For which value will the zero of ((k+2)x-12) be (3)?
Answer and explanation
Correct answer: \(k=2\)
If 3 is a zero of the polynomial, its value must be 0 when \(x=3\). Thus, \((k+2)\times 3-12=0\), or \(3k+6-12=0\). Hence \(3k=6\), so \(k=2\). For \(k=4\), the polynomial gives 6, not 0. Exam tip: Substitute the given zero into the polynomial and equate the result to 0.
Frequently asked questions
What is the correct answer to this question?
\(k=2\)
Why is this the correct answer?
If 3 is a zero of the polynomial, its value must be 0 when \(x=3\). Thus, \((k+2)\times 3-12=0\), or \(3k+6-12=0\). Hence \(3k=6\), so \(k=2\). For \(k=4\), the polynomial gives 6, not 0. Exam tip: Substitute the given zero into the polynomial and equate the result to 0.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear polynomials.
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