Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 271-280 of 600 questions.
Which is the solution of (4x+5y=39) and (2x-y=9)?
A. (x=6,\ y=3)
दूसरे समीकरण से (y=2x-9) रखें। पहले में रखने पर (14x=84), इसलिए (x=6,\ y=3)। / Use (y=2x-9) from the second equation. Substitution gives (14x=84), so (x=6,\ y=3).
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If (2x+y=23) and (x+3y=19), what is the value of (x-2y)?
D. (4)
पहले समीकरण से (y=23-2x) रखें। दूसरे में रखने पर (x=10,\ y=3), इसलिए (x-2y=4)। / Use (y=23-2x) from the first equation. Substitution gives (x=10,\ y=3), so (x-2y=4).
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The sum of two numbers is (29) and their difference is (7). What is the larger number?
C. (18)
मान लें बड़ी संख्या (x) और छोटी (y) है। (x+y=29) और (x-y=7) जोड़ने पर (2x=36), इसलिए (x=18)। / Let the larger number be (x) and the smaller be (y). Adding (x+y=29) and (x-y=7) gives (2x=36), so (x=18).
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If (x=2y+1) and (5x-3y=33), which is the correct solution?
B. (x=9,\ y=4)
(x=2y+1) रखने पर (10y+5-3y=33) मिलता है। इससे (y=4) और (x=9)। / Substituting (x=2y+1) gives (10y+5-3y=33). This gives (y=4) and (x=9).
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What is the value of (y) from (8x-5y=29) and (3x+5y=26)?
D. \(y=\frac{11}{5}\)
दोनों समीकरण जोड़ने पर (11x=55), इसलिए (x=5)। दूसरे समीकरण से (15+5y=26), अतः \(y=\frac{11}{5}\)। / Adding both equations gives (11x=55), so (x=5). From the second equation (15+5y=26), hence \(y=\frac{11}{5}\).
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If (3x+my=23) and (x-y=1) have solution (x=5,\ y=4), what is the value of (m)?
A. (m=2)
(x=5,\ y=4) को (3x+my=23) में रखें। (15+4m=23), इसलिए (m=2)। / Put (x=5,\ y=4) in (3x+my=23). Then (15+4m=23), so (m=2).
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What is the number of solutions of (5x-10y=15) and (x-2y=3)?
D. अनंत हलInfinitely many solutions
पहला समीकरण दूसरे का (5) गुना है। इसलिए दोनों एक ही समीकरण हैं और अनंत हल हैं। / The first equation is (5) times the second. Therefore both are the same equation and have infinitely many solutions.
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If (6x-9y=12) and (2x-3y=5), which statement is correct?
B. कोई हल नहीं हैThere is no solution
पहला समीकरण (2x-3y=4) बनता है, लेकिन दूसरा (2x-3y=5) है। इसलिए कोई हल नहीं है। / The first equation becomes (2x-3y=4), but the second is (2x-3y=5). Therefore there is no solution.
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The sum of two numbers is (64) and the difference is (18). What is the smaller number?
C. (23)
मान लें बड़ी संख्या (x) और छोटी (y) है। (x+y=64) और (x-y=18) से (2y=46), इसलिए (y=23)। / Let the larger number be (x) and the smaller be (y). From (x+y=64) and (x-y=18), (2y=46), so (y=23).
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What is the solution of \(\frac{x}{2}+\frac{y}{3}=5\) and (x-y=3)?
A. \(x=\frac{36}{5},\ y=\frac{21}{5}\)
पहले समीकरण को (6) से गुणा करने पर (3x+2y=30) मिलता है। (x=y+3) रखने पर \(y=\frac{21}{5}\) और \(x=\frac{36}{5}\)। / Multiplying the first equation by (6) gives (3x+2y=30). Using (x=y+3) gives \(y=\frac{21}{5}\) and \(x=\frac{36}{5}\).
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