Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
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On solving (0.2x+0.8y=5.6) and (0.5x-0.3y=2.7), what is (x)?
B. \(x=\frac{192}{23}\)
दशमलव हटाने पर (2x+8y=56) और (5x-3y=27) मिलते हैं। विलोपन से \(x=\frac{192}{23}\)। / Removing decimals gives (2x+8y=56) and (5x-3y=27). Elimination gives \(x=\frac{192}{23}\).
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If (4(x+y)+3(x-y)=62) and (2(x+y)-5(x-y)=-2), what is the value of (y)?
C. \(y=\frac{43}{13}\)
(x+y=s) और (x-y=d) मानकर हल करें। \(x=\frac{109}{13}\) और \(y=\frac{43}{13}\) मिलता है। / Let (x+y=s) and (x-y=d), then solve. This gives \(x=\frac{109}{13}\) and \(y=\frac{43}{13}\).
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If (5x+6y=142) and (6x+5y=144), what is the value of (x-y)?
B. (2)
दूसरे समीकरण से पहला घटाने पर (x-y=2) सीधे मिलता है। ऐसे प्रश्नों में घटाना समय बचाता है। / Subtracting the first equation from the second directly gives (x-y=2). In such questions, subtraction saves time.
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What is the value of (x+y) from (4x-7y=9) and (6x+7y=71)?
D. \(x+y=\frac{79}{7}\)
दोनों समीकरण जोड़ने पर (10x=80), इसलिए (x=8)। फिर \(y=\frac{23}{7}\), अतः \(x+y=\frac{79}{7}\)। / Adding both equations gives (10x=80), so (x=8). Then \(y=\frac{23}{7}\), hence \(x+y=\frac{79}{7}\).
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What is the solution of \(\frac{x}{8}+\frac{y}{4}=5\) and \(\frac{x}{4}-\frac{y}{6}=2\)?
C. (x=16,\ y=12)
हर हटाने पर (x+2y=40) और (3x-2y=24) बनते हैं। जोड़ने पर (x=16) और फिर (y=12)। / After clearing denominators, (x+2y=40) and (3x-2y=24) are obtained. Adding gives (x=16), then (y=12).
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What is the value of (a) for (ax+9y=27) and (2x+3y=9) to have infinitely many solutions?
C. (a=6)
अनंत हल के लिए पहला समीकरण दूसरे का (3) गुना होना चाहिए। इसलिए (a=6)। / For infinitely many solutions, the first equation must be (3) times the second. Therefore (a=6).
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B. (63)
दहाई अंक (x) और इकाई अंक (y) मानें। (10x+y=7(x+y)) और (x-y=3) से संख्या (63) है। / Let the tens digit be (x) and units digit be (y). From (10x+y=7(x+y)) and (x-y=3), the number is (63).
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What is the value of (y) from (11x+4y=91) and (5x-4y=21)?
C. \(y=\frac{7}{2}\)
दोनों समीकरण जोड़ने पर (16x=112), इसलिए (x=7)। पहले समीकरण से \(y=\frac{7}{2}\)। / Adding both equations gives (16x=112), so (x=7). The first equation gives \(y=\frac{7}{2}\).
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If (x=9,\ y=5) is a solution of (4x+ky=55), what is the value of (k)?
C. \(k=\frac{19}{5}\)
(x=9,\ y=5) रखने पर (36+5k=55) मिलता है। इसलिए \(k=\frac{19}{5}\)। / Substituting (x=9,\ y=5) gives (36+5k=55). Therefore \(k=\frac{19}{5}\).
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What is the value of (x) from \(\frac{2x-y}{5}=4\) and \(\frac{x+3y}{4}=8\)?
C. \(x=\frac{92}{7}\)
दिए समीकरण (2x-y=20) और (x+3y=32) बनते हैं। प्रतिस्थापन से \(x=\frac{92}{7}\)। / The equations become (2x-y=20) and (x+3y=32). Substitution gives \(x=\frac{92}{7}\).
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