In the arithmetic progression (5,14,23,32,\ldots), which term is (95)?
Answer and explanation
Correct answer: eleventh term
Here, the first term is \(a=5\) and the common difference is \(d=9\). The \(n\)th term is \(a_n=a+(n-1)d\). So, \(5+(n-1)\times9=95\) gives \((n-1)\times9=90\), hence \(n=11\). Therefore, 95 is the eleventh term. The tenth term is 86, so it is not correct. Exam tip: when asked for a term number, equate \(a_n\) to the given term and solve for \(n\).
Frequently asked questions
What is the correct answer to this question?
eleventh term
Why is this the correct answer?
Here, the first term is \(a=5\) and the common difference is \(d=9\). The \(n\)th term is \(a_n=a+(n-1)d\). So, \(5+(n-1)\times9=95\) gives \((n-1)\times9=90\), hence \(n=11\). Therefore, 95 is the eleventh term. The tenth term is 86, so it is not correct. Exam tip: when asked for a term number, equate \(a_n\) to the given term and solve for \(n\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Arithmetic Progression.
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