Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
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If (r=0), what is the degree of (\(r^2-r\)x-3+(r+2)x-2+1)?
B. (2)
(r=0) रखने पर \(x^3\) का गुणांक (0) और \(x^2\) का गुणांक (2) होता है। इसलिए डिग्री (2) है। / Putting (r=0), the coefficient of \(x^3\) is (0) and the coefficient of \(x^2\) is (2). Therefore the degree is (2).
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Which expression is the zero polynomial in (x)?
A. \(0x^5+0x^2+0\)
पहले व्यंजक के सभी पदों के गुणांक (0) हैं। इसलिए यह शून्य बहुपद है। / All terms in the first expression have coefficient (0). Therefore it is the zero polynomial.
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Which option has degree (2) and a negative leading coefficient?
B. \(-4x^2+7x-2\)
\(-4x^2+7x-2\) की डिग्री (2) है और अग्रणी गुणांक (-4) है। दोनों शर्तें इसी में पूरी होती हैं। / \(-4x^2+7x-2\) has degree (2) and leading coefficient (-4). Both conditions are satisfied here.
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Which polynomial is obtained by simplifying (x-2(x+1)-x-3+4)?
B. \(x^2+4\)
(x-2(x+1)=x-3+x-2), फिर \(-x^3\) से \(x^3\) कट जाता है। सरल रूप \(x^2+4\) है। / (x-2(x+1)=x-3+x-2), then \(-x^3\) cancels \(x^3\). The simplified form is \(x^2+4\).
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What is the degree of the simplified form \(x^2+4\)?
C. (2)
\(x^2+4\) में सबसे बड़ी घात (2) है। इसलिए इसकी डिग्री (2) है। / In \(x^2+4\), the highest power is (2). Therefore its degree is (2).
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Which conclusion is correct for \(x^0+\sqrt{3}x^2-\frac{x}{5}\)?
B. यह बहुपद है और डिग्री (2) हैIt is a polynomial and degree is (2)
\(\sqrt{3}\) और \(-\frac{1}{5}\) वास्तविक गुणांक हैं। (x) की घातें (0), (2) और (1) हैं इसलिए डिग्री (2) है। / \(\sqrt{3}\) and \(-\frac{1}{5}\) are real coefficients. The powers of (x) are (0), (2), and (1), so the degree is (2).
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If (s=2), what will be the degree of ((s-2)x-4+(s+1)x-3-5)?
B. (3)
(s=2) रखने पर \(x^4\) का गुणांक (0) और \(x^3\) का गुणांक (3) हो जाता है। इसलिए सबसे बड़ी घात (3) है। / Putting (s=2) makes the coefficient of \(x^4\) equal to (0) and the coefficient of \(x^3\) equal to (3). So the highest power is (3).
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Which form is obtained by simplifying \(x^3+\frac{2x^2}{x}\) for \(x\neq0\)?
A. \(x^3+2x\)
\(x\neq0\) पर \(\frac{2x^2}{x}=2x\) होता है। इसलिए सरल रूप \(x^3+2x\) है। / For \(x\neq0\), \(\frac{2x^2}{x}=2x\). Therefore the simplified form is \(x^3+2x\).
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Which option has degree (3) but the coefficient of \(x^2\) is (0)?
A. \(2x^3+5x-1\)
\(2x^3+5x-1\) में सबसे बड़ी घात (3) है और \(x^2\) पद नहीं है। इसलिए \(x^2\) का गुणांक (0) है। / In \(2x^3+5x-1\), the highest power is (3) and the \(x^2\) term is absent. So the coefficient of \(x^2\) is (0).
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What is obtained by simplifying \(\frac{x^4-x^2}{x^2}\) for \(x\neq0\)?
A. \(x^2-1\)
\(x^2\) से भाग देने पर \(\frac{x^4}{x^2}=x^2\) और \(\frac{x^2}{x^2}=1\) मिलता है। इसलिए सरल रूप \(x^2-1\) है। / Dividing by \(x^2\) gives \(\frac{x^4}{x^2}=x^2\) and \(\frac{x^2}{x^2}=1\). Therefore the simplified form is \(x^2-1\).
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