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Class 9MathematicsSequences and ProgressionsArithmetic ProgressionHardLevel 53
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What is the sum of the first (14) terms of the arithmetic progression (6,13,20,27,\ldots)?

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Answer and explanation

Correct answer: (722)

(S_{14}=\frac{14}{2}[12+13\times7]=721). In exams, calculate the bracket and multiplication carefully.

Related tags

SequencesProgressionsArithmetic-ProgressionClass-9Hard

Frequently asked questions

What is the correct answer to this question?

(722)

Why is this the correct answer?

(S_{14}=\frac{14}{2}[12+13\times7]=721). In exams, calculate the bracket and multiplication carefully.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Arithmetic Progression.

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  1. 1How can B={1,4,7,10,13} be written in set-builder form?
  2. 2What is the common difference in the sequence 11, 16, 21, 26, ...?
  3. 3In the sequence (5, 12, 19, 26, ...), how many terms are greater than 50 and less than 150?
  4. 4In the sequence 5, 10, 20, 40, ..., which term is 5120?
  5. 5In an arithmetic sequence, a_1=8 and a_4=20. What is its explicit rule?
  6. 6What is the common difference in the sequence (2,5,8,11,\ldots)?
  7. 7What will be the next term of the sequence (7,12,17,22,\ldots)?
  8. 8If an arithmetic progression has first term (4) and common difference (6), what is the second term?
  9. 9What is the common difference in the sequence (15,11,7,3,\ldots)?
  10. 10Is the sequence (3,6,9,12,\ldots) an arithmetic progression?
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