How can B={1,4,7,10,13} be written in set-builder form?
Answer and explanation
Correct answer: B={x:x=3n+1, n∈W, 0≤n≤4}
The governing pattern is an arithmetic progression with first term 1 and common difference 3. The rule x=3n+1, with n∈W and 0≤n≤4, produces x=1,4,7,10,13 when n=0,1,2,3,4. Thus it gives exactly the five members of B. Option B produces multiples of 3, option C has difference 2, and option D has difference 4, so option A is correct.
Frequently asked questions
What is the correct answer to this question?
B={x:x=3n+1, n∈W, 0≤n≤4}
Why is this the correct answer?
The governing pattern is an arithmetic progression with first term 1 and common difference 3. The rule x=3n+1, with n∈W and 0≤n≤4, produces x=1,4,7,10,13 when n=0,1,2,3,4. Thus it gives exactly the five members of B. Option B produces multiples of 3, option C has difference 2, and option D has difference 4, so option A is correct.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Arithmetic Progression.
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