कौन सा निष्कर्ष \(x^0+\sqrt{3}x^2-\frac{x}{5}\) के लिए सही है?

Which conclusion is correct for \(x^0+\sqrt{3}x^2-\frac{x}{5}\)?

Explanation opens after your attempt
Correct Answer

B. यह बहुपद है और डिग्री (2) हैIt is a polynomial and degree is (2)

Step 1

Concept

\(\sqrt{3}\) and \(-\frac{1}{5}\) are real coefficients. The powers of (x) are (0), (2), and (1), so the degree is (2).

Step 2

Why this answer is correct

The correct answer is B. यह बहुपद है और डिग्री (2) है / It is a polynomial and degree is (2). \(\sqrt{3}\) and \(-\frac{1}{5}\) are real coefficients. The powers of (x) are (0), (2), and (1), so the degree is (2).

Step 3

Exam Tip

\(\sqrt{3}\) और \(-\frac{1}{5}\) वास्तविक गुणांक हैं। (x) की घातें (0), (2) और (1) हैं इसलिए डिग्री (2) है।

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Mathematics Answer, Explanation and Revision Hints

कौन सा निष्कर्ष \(x^0+\sqrt{3}x^2-\frac{x}{5}\) के लिए सही है? / Which conclusion is correct for \(x^0+\sqrt{3}x^2-\frac{x}{5}\)?

Correct Answer: B. यह बहुपद है और डिग्री (2) है / It is a polynomial and degree is (2). Explanation: \(\sqrt{3}\) और \(-\frac{1}{5}\) वास्तविक गुणांक हैं। (x) की घातें (0), (2) और (1) हैं इसलिए डिग्री (2) है। / \(\sqrt{3}\) and \(-\frac{1}{5}\) are real coefficients. The powers of (x) are (0), (2), and (1), so the degree is (2).

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{3}\) and \(-\frac{1}{5}\) are real coefficients. The powers of (x) are (0), (2), and (1), so the degree is (2).

What exam hint can help solve this Mathematics question?

\(\sqrt{3}\) और \(-\frac{1}{5}\) वास्तविक गुणांक हैं। (x) की घातें (0), (2) और (1) हैं इसलिए डिग्री (2) है।