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For which value will the zero of (p(x)=(c-3)x+4c) be (-2)?
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Answer and explanation
Correct answer: \(c=-3\)
If \(-2\) is a zero of \(p(x)\), then \(p(-2)=0\). Thus, \((c-3)(-2)+4c=0\), which gives \(-2c+6+4c=0\), or \(2c+6=0\). Hence, \(c=-3\). For \(c=3\), the polynomial becomes \(12\), which has no zero. Exam tip: for a given zero \(a\), directly use \(p(a)=0\).
Frequently asked questions
What is the correct answer to this question?
\(c=-3\)
Why is this the correct answer?
If \(-2\) is a zero of \(p(x)\), then \(p(-2)=0\). Thus, \((c-3)(-2)+4c=0\), which gives \(-2c+6+4c=0\), or \(2c+6=0\). Hence, \(c=-3\). For \(c=3\), the polynomial becomes \(12\), which has no zero. Exam tip: for a given zero \(a\), directly use \(p(a)=0\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear polynomials.
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