यदि (r=0), तो (\(r^2-r\)x-3+(r+2)x-2+1) की डिग्री क्या है?

If (r=0), what is the degree of (\(r^2-r\)x-3+(r+2)x-2+1)?

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Correct Answer

B. (2)

Step 1

Concept

Putting (r=0), the coefficient of \(x^3\) is (0) and the coefficient of \(x^2\) is (2). Therefore the degree is (2).

Step 2

Why this answer is correct

The correct answer is B. (2). Putting (r=0), the coefficient of \(x^3\) is (0) and the coefficient of \(x^2\) is (2). Therefore the degree is (2).

Step 3

Exam Tip

(r=0) रखने पर \(x^3\) का गुणांक (0) और \(x^2\) का गुणांक (2) होता है। इसलिए डिग्री (2) है।

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Mathematics Answer, Explanation and Revision Hints

यदि (r=0), तो (\(r^2-r\)x-3+(r+2)x-2+1) की डिग्री क्या है? / If (r=0), what is the degree of (\(r^2-r\)x-3+(r+2)x-2+1)?

Correct Answer: B. (2). Explanation: (r=0) रखने पर \(x^3\) का गुणांक (0) और \(x^2\) का गुणांक (2) होता है। इसलिए डिग्री (2) है। / Putting (r=0), the coefficient of \(x^3\) is (0) and the coefficient of \(x^2\) is (2). Therefore the degree is (2).

Which concept should I revise for this Mathematics MCQ?

Putting (r=0), the coefficient of \(x^3\) is (0) and the coefficient of \(x^2\) is (2). Therefore the degree is (2).

What exam hint can help solve this Mathematics question?

(r=0) रखने पर \(x^3\) का गुणांक (0) और \(x^2\) का गुणांक (2) होता है। इसलिए डिग्री (2) है।