\( \pi \) is an irrational number and lies on the real number line. Do not treat it as exactly equal to \( \frac{22}{7} \).
Step 2
Why this answer is correct
The correct answer is B. अपरिमेय वास्तविक संख्या / Irrational real number. \( \pi \) is an irrational number and lies on the real number line. Do not treat it as exactly equal to \( \frac{22}{7} \).
Step 3
Exam Tip
\( \pi \) अपरिमेय संख्या है और वास्तविक संख्या रेखा पर स्थित है। इसे \( \frac{22}{7} \) के बिल्कुल बराबर न मानें।
\(5+\sqrt{2}\) is irrational because adding a rational and an irrational gives an irrational. In such questions watch the irrational part.
Step 2
Why this answer is correct
The correct answer is B. अपरिमेय / Irrational. \(5+\sqrt{2}\) is irrational because adding a rational and an irrational gives an irrational. In such questions watch the irrational part.
Step 3
Exam Tip
\(5+\sqrt{2}\) अपरिमेय है क्योंकि परिमेय में अपरिमेय जोड़ने से अपरिमेय मिलता है। ऐसे सवाल में अपरिमेय भाग देखें।
The new hypotenuse is formed from previous \(\sqrt{n}\) and a (1) unit perpendicular. Therefore the previous hypotenuse was \(\sqrt{n}\).
Step 2
Why this answer is correct
The correct answer is A. \(\sqrt{n}\). The new hypotenuse is formed from previous \(\sqrt{n}\) and a (1) unit perpendicular. Therefore the previous hypotenuse was \(\sqrt{n}\).
Step 3
Exam Tip
नया कर्ण पिछले \(\sqrt{n}\) और (1) इकाई लंब से बनता है। इसलिए पिछला कर्ण \(\sqrt{n}\) था।
A. क्योंकि (\(\sqrt{n}\)2+12=n+1)/Because (\(\sqrt{n}\)2+12=n+1)
Step 1
Concept
In Pythagoras theorem the squares of sides are added. Therefore the new hypotenuse is \(\sqrt{n+1}\).
Step 2
Why this answer is correct
The correct answer is A. क्योंकि (\(\sqrt{n}\)2+12=n+1) / Because (\(\sqrt{n}\)2+12=n+1). In Pythagoras theorem the squares of sides are added. Therefore the new hypotenuse is \(\sqrt{n+1}\).
Step 3
Exam Tip
पाइथागोरस प्रमेय में भुजाओं के वर्ग जुड़ते हैं। इसलिए नया कर्ण \(\sqrt{n+1}\) होता है।
A. पिछले कर्ण और (1) इकाई लंब के वर्गों का योग लिया जाता है/The sum of squares of previous hypotenuse and (1) unit perpendicular is taken
Step 1
Concept
Pythagoras theorem uses the sum of squares. Therefore the new hypotenuse becomes \(\sqrt{n+1}\).
Step 2
Why this answer is correct
The correct answer is A. पिछले कर्ण और (1) इकाई लंब के वर्गों का योग लिया जाता है / The sum of squares of previous hypotenuse and (1) unit perpendicular is taken. Pythagoras theorem uses the sum of squares. Therefore the new hypotenuse becomes \(\sqrt{n+1}\).
Step 3
Exam Tip
पाइथागोरस प्रमेय में वर्गों का योग आता है। इसलिए नया कर्ण \(\sqrt{n+1}\) बनता है।
