In the arithmetic progression (4,10,16,22,\ldots), which term is (70)?
Answer and explanation
Correct answer: 12th term
Here, the first term is \(a=4\) and the common difference is \(d=6\). The \(n\)th term is \(a_n=a+(n-1)d\). So, \(4+(n-1)6=70\) gives \(6(n-1)=66\), hence \(n=12\). Therefore, 70 is the twelfth term. The eleventh term is \(64\), so it is not correct. Exam tip: when asked for a term number, equate \(a_n\) to the given term and solve for \(n\).
Frequently asked questions
What is the correct answer to this question?
12th term
Why is this the correct answer?
Here, the first term is \(a=4\) and the common difference is \(d=6\). The \(n\)th term is \(a_n=a+(n-1)d\). So, \(4+(n-1)6=70\) gives \(6(n-1)=66\), hence \(n=12\). Therefore, 70 is the twelfth term. The eleventh term is \(64\), so it is not correct. Exam tip: when asked for a term number, equate \(a_n\) to the given term and solve for \(n\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Arithmetic Progression.
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