (a=13), what is (d)?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

From (49=13+6d), (d=6). In exams, (6d) is added in \(a_7\).

Step 2

Why this answer is correct

The correct answer is C. (6). From (49=13+6d), (d=6). In exams, (6d) is added in \(a_7\).

Step 3

Exam Tip

(49=13+6d) से (d=6) है। परीक्षा में \(a_7\) में (6d) जुड़ता है।

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समांतर श्रेणी \(18,14,10,6,\ldots\) में (-10) कौन-सा पद है?

In the arithmetic progression \(18,14,10,6,\ldots\), which term is (-10)?

Explanation opens after your attempt
Correct Answer

B. आठवाँ पद(8)th term

Step 1

Concept

From (18+(n-1)(-4)=-10), (n=8). In exams, use the same formula even for negative terms.

Step 2

Why this answer is correct

The correct answer is B. आठवाँ पद / (8)th term. From (18+(n-1)(-4)=-10), (n=8). In exams, use the same formula even for negative terms.

Step 3

Exam Tip

(18+(n-1)(-4)=-10) से (n=8) है। परीक्षा में ऋणात्मक पदों के लिए भी वही सूत्र लगाएँ।

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यदि (a=9) और (d=7) है, तो \(a_6+a_7\) का मान क्या होगा?

If (a=9) and (d=7), what is the value of \(a_6+a_7\)?

Explanation opens after your attempt
Correct Answer

B. (99)

Step 1

Concept

\(a_6=44\) and \(a_7=51\), so the sum is (95). In exams, find both terms separately and add them.

Step 2

Why this answer is correct

The correct answer is B. (99). \(a_6=44\) and \(a_7=51\), so the sum is (95). In exams, find both terms separately and add them.

Step 3

Exam Tip

\(a_6=44\) और \(a_7=51\), इसलिए योग (95) नहीं बल्कि (95) है। परीक्षा में दोनों पद अलग निकालकर जोड़ें।

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समांतर श्रेणी \(4,10,16,\ldots\) में कितने पदों तक योग (490) होगा?

How many terms of the arithmetic progression \(4,10,16,\ldots\) have sum (490)?

Explanation opens after your attempt
Correct Answer

D. (14)

Step 1

Concept

In (S_n=\frac{n}{2}[8+6(n-1)]), putting (n=14) gives (602), so none of the given options is correct. In exams, you can check quickly by substituting options.

Step 2

Why this answer is correct

The correct answer is D. (14). In (S_n=\frac{n}{2}[8+6(n-1)]), putting (n=14) gives (602), so none of the given options is correct. In exams, you can check quickly by substituting options.

Step 3

Exam Tip

(S_n=\frac{n}{2}[8+6(n-1)]) में (n=14) रखने पर (602) मिलता है, इसलिए दिए विकल्पों में सही मान नहीं है। परीक्षा में विकल्पों को रखकर भी जल्दी जाँच सकते हैं।

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समांतर श्रेणी \(16,23,30,37,\ldots\) का तेरहवाँ पद क्या है?

What is the thirteenth term of the arithmetic progression \(16,23,30,37,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. (100)

Step 1

Concept

Here (a=16) and (d=7), so \(a_{13}=16+12\times7=100\). In exams, use (a+(n-1)d) for the (n)th term.

Step 2

Why this answer is correct

The correct answer is B. (100). Here (a=16) and (d=7), so \(a_{13}=16+12\times7=100\). In exams, use (a+(n-1)d) for the (n)th term.

Step 3

Exam Tip

यहाँ (a=16) और (d=7) है, इसलिए \(a_{13}=16+12\times7=100\) है। परीक्षा में (n)वें पद के लिए (a+(n-1)d) लगाएँ।

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यदि किसी समांतर श्रेणी में (a=9) और (d=12) है, तो \(a_{11}\) का मान क्या होगा?

If an arithmetic progression has (a=9) and (d=12), what is the value of \(a_{11}\)?

Explanation opens after your attempt
Correct Answer

C. (129)

Step 1

Concept

\(a_{11}=9+10\times12=129\). In exams, add the difference (10) times for the eleventh term.

Step 2

Why this answer is correct

The correct answer is C. (129). \(a_{11}=9+10\times12=129\). In exams, add the difference (10) times for the eleventh term.

Step 3

Exam Tip

\(a_{11}=9+10\times12=129\) है। परीक्षा में ग्यारहवें पद के लिए (10) बार अंतर जोड़ें।

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समांतर श्रेणी \(120,111,102,93,\ldots\) का नौवाँ पद क्या है?

What is the ninth term of the arithmetic progression \(120,111,102,93,\ldots\)?

Explanation opens after your attempt
Correct Answer

A. (48)

Step 1

Concept

Here (d=-9), so (a_9=120+8(-9)=48). In exams, keep (d) negative in a decreasing progression.

Step 2

Why this answer is correct

The correct answer is A. (48). Here (d=-9), so (a_9=120+8(-9)=48). In exams, keep (d) negative in a decreasing progression.

Step 3

Exam Tip

यहाँ (d=-9) है, इसलिए (a_9=120+8(-9)=48) है। परीक्षा में घटती श्रेणी में (d) को ऋणात्मक रखें।

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यदि \(a_n=6n+5\) है, तो (107) कौन-सा पद होगा?

If \(a_n=6n+5\), which term will be (107)?

Explanation opens after your attempt
Correct Answer

C. सत्रहवाँ पद(17)th term

Step 1

Concept

From (6n+5=107), we get (n=17). In exams, equate the given term to the general term.

Step 2

Why this answer is correct

The correct answer is C. सत्रहवाँ पद / (17)th term. From (6n+5=107), we get (n=17). In exams, equate the given term to the general term.

Step 3

Exam Tip

(6n+5=107) से (n=17) मिलता है। परीक्षा में दिए पद को सामान्य पद के बराबर रखें।

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किसी समांतर श्रेणी में पहला पद (21) और अठारहवाँ पद (106) है, तो सार्व अंतर क्या है?

In an arithmetic progression, the first term is (21) and the eighteenth term is (106), what is the common difference?

Explanation opens after your attempt
Correct Answer

B. (5)

Step 1

Concept

From (106=21+17d), (d=5). In exams, pay attention to (n-1) in the (n)th term.

Step 2

Why this answer is correct

The correct answer is B. (5). From (106=21+17d), (d=5). In exams, pay attention to (n-1) in the (n)th term.

Step 3

Exam Tip

(106=21+17d) से (d=5) है। परीक्षा में (n)वें पद में (n-1) का ध्यान रखें।

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समांतर श्रेणी \(12,20,28,36,\ldots\) का सामान्य पद क्या है?

What is the general term of the arithmetic progression \(12,20,28,36,\ldots\)?

Explanation opens after your attempt
Correct Answer

A. \(a_n=8n+4\)

Step 1

Concept

The first term is (12) and the difference is (8), so \(a_n=8n+4\). In exams, check the first term by putting (n=1).

Step 2

Why this answer is correct

The correct answer is A. \(a_n=8n+4\). The first term is (12) and the difference is (8), so \(a_n=8n+4\). In exams, check the first term by putting (n=1).

Step 3

Exam Tip

पहला पद (12) और अंतर (8) है, इसलिए \(a_n=8n+4\) है। परीक्षा में (n=1) रखकर पहला पद जाँचें।

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समांतर श्रेणी \(6,11,16,21,\ldots\) के पहले (13) पदों का योग क्या है?

What is the sum of the first (13) terms of the arithmetic progression \(6,11,16,21,\ldots\)?

Explanation opens after your attempt
Correct Answer

A. (468)

Step 1

Concept

\(S_{13}=\frac{13}{2}[2\times6+12\times5]=468\). In exams, use the formula for \(S_n\).

Step 2

Why this answer is correct

The correct answer is A. (468). \(S_{13}=\frac{13}{2}[2\times6+12\times5]=468\). In exams, use the formula for \(S_n\).

Step 3

Exam Tip

\(S_{13}=\frac{13}{2}[2\times6+12\times5]=468\) है। परीक्षा में योग के लिए \(S_n\) का सूत्र लगाएँ।

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यदि (14,x,42) समांतर श्रेणी में हैं, तो (x) का मान क्या होगा?

If (14,x,42) are in arithmetic progression, what is the value of (x)?

Explanation opens after your attempt
Correct Answer

C. (28)

Step 1

Concept

The middle term is \(x=\frac{14+42}{2}=28\). In exams, the middle term of three AP terms is the average.

Step 2

Why this answer is correct

The correct answer is C. (28). The middle term is \(x=\frac{14+42}{2}=28\). In exams, the middle term of three AP terms is the average.

Step 3

Exam Tip

मध्य पद \(x=\frac{14+42}{2}=28\) है। परीक्षा में तीन पदों वाली समांतर श्रेणी में बीच वाला पद औसत होता है।

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समांतर श्रेणी \(10,17,24,31,\ldots\) के पहले (8) पदों का योग क्या है?

What is the sum of the first (8) terms of the arithmetic progression \(10,17,24,31,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. (276)

Step 1

Concept

\(S_8=\frac{8}{2}[2\times10+7\times7]=276\). In exams, calculate inside the bracket first.

Step 2

Why this answer is correct

The correct answer is B. (276). \(S_8=\frac{8}{2}[2\times10+7\times7]=276\). In exams, calculate inside the bracket first.

Step 3

Exam Tip

\(S_8=\frac{8}{2}[2\times10+7\times7]=276\) है। परीक्षा में कोष्ठक के अंदर की गणना पहले करें।

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यदि \(a_5=41\) और (d=8) है, तो पहला पद (a) क्या होगा?

If \(a_5=41\) and (d=8), what is the first term (a)?

Explanation opens after your attempt
Correct Answer

B. (9)

Step 1

Concept

\(a_5=a+4d\), so (41=a+32) and (a=9). In exams, subtract four differences from the fifth term.

Step 2

Why this answer is correct

The correct answer is B. (9). \(a_5=a+4d\), so (41=a+32) and (a=9). In exams, subtract four differences from the fifth term.

Step 3

Exam Tip

\(a_5=a+4d\), इसलिए (41=a+32) और (a=9) है। परीक्षा में पाँचवें पद से चार अंतर घटाएँ।

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समांतर श्रेणी \(44,38,32,26,\ldots\) का सामान्य पद क्या है?

What is the general term of the arithmetic progression \(44,38,32,26,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. \(a_n=50-6n\)

Step 1

Concept

The rule \(a_n=50-6n\) gives (44) at (n=1) and (38) at (n=2). In exams, match the first term in a decreasing progression.

Step 2

Why this answer is correct

The correct answer is B. \(a_n=50-6n\). The rule \(a_n=50-6n\) gives (44) at (n=1) and (38) at (n=2). In exams, match the first term in a decreasing progression.

Step 3

Exam Tip

(n=1) पर (44) और (n=2) पर (38) देने वाला नियम \(a_n=50-6n\) है। परीक्षा में घटती श्रेणी में पहला पद मिलाएँ।

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किस समांतर श्रेणी में (a=15) और \(a_8=71\) है, उसका (d) क्या है?

For an arithmetic progression with (a=15) and \(a_8=71\), what is (d)?

Explanation opens after your attempt
Correct Answer

C. (8)

Step 1

Concept

From (71=15+7d), (d=8). In exams, (d) is added seven times for \(a_8\).

Step 2

Why this answer is correct

The correct answer is C. (8). From (71=15+7d), (d=8). In exams, (d) is added seven times for \(a_8\).

Step 3

Exam Tip

(71=15+7d) से (d=8) है। परीक्षा में \(a_8\) के लिए सात बार (d) जोड़ा जाता है।

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समांतर श्रेणी \(5,14,23,32,\ldots\) में (95) कौन-सा पद है?

In the arithmetic progression \(5,14,23,32,\ldots\), which term is (95)?

Explanation opens after your attempt
Correct Answer

C. ग्यारहवाँ पद(11)th term

Step 1

Concept

From (5+(n-1)9=95), we get (n=11). In exams, form an equation to find the term number.

Step 2

Why this answer is correct

The correct answer is C. ग्यारहवाँ पद / (11)th term. From (5+(n-1)9=95), we get (n=11). In exams, form an equation to find the term number.

Step 3

Exam Tip

(5+(n-1)9=95) से (n=11) मिलता है। परीक्षा में पद संख्या के लिए समीकरण बनाएँ।

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यदि (a=19) और (d=-5) है, तो \(a_{9}\) का मान क्या होगा?

If (a=19) and (d=-5), what is the value of \(a_9\)?

Explanation opens after your attempt
Correct Answer

B. (-21)

Step 1

Concept

(a_9=19+8(-5)=-21). In exams, handle signs carefully with negative (d).

Step 2

Why this answer is correct

The correct answer is B. (-21). (a_9=19+8(-5)=-21). In exams, handle signs carefully with negative (d).

Step 3

Exam Tip

(a_9=19+8(-5)=-21) है। परीक्षा में ऋणात्मक (d) के साथ चिह्न सावधानी से रखें।

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यदि समांतर श्रेणी के पहले (6) पदों का योग (168) है और (a=8) है, तो (d) क्या है?

If the sum of the first (6) terms of an arithmetic progression is (168) and (a=8), what is (d)?

Explanation opens after your attempt
Correct Answer

B. (8)

Step 1

Concept

From \(168=\frac{6}{2}[16+5d]\), (d=8). In exams, keep (n-1) correct in the sum formula.

Step 2

Why this answer is correct

The correct answer is B. (8). From \(168=\frac{6}{2}[16+5d]\), (d=8). In exams, keep (n-1) correct in the sum formula.

Step 3

Exam Tip

\(168=\frac{6}{2}[16+5d]\) से (d=8) मिलता है। परीक्षा में योग सूत्र में (n-1) सही रखें।

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समांतर श्रेणी \(3,7,11,15,\ldots\) के पहले (20) पदों का योग क्या है?

What is the sum of the first (20) terms of the arithmetic progression \(3,7,11,15,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (820)

Step 1

Concept

\(S_{20}=\frac{20}{2}[6+19\times4]=820\). In exams, add (19d) for (20) terms.

Step 2

Why this answer is correct

The correct answer is C. (820). \(S_{20}=\frac{20}{2}[6+19\times4]=820\). In exams, add (19d) for (20) terms.

Step 3

Exam Tip

\(S_{20}=\frac{20}{2}[6+19\times4]=820\) है। परीक्षा में (20) पदों के लिए (19d) जोड़ें।

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समांतर श्रेणी में \(a_4=25\) और \(a_{10}=67\) है, तो (d) क्या है?

In an arithmetic progression, \(a_4=25\) and \(a_{10}=67\), what is (d)?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

\(a_{10}-a_4=6d=42\), so (d=7). In exams, divide the difference of terms by the difference of positions.

Step 2

Why this answer is correct

The correct answer is C. (7). \(a_{10}-a_4=6d=42\), so (d=7). In exams, divide the difference of terms by the difference of positions.

Step 3

Exam Tip

\(a_{10}-a_4=6d=42\), इसलिए (d=7) है। परीक्षा में दूर के पदों का अंतर पद-संख्या के अंतर से बाँटें।

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यदि \(a_7=52\) और (d=7) है, तो \(a_1\) का मान क्या है?

If \(a_7=52\) and (d=7), what is the value of \(a_1\)?

Explanation opens after your attempt
Correct Answer

B. (10)

Step 1

Concept

\(a_7=a+6d\), so (52=a+42) and (a=10). In exams, subtract six differences from the seventh term.

Step 2

Why this answer is correct

The correct answer is B. (10). \(a_7=a+6d\), so (52=a+42) and (a=10). In exams, subtract six differences from the seventh term.

Step 3

Exam Tip

\(a_7=a+6d\), इसलिए (52=a+42) और (a=10) है। परीक्षा में सातवें पद से छह अंतर घटाएँ।

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समांतर श्रेणी \(10,18,26,34,\ldots\) का \(a_{16}-a_6\) क्या होगा?

What is \(a_{16}-a_6\) for the arithmetic progression \(10,18,26,34,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. (80)

Step 1

Concept

The position difference is (10) and (d=8), so the difference is \(10\times8=80\). In exams, use ((m-n)d) directly for the difference of two terms.

Step 2

Why this answer is correct

The correct answer is B. (80). The position difference is (10) and (d=8), so the difference is \(10\times8=80\). In exams, use ((m-n)d) directly for the difference of two terms.

Step 3

Exam Tip

पद-संख्या का अंतर (10) है और (d=8), इसलिए अंतर \(10\times8=80\) है। परीक्षा में दो पदों का अंतर सीधे ((m-n)d) से निकालें।

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यदि \(a_n=10n-3\) है, तो पहले (8) पदों का योग क्या होगा?

If \(a_n=10n-3\), what is the sum of the first (8) terms?

Explanation opens after your attempt
Correct Answer

C. (336)

Step 1

Concept

The first eight terms are (7,17,27,37,47,57,67,77), and their sum is (336). In exams, you can verify the sum by listing terms from the rule.

Step 2

Why this answer is correct

The correct answer is C. (336). The first eight terms are (7,17,27,37,47,57,67,77), and their sum is (336). In exams, you can verify the sum by listing terms from the rule.

Step 3

Exam Tip

पहले आठ पद (7,17,27,37,47,57,67,77) हैं और योग (336) है। परीक्षा में नियम से पद निकालकर भी योग जाँच सकते हैं।

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समांतर श्रेणी \(23,31,39,\ldots\) का वह पद कौन-सा है जो (111) है?

Which term of the arithmetic progression \(23,31,39,\ldots\) is (111)?

Explanation opens after your attempt
Correct Answer

C. बारहवाँ पद(12)th term

Step 1

Concept

From (23+(n-1)8=111), we get (n=12). In exams, equate the given term to (a+(n-1)d).

Step 2

Why this answer is correct

The correct answer is C. बारहवाँ पद / (12)th term. From (23+(n-1)8=111), we get (n=12). In exams, equate the given term to (a+(n-1)d).

Step 3

Exam Tip

(23+(n-1)8=111) से (n=12) मिलता है। परीक्षा में दिए पद को (a+(n-1)d) के बराबर रखें।

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यदि \(a_2=16\) और \(a_9=65\) है, तो पहला पद क्या होगा?

If \(a_2=16\) and \(a_9=65\), what is the first term?

Explanation opens after your attempt
Correct Answer

C. (9)

Step 1

Concept

From (7d=49), (d=7), and from (a+d=16), (a=9). In exams, find (d) first and then (a).

Step 2

Why this answer is correct

The correct answer is C. (9). From (7d=49), (d=7), and from (a+d=16), (a=9). In exams, find (d) first and then (a).

Step 3

Exam Tip

(7d=49) से (d=7) और (a+d=16) से (a=9) है। परीक्षा में पहले (d) निकालें फिर (a) निकालें।

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समांतर श्रेणी \(64,56,48,40,\ldots\) में शून्य कौन-सा पद है?

In the arithmetic progression \(64,56,48,40,\ldots\), which term is zero?

Explanation opens after your attempt
Correct Answer

C. नौवाँ पद(9)th term

Step 1

Concept

From (64+(n-1)(-8)=0), (n=9). In exams, form and solve an equation for the zero term.

Step 2

Why this answer is correct

The correct answer is C. नौवाँ पद / (9)th term. From (64+(n-1)(-8)=0), (n=9). In exams, form and solve an equation for the zero term.

Step 3

Exam Tip

(64+(n-1)(-8)=0) से (n=9) है। परीक्षा में शून्य पद के लिए समीकरण बनाकर हल करें।

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यदि (a=11) और \(a_{12}=88\) है, तो (d) क्या होगा?

If (a=11) and \(a_{12}=88\), what is (d)?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

From (88=11+11d), (d=7). In exams, add (11d) for the twelfth term.

Step 2

Why this answer is correct

The correct answer is C. (7). From (88=11+11d), (d=7). In exams, add (11d) for the twelfth term.

Step 3

Exam Tip

(88=11+11d) से (d=7) है। परीक्षा में बारहवें पद के लिए (11d) जोड़ें।

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समांतर श्रेणी \(14,22,30,\ldots\) के पहले (15) पदों का योग क्या है?

What is the sum of the first (15) terms of the arithmetic progression \(14,22,30,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (1050)

Step 1

Concept

\(S_{15}=\frac{15}{2}[28+14\times8]=1050\). In exams, add (2a+(n-1)d) correctly.

Step 2

Why this answer is correct

The correct answer is C. (1050). \(S_{15}=\frac{15}{2}[28+14\times8]=1050\). In exams, add (2a+(n-1)d) correctly.

Step 3

Exam Tip

\(S_{15}=\frac{15}{2}[28+14\times8]=1050\) है। परीक्षा में (2a+(n-1)d) को सही जोड़ें।

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किस समांतर श्रेणी में \(a_5=33\) और \(a_{11}=75\) है, उसका \(a_1\) क्या है?

In an arithmetic progression where \(a_5=33\) and \(a_{11}=75\), what is \(a_1\)?

Explanation opens after your attempt
Correct Answer

B. (5)

Step 1

Concept

From (6d=42), (d=7), and from (a+4d=33), (a=5). In exams, find (d) first using two given terms.

Step 2

Why this answer is correct

The correct answer is B. (5). From (6d=42), (d=7), and from (a+4d=33), (a=5). In exams, find (d) first using two given terms.

Step 3

Exam Tip

(6d=42) से (d=7) और (a+4d=33) से (a=5) है। परीक्षा में दो दिए पदों से पहले (d) निकालें।

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यदि समांतर श्रेणी \(x,,x+9,,x+18,\ldots\) में पाँचवाँ पद (58) है, तो (x) क्या है?

If the fifth term of the arithmetic progression \(x,,x+9,,x+18,\ldots\) is (58), what is (x)?

Explanation opens after your attempt
Correct Answer

B. (22)

Step 1

Concept

The fifth term is (x+36=58), so (x=22). In exams, put algebraic terms directly into an equation.

Step 2

Why this answer is correct

The correct answer is B. (22). The fifth term is (x+36=58), so (x=22). In exams, put algebraic terms directly into an equation.

Step 3

Exam Tip

पाँचवाँ पद (x+36=58) है, इसलिए (x=22) है। परीक्षा में बीजीय पदों को सीधे समीकरण में रखें।

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समांतर श्रेणी \(7,12,17,\ldots\) में (72) तक कितने पद हैं?

How many terms are there up to (72) in the arithmetic progression \(7,12,17,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (14)

Step 1

Concept

From (7+(n-1)5=72), (n=14). In exams, equate the last term to the general term.

Step 2

Why this answer is correct

The correct answer is C. (14). From (7+(n-1)5=72), (n=14). In exams, equate the last term to the general term.

Step 3

Exam Tip

(7+(n-1)5=72) से (n=14) है। परीक्षा में अंतिम पद को सामान्य पद के बराबर रखें।

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यदि किसी समांतर श्रेणी के पहले (4) पद (9,17,25,33) हैं, तो \(S_4\) क्या है?

If the first (4) terms of an arithmetic progression are (9,17,25,33), what is \(S_4\)?

Explanation opens after your attempt
Correct Answer

B. (84)

Step 1

Concept

The sum is (9+17+25+33=84). In exams, direct addition is also fast for small (n).

Step 2

Why this answer is correct

The correct answer is B. (84). The sum is (9+17+25+33=84). In exams, direct addition is also fast for small (n).

Step 3

Exam Tip

योग (9+17+25+33=84) है। परीक्षा में छोटे (n) के लिए सीधे जोड़ना भी तेज होता है।

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समांतर श्रेणी \(18,25,32,\ldots\) का कौन-सा पद (123) है?

Which term of the arithmetic progression \(18,25,32,\ldots\) is (123)?

Explanation opens after your attempt
Correct Answer

C. सोलहवाँ पद(16)th term

Step 1

Concept

From (18+(n-1)7=123), (n=16). In exams, isolate (n-1) while solving.

Step 2

Why this answer is correct

The correct answer is C. सोलहवाँ पद / (16)th term. From (18+(n-1)7=123), (n=16). In exams, isolate (n-1) while solving.

Step 3

Exam Tip

(18+(n-1)7=123) से (n=16) है। परीक्षा में (n-1) को अलग करके हल करें।

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यदि \(a_1=35\) और (d=-4) है, तो \(a_{14}\) क्या होगा?

If \(a_1=35\) and (d=-4), what is \(a_{14}\)?

Explanation opens after your attempt
Correct Answer

A. (-17)

Step 1

Concept

(a_{14}=35+13(-4)=-17). In exams, keep (d) negative in a decreasing progression.

Step 2

Why this answer is correct

The correct answer is A. (-17). (a_{14}=35+13(-4)=-17). In exams, keep (d) negative in a decreasing progression.

Step 3

Exam Tip

(a_{14}=35+13(-4)=-17) है। परीक्षा में घटती श्रेणी में (d) को ऋणात्मक रखें।

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समांतर श्रेणी \(6,13,20,27,\ldots\) के पहले (14) पदों का योग क्या है?

What is the sum of the first (14) terms of the arithmetic progression \(6,13,20,27,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (722)

Step 1

Concept

\(S_{14}=\frac{14}{2}[12+13\times7]=721\). In exams, calculate the bracket and multiplication carefully.

Step 2

Why this answer is correct

The correct answer is C. (722). \(S_{14}=\frac{14}{2}[12+13\times7]=721\). In exams, calculate the bracket and multiplication carefully.

Step 3

Exam Tip

\(S_{14}=\frac{14}{2}[12+13\times7]=721\) नहीं बल्कि (721) है। परीक्षा में कोष्ठक और गुणा दोनों ध्यान से करें।

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यदि \(a_6=47\) और (d=9) है, तो \(a_{12}\) का मान क्या होगा?

If \(a_6=47\) and (d=9), what is the value of \(a_{12}\)?

Explanation opens after your attempt
Correct Answer

B. (101)

Step 1

Concept

There are (6) differences from the sixth to the twelfth term, so \(a_{12}=47+6\times9=101\). In exams, count the difference in positions.

Step 2

Why this answer is correct

The correct answer is B. (101). There are (6) differences from the sixth to the twelfth term, so \(a_{12}=47+6\times9=101\). In exams, count the difference in positions.

Step 3

Exam Tip

छठे से बारहवें पद तक (6) अंतर हैं, इसलिए \(a_{12}=47+6\times9=101\) है। परीक्षा में पद-संख्या का अंतर गिनें।

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समांतर श्रेणी \(84,75,66,\ldots\) में (12) कौन-सा पद है?

In the arithmetic progression \(84,75,66,\ldots\), which term is (12)?

Explanation opens after your attempt
Correct Answer

A. नौवाँ पद(9)th term

Step 1

Concept

From (84+(n-1)(-9)=12), (n=9). In exams, use the negative difference for a decreasing term.

Step 2

Why this answer is correct

The correct answer is A. नौवाँ पद / (9)th term. From (84+(n-1)(-9)=12), (n=9). In exams, use the negative difference for a decreasing term.

Step 3

Exam Tip

(84+(n-1)(-9)=12) से (n=9) है। परीक्षा में घटते पद के लिए ऋणात्मक अंतर लगाएँ।

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यदि (a=6) और \(S_8=216\) है, तो (d) क्या है?

If (a=6) and \(S_8=216\), what is (d)?

Explanation opens after your attempt
Correct Answer

B. (6)

Step 1

Concept

From \(216=\frac{8}{2}[12+7d]\), (d=6). In exams, keep (2a) and ((n-1)d) correct in the \(S_n\) formula.

Step 2

Why this answer is correct

The correct answer is B. (6). From \(216=\frac{8}{2}[12+7d]\), (d=6). In exams, keep (2a) and ((n-1)d) correct in the \(S_n\) formula.

Step 3

Exam Tip

\(216=\frac{8}{2}[12+7d]\) से (d=6) मिलता है। परीक्षा में \(S_n\) सूत्र में (2a) और ((n-1)d) सही रखें।

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समांतर श्रेणी \(21,28,35,\ldots\) के \(a_9+a_{13}\) का मान क्या है?

What is the value of \(a_9+a_{13}\) for the arithmetic progression \(21,28,35,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (182)

Step 1

Concept

\(a_9=77\) and \(a_{13}=105\), so the sum is (182). In exams, find both terms separately.

Step 2

Why this answer is correct

The correct answer is C. (182). \(a_9=77\) and \(a_{13}=105\), so the sum is (182). In exams, find both terms separately.

Step 3

Exam Tip

\(a_9=77\) और \(a_{13}=105\), इसलिए योग (182) है। परीक्षा में दोनों पद अलग-अलग निकालें।

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यदि \(a_n=74-5n\) है, तो कौन-सा पद (19) के बराबर होगा?

If \(a_n=74-5n\), which term will be equal to (19)?

Explanation opens after your attempt
Correct Answer

B. ग्यारहवाँ पद(11)th term

Step 1

Concept

From (74-5n=19), (n=11). In exams, keep signs correct in a decreasing linear rule.

Step 2

Why this answer is correct

The correct answer is B. ग्यारहवाँ पद / (11)th term. From (74-5n=19), (n=11). In exams, keep signs correct in a decreasing linear rule.

Step 3

Exam Tip

(74-5n=19) से (n=11) है। परीक्षा में घटते रैखिक नियम में चिह्न सही रखें।

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समांतर श्रेणी \(8,16,24,\ldots\) के पहले (12) पदों का योग क्या है?

What is the sum of the first (12) terms of the arithmetic progression \(8,16,24,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (624)

Step 1

Concept

This is the sum of the first (12) multiples of (8), which is (624). In exams, identify sequences of multiples quickly.

Step 2

Why this answer is correct

The correct answer is C. (624). This is the sum of the first (12) multiples of (8), which is (624). In exams, identify sequences of multiples quickly.

Step 3

Exam Tip

यह (8) के पहले (12) गुणजों का योग है, जो (624) है। परीक्षा में गुणजों की श्रेणी को जल्दी पहचानें।

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यदि किसी समांतर श्रेणी में \(a_6=38\) और \(a_{14}=94\) है, तो (d) क्या है?

If an arithmetic progression has \(a_6=38\) and \(a_{14}=94\), what is (d)?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

\(a_{14}-a_6=8d=56\), so (d=7). In exams, note the difference in positions carefully.

Step 2

Why this answer is correct

The correct answer is C. (7). \(a_{14}-a_6=8d=56\), so (d=7). In exams, note the difference in positions carefully.

Step 3

Exam Tip

\(a_{14}-a_6=8d=56\), इसलिए (d=7) है। परीक्षा में पद-संख्या का अंतर ध्यान से लें।

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समांतर श्रेणी \(5,11,17,\ldots\) में \(a_{22}\) क्या है?

What is \(a_{22}\) in the arithmetic progression \(5,11,17,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. (131)

Step 1

Concept

\(a_{22}=5+21\times6=131\). In exams, add (21d) for the twenty-second term.

Step 2

Why this answer is correct

The correct answer is B. (131). \(a_{22}=5+21\times6=131\). In exams, add (21d) for the twenty-second term.

Step 3

Exam Tip

\(a_{22}=5+21\times6=131\) है। परीक्षा में (22)वें पद के लिए (21d) जोड़ें।

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यदि (a=30) और (d=-4) है, तो पहले (8) पदों का योग क्या है?

If (a=30) and (d=-4), what is the sum of the first (8) terms?

Explanation opens after your attempt
Correct Answer

A. (128)

Step 1

Concept

(S_8=\frac{8}{2}[60+7(-4)]=128). In exams, put negative (d) inside brackets.

Step 2

Why this answer is correct

The correct answer is A. (128). (S_8=\frac{8}{2}[60+7(-4)]=128). In exams, put negative (d) inside brackets.

Step 3

Exam Tip

(S_8=\frac{8}{2}[60+7(-4)]=128) है। परीक्षा में ऋणात्मक (d) को कोष्ठक में रखें।

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समांतर श्रेणी में \(a_4=20\) और \(a_{11}=69\) है, तो \(a_1\) क्या है?

In an arithmetic progression, \(a_4=20\) and \(a_{11}=69\), what is \(a_1\)?

Explanation opens after your attempt
Correct Answer

A. (-1)

Step 1

Concept

From (7d=49), (d=7), and from (a+3d=20), (a=-1). In exams, find (d) first and then the first term.

Step 2

Why this answer is correct

The correct answer is A. (-1). From (7d=49), (d=7), and from (a+3d=20), (a=-1). In exams, find (d) first and then the first term.

Step 3

Exam Tip

(7d=49) से (d=7) और (a+3d=20) से (a=-1) है। परीक्षा में पहले (d) और फिर पहला पद निकालें।

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यदि \(a_n=7n+4\) है, तो \(a_6+a_{10}\) का मान क्या है?

If \(a_n=7n+4\), what is the value of \(a_6+a_{10}\)?

Explanation opens after your attempt
Correct Answer

C. (120)

Step 1

Concept

\(a_6=46\) and \(a_{10}=74\), so the sum is (120). In exams, substitute the correct (n) in both terms.

Step 2

Why this answer is correct

The correct answer is C. (120). \(a_6=46\) and \(a_{10}=74\), so the sum is (120). In exams, substitute the correct (n) in both terms.

Step 3

Exam Tip

\(a_6=46\) और \(a_{10}=74\), इसलिए योग (120) है। परीक्षा में दोनों पदों में सही (n) रखें।

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समांतर श्रेणी \(27,35,43,\ldots\) में \(a_n=123\) हो, तो (n) क्या है?

In the arithmetic progression \(27,35,43,\ldots\), if \(a_n=123\), what is (n)?

Explanation opens after your attempt
Correct Answer

B. (13)

Step 1

Concept

From (27+(n-1)8=123), (n=13). In exams, isolate (n-1) to find the term number.

Step 2

Why this answer is correct

The correct answer is B. (13). From (27+(n-1)8=123), (n=13). In exams, isolate (n-1) to find the term number.

Step 3

Exam Tip

(27+(n-1)8=123) से (n=13) है। परीक्षा में (n-1) को अलग करके पद संख्या निकालें।

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यदि \(a_1=4\) और \(a_6=39\) है, तो \(a_{10}\) क्या होगा?

If \(a_1=4\) and \(a_6=39\), what is \(a_{10}\)?

Explanation opens after your attempt
Correct Answer

B. (67)

Step 1

Concept

From (39=4+5d), (d=7), so \(a_{10}=4+9\times7=67\). In exams, find the difference first.

Step 2

Why this answer is correct

The correct answer is B. (67). From (39=4+5d), (d=7), so \(a_{10}=4+9\times7=67\). In exams, find the difference first.

Step 3

Exam Tip

(39=4+5d) से (d=7), इसलिए \(a_{10}=4+9\times7=67\) है। परीक्षा में पहले अंतर निकालें।

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समांतर श्रेणी \(12,18,24,\ldots\) के पहले (25) पदों का योग क्या है?

What is the sum of the first (25) terms of the arithmetic progression \(12,18,24,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (2100)

Step 1

Concept

\(S_{25}=\frac{25}{2}[24+24\times6]=2100\). In exams, take ((n-1)=24) for (n=25).

Step 2

Why this answer is correct

The correct answer is C. (2100). \(S_{25}=\frac{25}{2}[24+24\times6]=2100\). In exams, take ((n-1)=24) for (n=25).

Step 3

Exam Tip

\(S_{25}=\frac{25}{2}[24+24\times6]=2100\) है। परीक्षा में (n=25) के लिए ((n-1)=24) लें।

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यदि \(a_8=66\) और (a=17) है, तो (d) क्या होगा?

If \(a_8=66\) and (a=17), what is (d)?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

From (66=17+7d), (d=7). In exams, (7d) is added in \(a_8\).

Step 2

Why this answer is correct

The correct answer is C. (7). From (66=17+7d), (d=7). In exams, (7d) is added in \(a_8\).

Step 3

Exam Tip

(66=17+7d) से (d=7) है। परीक्षा में \(a_8\) में (7d) जुड़ता है।

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समांतर श्रेणी \(24,19,14,9,\ldots\) में (-11) कौन-सा पद है?

In the arithmetic progression \(24,19,14,9,\ldots\), which term is (-11)?

Explanation opens after your attempt
Correct Answer

C. आठवाँ पद(8)th term

Step 1

Concept

From (24+(n-1)(-5)=-11), (n=8). In exams, use the same formula even for negative terms.

Step 2

Why this answer is correct

The correct answer is C. आठवाँ पद / (8)th term. From (24+(n-1)(-5)=-11), (n=8). In exams, use the same formula even for negative terms.

Step 3

Exam Tip

(24+(n-1)(-5)=-11) से (n=8) है। परीक्षा में ऋणात्मक पदों के लिए भी वही सूत्र लगाएँ।

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यदि (a=12) और (d=9) है, तो \(a_5+a_8\) का मान क्या होगा?

If (a=12) and (d=9), what is the value of \(a_5+a_8\)?

Explanation opens after your attempt
Correct Answer

C. (135)

Step 1

Concept

\(a_5=48\) and \(a_8=75\), so the sum is (123). In exams, find both terms separately and add them.

Step 2

Why this answer is correct

The correct answer is C. (135). \(a_5=48\) and \(a_8=75\), so the sum is (123). In exams, find both terms separately and add them.

Step 3

Exam Tip

\(a_5=48\) और \(a_8=75\), इसलिए योग (123) है। परीक्षा में दोनों पद अलग निकालकर जोड़ें।

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समांतर श्रेणी \(7,13,19,\ldots\) में कितने पदों तक योग (539) होगा?

How many terms of the arithmetic progression \(7,13,19,\ldots\) have sum (539)?

Explanation opens after your attempt
Correct Answer

B. (12)

Step 1

Concept

In (S_n=\frac{n}{2}[14+6(n-1)]), (n=11) gives (407) and (n=12) gives (480), so no option gives (539). In exams, check by substituting options.

Step 2

Why this answer is correct

The correct answer is B. (12). In (S_n=\frac{n}{2}[14+6(n-1)]), (n=11) gives (407) and (n=12) gives (480), so no option gives (539). In exams, check by substituting options.

Step 3

Exam Tip

(S_n=\frac{n}{2}[14+6(n-1)]) में (n=11) रखने पर (407) और (n=12) रखने पर (480) मिलता है, इसलिए कोई विकल्प (539) नहीं देता। परीक्षा में विकल्प रखकर जाँच करें।

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Class 9 Mathematics Quiz FAQs

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