What is the value of (a_8+a_{12}) for the arithmetic progression (16,22,28,\ldots)?
Answer and explanation
Correct answer: 132
Here, the first term is 16 and the common difference is 6. Thus, \(a_8=16+(8-1)\times6=58\) and \(a_{12}=16+(12-1)\times6=82\). Therefore, \(a_8+a_{12}=58+82=140\), which is not among the given options. The question or options contain an error, so no option is correct. Exam tip: In \(a_n=a+(n-1)d\), be sure to use \(n-1\).
Frequently asked questions
What is the correct answer to this question?
132
Why is this the correct answer?
Here, the first term is 16 and the common difference is 6. Thus, \(a_8=16+(8-1)\times6=58\) and \(a_{12}=16+(12-1)\times6=82\). Therefore, \(a_8+a_{12}=58+82=140\), which is not among the given options. The question or options contain an error, so no option is correct. Exam tip: In \(a_n=a+(n-1)d\), be sure to use \(n-1\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Arithmetic Progression.
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