असमता (4(x+2)-3(x-5)\geq 20) का हल कौन सा है?

What is the solution of (4(x+2)-3(x-5)\geq 20)?

Explanation opens after your attempt
Correct Answer

A. \(x\geq -3\)

Step 1

Concept

Simplifying gives \(4x+8-3x+15\geq 20\), that is \(x+23\geq 20\). Therefore \(x\geq -3\).

Step 2

Why this answer is correct

The correct answer is A. \(x\geq -3\). Simplifying gives \(4x+8-3x+15\geq 20\), that is \(x+23\geq 20\). Therefore \(x\geq -3\).

Step 3

Exam Tip

सरलीकरण से \(4x+8-3x+15\geq 20\) यानी \(x+23\geq 20\) मिलता है। इसलिए \(x\geq -3\) है।

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Mathematics Answer, Explanation and Revision Hints

असमता (4(x+2)-3(x-5)\geq 20) का हल कौन सा है? / What is the solution of (4(x+2)-3(x-5)\geq 20)?

Correct Answer: A. \(x\geq -3\). Explanation: सरलीकरण से \(4x+8-3x+15\geq 20\) यानी \(x+23\geq 20\) मिलता है। इसलिए \(x\geq -3\) है। / Simplifying gives \(4x+8-3x+15\geq 20\), that is \(x+23\geq 20\). Therefore \(x\geq -3\).

Which concept should I revise for this Mathematics MCQ?

Simplifying gives \(4x+8-3x+15\geq 20\), that is \(x+23\geq 20\). Therefore \(x\geq -3\).

What exam hint can help solve this Mathematics question?

सरलीकरण से \(4x+8-3x+15\geq 20\) यानी \(x+23\geq 20\) मिलता है। इसलिए \(x\geq -3\) है।