किस मान पर (p(x)=(c-7)x+8c) का शून्यक (-4) होगा?
For which value will the zero of (p(x)=(c-7)x+8c) be (-4)?
#polynomial
#linear
#parameter_zero
A (c=-7)
B (c=7)
C (c=1)
D कोई मान नहीं / No value
Explanation opens after your attempt
Explanation
Simple Explanation
(-4(c-7)+8c=0) से (4c+28=0) मिलता है। इसलिए (c=-7) है। / From (-4(c-7)+8c=0), we get (4c+28=0). Therefore (c=-7).
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किस मान पर ((n+6)x+4n-3) का शून्यक (1) होगा?
For which value will the zero of ((n+6)x+4n-3) be (1)?
#polynomial
#linear
#parameter_zero
A \(n=-\frac{3}{5}\)
B (n=1)
C (n=-1)
D (n=6)
Explanation opens after your attempt
Correct Answer
A. \(n=-\frac{3}{5}\)
Explanation
Simple Explanation
शून्यक (1) होने पर (n+6+4n-3=0) होगा। इससे (5n+3=0) और \(n=-\frac{3}{5}\) मिलता है। / If the zero is (1), then (n+6+4n-3=0). Thus (5n+3=0) and \(n=-\frac{3}{5}\).
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किस मान पर ((4a-5)x+30) का शून्यक (-2) होगा?
For which value will the zero of ((4a-5)x+30) be (-2)?
#polynomial
#linear
#parameter_zero
A (a=5)
B (a=4)
C (a=0)
D \(a=\frac{5}{4}\)
Explanation opens after your attempt
Explanation
Simple Explanation
शून्यक (-2) होने पर (-2(4a-5)+30=0) होगा। इससे (a=5) मिलता है। / If the zero is (-2), then (-2(4a-5)+30=0). This gives (a=5).
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किस मान पर (p(x)=(c-5)x+6c) का शून्यक (-3) होगा?
For which value will the zero of (p(x)=(c-5)x+6c) be (-3)?
#polynomial
#linear
#parameter_zero
A (c=-5)
B (c=5)
C (c=1)
D कोई मान नहीं / No value
Explanation opens after your attempt
Explanation
Simple Explanation
(-3(c-5)+6c=0) से (3c+15=0) मिलता है। इसलिए (c=-5) है। / From (-3(c-5)+6c=0), we get (3c+15=0). Therefore (c=-5).
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किस मान पर ((n-5)x+3n+2) का शून्यक (1) होगा?
For which value will the zero of ((n-5)x+3n+2) be (1)?
#polynomial
#linear
#parameter_zero
A \(n=\frac{3}{4}\)
B (n=1)
C (n=-1)
D (n=5)
Explanation opens after your attempt
Correct Answer
A. \(n=\frac{3}{4}\)
Explanation
Simple Explanation
शून्यक (1) होने पर (n-5+3n+2=0) होगा। इससे (4n-3=0) और \(n=\frac{3}{4}\) मिलता है। / If the zero is (1), then (n-5+3n+2=0). Thus (4n-3=0) and \(n=\frac{3}{4}\).
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किस मान पर ((3a-4)x+16) का शून्यक (-2) होगा?
For which value will the zero of ((3a-4)x+16) be (-2)?
#polynomial
#linear
#parameter_zero
A (a=4)
B (a=-4)
C (a=2)
D (a=0)
Explanation opens after your attempt
Explanation
Simple Explanation
शून्यक (-2) होने पर (-2(3a-4)+16=0) होगा। इससे (a=4) मिलता है। / If the zero is (-2), then (-2(3a-4)+16=0). This gives (a=4).
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किस मान पर (p(x)=(c-3)x+4c) का शून्यक (-2) होगा?
For which value will the zero of (p(x)=(c-3)x+4c) be (-2)?
#polynomial
#linear
#parameter_zero
A (c=-3)
B (c=3)
C (c=1)
D कोई मान नहीं / No value
Explanation opens after your attempt
Explanation
Simple Explanation
(-2(c-3)+4c=0) से (2c+6=0) मिलता है। इसलिए (c=-3) है। / From (-2(c-3)+4c=0), we get (2c+6=0). Therefore (c=-3).
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किस मान पर ((n+4)x+2n-1) का शून्यक (1) होगा?
For which value will the zero of ((n+4)x+2n-1) be (1)?
#polynomial
#linear
#parameter_zero
A (n=-1)
B (n=1)
C \(n=-\frac{1}{3}\)
D (n=4)
Explanation opens after your attempt
Explanation
Simple Explanation
शून्यक (1) होने पर (n+4+2n-1=0) होगा। इससे (3n+3=0) और (n=-1) मिलता है। / If the zero is (1), then (n+4+2n-1=0). Thus (3n+3=0) and (n=-1).
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किस मान पर ((2a-3)x-9) का शून्यक (3) होगा?
For which value will the zero of ((2a-3)x-9) be (3)?
#polynomial
#linear
#parameter_zero
A (a=1)
B (a=3)
C (a=0)
D \(a=\frac{1}{2}\)
Explanation opens after your attempt
Explanation
Simple Explanation
शून्यक (3) होने पर (3(2a-3)-9=0) होगा। इससे (a=3) मिलता है। / If the zero is (3), then (3(2a-3)-9=0). This gives (a=3).
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यदि (p(x)=(c+4)x+2c) का शून्यक (-1) है, तो (c) का सही मान क्या है?
If the zero of (p(x)=(c+4)x+2c) is (-1), what is the correct value of (c)?
#polynomial
#linear
#parameter_zero
A (c=4)
B (c=-4)
C (c=1)
D (c=2)
Explanation opens after your attempt
Explanation
Simple Explanation
(-(c+4)+2c=0) से (c-4=0) मिलता है। अतः (c=4) है। / From (-(c+4)+2c=0), we get (c-4=0). Hence (c=4).
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किस मान पर ((n-3)x+2n+1) का शून्यक (1) होगा?
For which value will the zero of ((n-3)x+2n+1) be (1)?
#polynomial
#linear
#parameter_zero
A \(n=\frac{2}{3}\)
B (n=1)
C (n=-1)
D (n=3)
Explanation opens after your attempt
Correct Answer
A. \(n=\frac{2}{3}\)
Explanation
Simple Explanation
शून्यक (1) होने पर (n-3+2n+1=0) होगा। इससे (3n-2=0) और \(n=\frac{2}{3}\) मिलता है। / If the zero is (1), then (n-3+2n+1=0). Thus (3n-2=0) and \(n=\frac{2}{3}\).
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किस मान पर ((2m+3)x-14) का शून्यक (2) होगा?
For which value will the zero of ((2m+3)x-14) be (2)?
#polynomial
#linear
#parameter_zero
A (m=2)
B \(m=\frac{7}{2}\)
C (m=7)
D \(m=\frac{1}{2}\)
Explanation opens after your attempt
Explanation
Simple Explanation
शून्यक (2) होने पर (2(2m+3)-14=0) होगा। इससे (m=2) मिलता है। / If the zero is (2), then (2(2m+3)-14=0). This gives (m=2).
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यदि (p(x)=(c-2)x+3c) का शून्यक (-2) है, तो (c) का सही मान क्या है?
If the zero of (p(x)=(c-2)x+3c) is (-2), what is the correct value of (c)?
#polynomial
#linear
#parameter_zero
A (c=4)
B (c=-4)
C (c=1)
D (c=2)
Explanation opens after your attempt
Explanation
Simple Explanation
(-2(c-2)+3c=0) से (c+4=0) मिलता है। अतः (c=-4) है। / From (-2(c-2)+3c=0), we get (c+4=0). Hence (c=-4).
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किस मान पर ((n+2)x+3n-1) का शून्यक (1) होगा?
For which value will the zero of ((n+2)x+3n-1) be (1)?
#polynomial
#linear
#parameter_zero
A \(n=-\frac{1}{4}\)
B (n=1)
C (n=-1)
D (n=2)
Explanation opens after your attempt
Correct Answer
A. \(n=-\frac{1}{4}\)
Explanation
Simple Explanation
शून्यक (1) होने पर (n+2+3n-1=0) होगा। इससे (4n+1=0) और \(n=-\frac{1}{4}\) मिलता है। / If the zero is (1), then (n+2+3n-1=0). Thus (4n+1=0) and \(n=-\frac{1}{4}\).
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किस मान पर ((3m+1)x+8) का शून्यक (-2) होगा?
For which value will the zero of ((3m+1)x+8) be (-2)?
#polynomial
#linear
#parameter_zero
A (m=1)
B \(m=\frac{1}{3}\)
C (m=-1)
D (m=2)
Explanation opens after your attempt
Explanation
Simple Explanation
शून्यक (-2) होने पर (-2(3m+1)+8=0) होगा। इससे (m=1) मिलता है। / If the zero is (-2), then (-2(3m+1)+8=0). This gives (m=1).
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यदि (p(x)=(c+1)x+2c) का शून्यक (-4) है, तो (c) का सही मान क्या है?
If the zero of (p(x)=(c+1)x+2c) is (-4), what is the correct value of (c)?
#polynomial
#linear
#parameter_zero
A (c=1)
B (c=2)
C (c=-2)
D (c=-1)
Explanation opens after your attempt
Explanation
Simple Explanation
(-4(c+1)+2c=0) से (-2c-4=0) मिलता है। अतः (c=-2) है। / From (-4(c+1)+2c=0), we get (-2c-4=0). Hence (c=-2).
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किस मान पर (p(x)=(c+1)x+2c) का शून्यक (-4) होगा?
For which value will the zero of (p(x)=(c+1)x+2c) be (-4)?
#polynomial
#linear
#parameter_zero
A (c=1)
B (c=2)
C (c=-2)
D (c=-1)
Explanation opens after your attempt
Explanation
Simple Explanation
(-4(c+1)+2c=0) से (-2c-4=0) मिलता है। इसलिए (c=-2) होना चाहिए। / From (-4(c+1)+2c=0), we get (-2c-4=0). Therefore (c=-2) is required.
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किस मान पर ((n-1)x+n+2) का शून्यक (1) होगा?
For which value will the zero of ((n-1)x+n+2) be (1)?
#polynomial
#linear
#parameter_zero
A \(n=-\frac{1}{2}\)
B (n=1)
C (n=-1)
D (n=2)
Explanation opens after your attempt
Correct Answer
A. \(n=-\frac{1}{2}\)
Explanation
Simple Explanation
शून्यक (1) होने पर (n-1+n+2=0) होगा। इससे (2n+1=0) और \(n=-\frac{1}{2}\) मिलता है। / If the zero is (1), then (n-1+n+2=0). Thus (2n+1=0) and \(n=-\frac{1}{2}\).
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यदि (p(x)=x+a) और (p(-9)=0), तो (a) क्या है?
If (p(x)=x+a) and (p(-9)=0), what is (a)?
#polynomial
#linear
#parameter_zero
A (9)
B (-9)
C (0)
D (1)
Explanation opens after your attempt
Explanation
Simple Explanation
(-9+a=0) से (a=9) मिलता है। शून्यक को बहुपद में रखकर हल करें। / From (-9+a=0), we get (a=9). Substitute the zero into the polynomial and solve.
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यदि (p(x)=4x+a) का शून्यक (-5) है, तो (a) का मान क्या है?
If the zero of (p(x)=4x+a) is (-5), what is the value of (a)?
#polynomial
#linear
#parameter_zero
A (20)
B (-20)
C (5)
D (-5)
Explanation opens after your attempt
Explanation
Simple Explanation
शून्यक (-5) होने से (4(-5)+a=0) होगा। इसलिए (a=20) है। / Since the zero is (-5), (4(-5)+a=0). Therefore (a=20).
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किस मान पर ((k+2)x-12) का शून्यक (3) होगा?
For which value will the zero of ((k+2)x-12) be (3)?
#polynomial
#linear
#parameter_zero
A (k=2)
B (k=4)
C (k=6)
D (k=10)
Explanation opens after your attempt
Explanation
Simple Explanation
शून्यक (3) होने पर (3(k+2)-12=0) होगा। इससे (k=2) मिलता है। / If the zero is (3), then (3(k+2)-12=0). This gives (k=2).
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यदि (p(x)=x+a) और (p(6)=0), तो (a) क्या है?
If (p(x)=x+a) and (p(6)=0), what is (a)?
#polynomial
#linear
#parameter_zero
A (6)
B (-6)
C (0)
D (1)
Explanation opens after your attempt
Explanation
Simple Explanation
(6+a=0) से (a=-6) मिलता है। शून्यक को बहुपद में रखकर हल करें। / From (6+a=0), we get (a=-6). Substitute the zero into the polynomial and solve.
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यदि (p(x)=3x+a) का शून्यक (-2) है, तो (a) का मान क्या है?
If the zero of (p(x)=3x+a) is (-2), what is the value of (a)?
#polynomial
#linear
#parameter_zero
A (6)
B (-6)
C (3)
D (-3)
Explanation opens after your attempt
Explanation
Simple Explanation
शून्यक (-2) होने से (3(-2)+a=0) होगा। इसलिए (a=6) है। / Since the zero is (-2), (3(-2)+a=0). Therefore (a=6).
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किस मान पर ((k-7)x+14) का शून्यक (-2) होगा?
For which value will the zero of ((k-7)x+14) be (-2)?
#polynomial
#linear
#parameter_zero
A (k=0)
B (k=7)
C (k=14)
D (k=21)
Explanation opens after your attempt
Explanation
Simple Explanation
शून्यक (-2) होने पर (-2(k-7)+14=0) होगा। इससे (k=14) मिलता है। / If the zero is (-2), then (-2(k-7)+14=0). This gives (k=14).
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यदि (p(x)=x+a) और (p(-5)=0), तो (a) क्या है?
If (p(x)=x+a) and (p(-5)=0), what is (a)?
#polynomial
#linear
#parameter_zero
A (5)
B (-5)
C (0)
D (1)
Explanation opens after your attempt
Explanation
Simple Explanation
(-5+a=0) से (a=5) मिलता है। शून्यक को बहुपद में रखकर हल करें। / From (-5+a=0), we get (a=5). Substitute the zero into the polynomial and solve.
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यदि (p(x)=2x+a) का शून्यक (-3) है, तो (a) का मान क्या है?
If the zero of (p(x)=2x+a) is (-3), what is the value of (a)?
#polynomial
#linear
#parameter_zero
A (6)
B (-6)
C (3)
D (-3)
Explanation opens after your attempt
Explanation
Simple Explanation
शून्यक (-3) होने से (2(-3)+a=0) होगा। इसलिए (a=6) है। / Since the zero is (-3), (2(-3)+a=0). Therefore (a=6).
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किस मान पर ((k+5)x-11) का शून्यक (1) होगा?
For which value will the zero of ((k+5)x-11) be (1)?
#polynomial
#linear
#parameter_zero
A (k=6)
B (k=11)
C (k=-5)
D (k=16)
Explanation opens after your attempt
Explanation
Simple Explanation
शून्यक (1) होने पर (k+5-11=0) होगा। इससे (k=6) मिलता है। / If the zero is (1), then (k+5-11=0). This gives (k=6).
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यदि (b=3), तो ((b-3)x^{12}+2x-5 -9) की डिग्री क्या होगी?
If (b=3), what will be the degree of ((b-3)x^{12}+2x-5 -9)?
#polynomial
#parameter_zero
#degree
A (12)
B (3)
C (5)
D (0)
Explanation opens after your attempt
Explanation
Simple Explanation
(b=3) होने पर \(x^{12}\) पद हट जाता है। बची हुई सबसे बड़ी घात (5) है। / When (b=3), the \(x^{12}\) term disappears. The remaining highest power is (5).
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यदि (b=-8), तो ((b+8)x^{16}+10x-7 -3) की डिग्री क्या होगी?
If (b=-8), what will be the degree of ((b+8)x^{16}+10x-7 -3)?
#polynomial
#parameter_zero
#degree
A (16)
B (10)
C (7)
D (0)
Explanation opens after your attempt
Explanation
Simple Explanation
(b=-8) होने पर \(x^{16}\) पद हट जाता है। बची हुई सबसे बड़ी घात (7) है। / When (b=-8), the \(x^{16}\) term disappears. The remaining highest power is (7).
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यदि (b=6), तो ((b-6)x^{15}+9x-6 -2) की डिग्री क्या होगी?
If (b=6), what will be the degree of ((b-6)x^{15}+9x-6 -2)?
#polynomial
#parameter_zero
#degree
A (15)
B (9)
C (6)
D (0)
Explanation opens after your attempt
Explanation
Simple Explanation
(b=6) होने पर \(x^{15}\) पद हट जाता है। बची हुई सबसे बड़ी घात (6) है। / When (b=6), the \(x^{15}\) term disappears. The remaining highest power is (6).
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