किस मान पर ((n-3)x+2n+1) का शून्यक (1) होगा?
For which value will the zero of ((n-3)x+2n+1) be (1)?
Explanation opens after your attempt
Correct Answer
A. \(n=\frac{2}{3}\)
Concept
If the zero is (1), then (n-3+2n+1=0). Thus (3n-2=0) and \(n=\frac{2}{3}\).
Why this answer is correct
The correct answer is A. \(n=\frac{2}{3}\). If the zero is (1), then (n-3+2n+1=0). Thus (3n-2=0) and \(n=\frac{2}{3}\).
Exam Tip
शून्यक (1) होने पर (n-3+2n+1=0) होगा। इससे (3n-2=0) और \(n=\frac{2}{3}\) मिलता है।
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