व्यंजक \(\frac{x^4-x^2}{x^2}\) को \(x\neq0\) पर सरल करने से क्या मिलता है?

What is obtained by simplifying \(\frac{x^4-x^2}{x^2}\) for \(x\neq0\)?

Explanation opens after your attempt
Correct Answer

A. \(x^2-1\)

Step 1

Concept

Dividing by \(x^2\) gives \(\frac{x^4}{x^2}=x^2\) and \(\frac{x^2}{x^2}=1\). Therefore the simplified form is \(x^2-1\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2-1\). Dividing by \(x^2\) gives \(\frac{x^4}{x^2}=x^2\) and \(\frac{x^2}{x^2}=1\). Therefore the simplified form is \(x^2-1\).

Step 3

Exam Tip

\(x^2\) से भाग देने पर \(\frac{x^4}{x^2}=x^2\) और \(\frac{x^2}{x^2}=1\) मिलता है। इसलिए सरल रूप \(x^2-1\) है।

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व्यंजक \(\frac{x^4-x^2}{x^2}\) को \(x\neq0\) पर सरल करने से क्या मिलता है? / What is obtained by simplifying \(\frac{x^4-x^2}{x^2}\) for \(x\neq0\)?

Correct Answer: A. \(x^2-1\). Explanation: \(x^2\) से भाग देने पर \(\frac{x^4}{x^2}=x^2\) और \(\frac{x^2}{x^2}=1\) मिलता है। इसलिए सरल रूप \(x^2-1\) है। / Dividing by \(x^2\) gives \(\frac{x^4}{x^2}=x^2\) and \(\frac{x^2}{x^2}=1\). Therefore the simplified form is \(x^2-1\).

Which concept should I revise for this Mathematics MCQ?

Dividing by \(x^2\) gives \(\frac{x^4}{x^2}=x^2\) and \(\frac{x^2}{x^2}=1\). Therefore the simplified form is \(x^2-1\).

What exam hint can help solve this Mathematics question?

\(x^2\) से भाग देने पर \(\frac{x^4}{x^2}=x^2\) और \(\frac{x^2}{x^2}=1\) मिलता है। इसलिए सरल रूप \(x^2-1\) है।