How many terms are there up to (41) in the arithmetic progression (5,9,13,\ldots)?
Answer and explanation
Correct answer: 10
Here, the first term is 5 and the common difference is 4. Using \(a_n=a+(n-1)d\), we get \(41=5+(n-1)\times4\). Thus, \(n-1=9\), so \(n=10\). Option 9 is incorrect because 37 is the ninth term. Exam tip: To find the number of terms up to a given last term, equate that term to \(a_n\) and solve for \(n\).
Frequently asked questions
What is the correct answer to this question?
10
Why is this the correct answer?
Here, the first term is 5 and the common difference is 4. Using \(a_n=a+(n-1)d\), we get \(41=5+(n-1)\times4\). Thus, \(n-1=9\), so \(n=10\). Option 9 is incorrect because 37 is the ninth term. Exam tip: To find the number of terms up to a given last term, equate that term to \(a_n\) and solve for \(n\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Arithmetic Progression.
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