Which term of the arithmetic progression (19,26,33,\ldots) is (89)?
Answer and explanation
Correct answer: Eleventh term
Here, the first term is \(a=19\) and the common difference is \(d=26-19=7\). The \(n\)th term of an AP is \(a_n=a+(n-1)d\). Thus, \(89=19+(n-1)\times7\), so \(70=7(n-1)\), giving \(n=11\). Therefore, 89 is the eleventh term. The tenth term is \(19+9\times7=82\), so it is not correct. Exam tip: identify \(a\) and \(d\) first, then equate the given value to \(a_n\).
Frequently asked questions
What is the correct answer to this question?
Eleventh term
Why is this the correct answer?
Here, the first term is \(a=19\) and the common difference is \(d=26-19=7\). The \(n\)th term of an AP is \(a_n=a+(n-1)d\). Thus, \(89=19+(n-1)\times7\), so \(70=7(n-1)\), giving \(n=11\). Therefore, 89 is the eleventh term. The tenth term is \(19+9\times7=82\), so it is not correct. Exam tip: identify \(a\) and \(d\) first, then equate the given value to \(a_n\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Arithmetic Progression.
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