How many terms are there up to (50) in the arithmetic progression (6,10,14,\ldots)?
Answer and explanation
Correct answer: 12
Here, the first term is \(a=6\), the common difference is \(d=4\), and the last term is \(l=50\). Using \(l=a+(n-1)d\), we get \(50=6+(n-1)4\), so \(n-1=11\) and \(n=12\). Therefore, there are 12 terms up to 50. With 11 terms, the last term would be 46, not 50. Exam tip: To find the number of terms, equate the last term to \(a+(n-1)d\).
Frequently asked questions
What is the correct answer to this question?
12
Why is this the correct answer?
Here, the first term is \(a=6\), the common difference is \(d=4\), and the last term is \(l=50\). Using \(l=a+(n-1)d\), we get \(50=6+(n-1)4\), so \(n-1=11\) and \(n=12\). Therefore, there are 12 terms up to 50. With 11 terms, the last term would be 46, not 50. Exam tip: To find the number of terms, equate the last term to \(a+(n-1)d\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Arithmetic Progression.
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