Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 391-400 of 591 questions.
What is the solution of (2x-3<5x+12)?
A. (x>-5)
(2x-3<5x+12) से (-15<3x) मिलता है। अतः (x>-5) है। / From (2x-3<5x+12), we get (-15<3x). Hence (x>-5).
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If \(x\in[0,6\)), which value is not included?
C. (x=6)
([0,6)) में (0) शामिल है लेकिन (6) शामिल नहीं है। गोल कोष्ठक खुले सिरे को दिखाता है। / In ([0,6)), (0) is included but (6) is not included. A round bracket shows an open endpoint.
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If (k>0) and \(a\leq b\), which conclusion is correct?
B. \(ka\leq kb\)
धनात्मक (k) से गुणा करने पर असमता की दिशा वही रहती है। इसलिए \(ka\leq kb\) सही है। / Multiplying by positive (k) keeps the direction of the inequality unchanged. Therefore \(ka\leq kb\) is correct.
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What is the solution of \(9-3x\geq 2x-16\)?
A. \(x\leq 5\)
\(9-3x\geq 2x-16\) से \(25\geq 5x\) मिलता है। अतः \(x\leq 5\) है। / From \(9-3x\geq 2x-16\), we get \(25\geq 5x\). Hence \(x\leq 5\).
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Which inequality shows an open circle at (4) and shading to the right?
B. (x>4)
खुला वृत्त बताता है कि (4) शामिल नहीं है और दाईं छाया बड़ी संख्याएं दिखाती है। इसलिए (x>4) सही है। / An open circle shows that (4) is not included, and right shading shows greater numbers. Therefore (x>4) is correct.
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If \(x\in\mathbb{R}\) and \(12<4x\leq 28\), which solution is correct?
A. \(3<x\leq 7\)
(4) से भाग देने पर \(3<x\leq 7\) मिलता है। धनात्मक संख्या से भाग देने पर चिन्ह नहीं बदलता। / Dividing by (4) gives \(3<x\leq 7\). Dividing by a positive number does not change the signs.
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If \(x\in\mathbb{Z}\) and \(\frac{x-2}{3}\leq -1\), what is the greatest possible (x)?
C. (-1)
(3) से गुणा करने पर \(x-2\leq -3\) और \(x\leq -1\) मिलता है। इसलिए सबसे बड़ा पूर्णांक हल (-1) है। / Multiplying by (3) gives \(x-2\leq -3\), so \(x\leq -1\). Therefore the greatest integer solution is (-1).
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What is the solution of (4(x+2)-3(x-5)\geq 20)?
A. \(x\geq -3\)
सरलीकरण से \(4x+8-3x+15\geq 20\) यानी \(x+23\geq 20\) मिलता है। इसलिए \(x\geq -3\) है। / Simplifying gives \(4x+8-3x+15\geq 20\), that is \(x+23\geq 20\). Therefore \(x\geq -3\).
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If (x) is real and (x-2<4) and \(x+5\geq 1\), what is the combined solution?
A. ([-4,6))
पहली असमता से (x<6) और दूसरी से \(x\geq -4\) मिलता है। संयुक्त हल ([-4,6)) है। / The first inequality gives (x<6), and the second gives \(x\geq -4\). The combined solution is ([-4,6)).
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Which inequality has solution (\(-\infty,\infty\)) in \(\mathbb{R}\)?
C. \(7x-4\leq 7x+9\)
\(7x-4\leq 7x+9\) से \(-4\leq 9\) मिलता है जो हमेशा सत्य है। इसलिए हर वास्तविक (x) हल है। / From \(7x-4\leq 7x+9\), we get \(-4\leq 9\), which is always true. Therefore every real (x) is a solution.
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