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A two-digit number is 7 times the sum of its digits, and the tens digit is 3 more than the units digit. What is the number?

Answer and explanation

Correct answer: 63

The key concept is translating place value and digit conditions into a pair of linear equations. Let the tens digit be x and the units digit be y. Then the two-digit number is 10x + y, while the sum of its digits is x + y. The conditions give x = y + 3 and 10x + y = 7(x + y). Expanding the second equation gives 10x + y = 7x + 7y, so 3x = 6y and x = 2y. Substituting into x = y + 3 gives 2y = y + 3, hence y = 3 and x = 6. The number is therefore 10(6) + 3 = 63, so option B is correct. Checking confirms that its digit sum is 9 and 7 × 9 = 63. The other choices fail at least one of the two stated conditions.

Related tags

Linear EquationsWord ProblemDigitsPlace ValueAlgebraic Methods: Substitution Method And Elimination Method.Algebraic Methods Substitution Method And Elimination MethodPair Of Linear Equations In Two VariablesMathematics

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