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Mathematics General chapter practice MCQ Questions for Class 9

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General chapter practice Practice Questions

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\(\sqrt{a^2}\) का मान (a) कब होगा?

When will \(\sqrt{a^2}\) be equal to (a)?

Explanation opens after your attempt
Correct Answer

B. जब \(a\ge0\)When \(a\ge0\)

Step 1

Concept

\(\sqrt{a^2}=|a|\). It equals (a) only when \(a\ge0\).

Step 2

Why this answer is correct

The correct answer is B. जब \(a\ge0\) / When \(a\ge0\). \(\sqrt{a^2}=|a|\). It equals (a) only when \(a\ge0\).

Step 3

Exam Tip

\(\sqrt{a^2}=|a|\) होता है। यह (a) के बराबर तभी है जब \(a\ge0\)।

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कौन-सा विकल्प (1.272727...) का सही प्रकार बताता है?

Which option correctly describes (1.272727...)?

Explanation opens after your attempt
Correct Answer

A. परिमेय संख्याRational number

Step 1

Concept

The block (27) repeats in the decimal, so it is recurring. Every recurring decimal is rational.

Step 2

Why this answer is correct

The correct answer is A. परिमेय संख्या / Rational number. The block (27) repeats in the decimal, so it is recurring. Every recurring decimal is rational.

Step 3

Exam Tip

दशमलव में (27) बार-बार दोहर रहा है, इसलिए यह आवर्ती दशमलव है। हर आवर्ती दशमलव परिमेय होता है।

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\(\sqrt{27}+\sqrt{12}-\sqrt{3}\) का सरलतम रूप क्या है?

What is the simplest form of \(\sqrt{27}+\sqrt{12}-\sqrt{3}\)?

Explanation opens after your attempt
Correct Answer

A. \(4\sqrt{3}\)

Step 1

Concept

\(\sqrt{27}=3\sqrt{3}\) and \(\sqrt{12}=2\sqrt{3}\). So \(3\sqrt{3}+2\sqrt{3}-\sqrt{3}=4\sqrt{3}\).

Step 2

Why this answer is correct

The correct answer is A. \(4\sqrt{3}\). \(\sqrt{27}=3\sqrt{3}\) and \(\sqrt{12}=2\sqrt{3}\). So \(3\sqrt{3}+2\sqrt{3}-\sqrt{3}=4\sqrt{3}\).

Step 3

Exam Tip

\(\sqrt{27}=3\sqrt{3}\) और \(\sqrt{12}=2\sqrt{3}\)। इसलिए \(3\sqrt{3}+2\sqrt{3}-\sqrt{3}=4\sqrt{3}\)।

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यदि \(\sqrt{x}\) अपरिमेय है और (5) परिमेय है, तो \(5\sqrt{x}\) सामान्यतः किस प्रकार की संख्या होगी, जब \(5\ne0\)?

If \(\sqrt{x}\) is irrational and (5) is rational, what type of number will \(5\sqrt{x}\) generally be when \(5\ne0\)?

Explanation opens after your attempt
Correct Answer

B. अपरिमेयIrrational

Step 1

Concept

The product of a non-zero rational number and an irrational number remains irrational. This property is often tested in options.

Step 2

Why this answer is correct

The correct answer is B. अपरिमेय / Irrational. The product of a non-zero rational number and an irrational number remains irrational. This property is often tested in options.

Step 3

Exam Tip

शून्येतर परिमेय संख्या से अपरिमेय संख्या का गुणनफल अपरिमेय रहता है। यह गुण अक्सर विकल्पों में पूछा जाता है।

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\(\sqrt{2}\) को संख्या रेखा पर बनाने में कौन-सा निर्माण सही है?

Which construction is correct for representing \(\sqrt{2}\) on the number line?

Explanation opens after your attempt
Correct Answer

A. (1) और (1) भुजाओं वाला समकोण त्रिभुज बनाकर कर्ण लेनाMake a right triangle with sides (1) and (1), then take the hypotenuse

Step 1

Concept

\(1^2+1^2=2\), so the hypotenuse is \(\sqrt{2}\). Transfer that hypotenuse length to the number line.

Step 2

Why this answer is correct

The correct answer is A. (1) और (1) भुजाओं वाला समकोण त्रिभुज बनाकर कर्ण लेना / Make a right triangle with sides (1) and (1), then take the hypotenuse. \(1^2+1^2=2\), so the hypotenuse is \(\sqrt{2}\). Transfer that hypotenuse length to the number line.

Step 3

Exam Tip

\(1^2+1^2=2\), इसलिए कर्ण \(\sqrt{2}\) होगा। संख्या रेखा पर वही कर्ण लंबाई स्थानांतरित करें।

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कौन-सा विकल्प \(\sqrt{64}\) और \(\sqrt{65}\) के बारे में सही है?

Which option is correct about \(\sqrt{64}\) and \(\sqrt{65}\)?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{64}=8\) और \(\sqrt{65}\) (8) और (9) के बीच है\(\sqrt{64}=8\) and \(\sqrt{65}\) lies between (8) and (9)

Step 1

Concept

\(64=8^2\) and \(8^2<65<9^2\). Therefore the first statement is correct.

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{64}=8\) और \(\sqrt{65}\) (8) और (9) के बीच है / \(\sqrt{64}=8\) and \(\sqrt{65}\) lies between (8) and (9). \(64=8^2\) and \(8^2<65<9^2\). Therefore the first statement is correct.

Step 3

Exam Tip

\(64=8^2\) और \(8^2<65<9^2\) है। इसलिए पहला कथन सही है।

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\(\frac{2}{7}\) और (0.285714285714...) के संबंध में कौन-सा कथन सही है?

Which statement is correct about \(\frac{2}{7}\) and (0.285714285714...)?

Explanation opens after your attempt
Correct Answer

C. दशमलव आवर्ती है और \(\frac{2}{7}\) के बराबर हैThe decimal is recurring and equal to \(\frac{2}{7}\)

Step 1

Concept

The block (0.285714) repeats and it is the decimal form of \(\frac{2}{7}\). A recurring decimal is rational.

Step 2

Why this answer is correct

The correct answer is C. दशमलव आवर्ती है और \(\frac{2}{7}\) के बराबर है / The decimal is recurring and equal to \(\frac{2}{7}\). The block (0.285714) repeats and it is the decimal form of \(\frac{2}{7}\). A recurring decimal is rational.

Step 3

Exam Tip

(0.285714) का ब्लॉक दोहरता है और यह \(\frac{2}{7}\) का दशमलव रूप है। आवर्ती दशमलव परिमेय होता है।

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\(\sqrt{32}+\sqrt{18}\) का सरलतम रूप क्या है?

What is the simplest form of \(\sqrt{32}+\sqrt{18}\)?

Explanation opens after your attempt
Correct Answer

B. \(7\sqrt{2}\)

Step 1

Concept

\(\sqrt{32}=4\sqrt{2}\) and \(\sqrt{18}=3\sqrt{2}\). The sum is \(7\sqrt{2}\).

Step 2

Why this answer is correct

The correct answer is B. \(7\sqrt{2}\). \(\sqrt{32}=4\sqrt{2}\) and \(\sqrt{18}=3\sqrt{2}\). The sum is \(7\sqrt{2}\).

Step 3

Exam Tip

\(\sqrt{32}=4\sqrt{2}\) और \(\sqrt{18}=3\sqrt{2}\)। योग \(7\sqrt{2}\) है।

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कौन-सी संख्या (3) और (4) के बीच स्थित है?

Which number lies between (3) and (4)?

Explanation opens after your attempt
Correct Answer

B. \(\sqrt{10}\)

Step 1

Concept

\(3^2<10<4^2\), so \(\sqrt{10}\) lies between (3) and (4). Comparing squares is the fastest method.

Step 2

Why this answer is correct

The correct answer is B. \(\sqrt{10}\). \(3^2<10<4^2\), so \(\sqrt{10}\) lies between (3) and (4). Comparing squares is the fastest method.

Step 3

Exam Tip

\(3^2<10<4^2\), इसलिए \(\sqrt{10}\) (3) और (4) के बीच है। वर्गों की तुलना सबसे तेज तरीका है।

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\(\sqrt{a}+\sqrt{b}=\sqrt{a+b}\) कब सामान्य रूप से सही नहीं माना जा सकता?

When can \(\sqrt{a}+\sqrt{b}=\sqrt{a+b}\) generally not be considered true?

Explanation opens after your attempt
Correct Answer

B. यह सामान्य रूप से सही नियम नहीं हैIt is not a generally true rule

Step 1

Concept

Numbers inside roots are not added directly when adding square roots. For example, \(\sqrt{4}+\sqrt{9}\ne\sqrt{13}\).

Step 2

Why this answer is correct

The correct answer is B. यह सामान्य रूप से सही नियम नहीं है / It is not a generally true rule. Numbers inside roots are not added directly when adding square roots. For example, \(\sqrt{4}+\sqrt{9}\ne\sqrt{13}\).

Step 3

Exam Tip

वर्गमूलों को जोड़ने में अंदर की संख्याएँ सीधे नहीं जोड़ी जातीं। जैसे \(\sqrt{4}+\sqrt{9}\ne\sqrt{13}\)।

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