सरल करने के बाद (3(2x-5)-2(5x+1)) कौन सा रेखीय बहुपद बनेगा?
After simplifying (3(2x-5)-2(5x+1)), which linear polynomial is obtained?
#polynomial
#linear
#simplification
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A (4x-17)
B (16x-17)
C (-4x+17)
D (-4x-17)
Explanation opens after your attempt
Correct Answer
D. (-4x-17)
Step 1
Concept
(6x-15-10x-2=-4x-17). Apply negative signs carefully while opening brackets.
Step 2
Why this answer is correct
The correct answer is D. (-4x-17). (6x-15-10x-2=-4x-17). Apply negative signs carefully while opening brackets.
Step 3
Exam Tip
(6x-15-10x-2=-4x-17) है। कोष्ठक खोलते समय ऋणात्मक चिन्ह सावधानी से लगाएं।
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किस मान पर (\(m^2-1\)x+7) रेखीय बहुपद नहीं रहेगा?
For which value will (\(m^2-1\)x+7) not remain a linear polynomial?
#polynomial
#linear
#parameter
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A (m=0)
B (m=1) या (m=-1) / (m=1) or (m=-1)
C (m=2)
D (m=-2)
Explanation opens after your attempt
Correct Answer
B. (m=1) या (m=-1) / (m=1) or (m=-1)
Step 1
Concept
For it not to be linear, the coefficient of (x) must be (0). From \(m^2-1=0\), \(m=\pm1\).
Step 2
Why this answer is correct
The correct answer is B. (m=1) या (m=-1) / (m=1) or (m=-1). For it not to be linear, the coefficient of (x) must be (0). From \(m^2-1=0\), \(m=\pm1\).
Step 3
Exam Tip
रेखीय न रहने के लिए (x) का गुणांक (0) चाहिए। \(m^2-1=0\) से \(m=\pm1\) मिलता है।
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यदि (p(x)=(k-5)x+12) का शून्यक (-3) है, तो (k) क्या है?
If the zero of (p(x)=(k-5)x+12) is (-3), what is (k)?
#polynomial
#linear
#zero_parameter
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A (1)
B (5)
C (9)
D (-1)
Explanation opens after your attempt
Step 1
Concept
From (-3(k-5)+12=0), we get (k=9). Substitute the zero into the polynomial to form the equation.
Step 2
Why this answer is correct
The correct answer is C. (9). From (-3(k-5)+12=0), we get (k=9). Substitute the zero into the polynomial to form the equation.
Step 3
Exam Tip
(-3(k-5)+12=0) से (k=9) मिलता है। शून्यक को बहुपद में रखकर समीकरण बनाएं।
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यदि (p(x)=5x-4) और (q(x)=2x+7), तो (3p(x)-4q(x)) क्या है?
If (p(x)=5x-4) and (q(x)=2x+7), what is (3p(x)-4q(x))?
#polynomial
#linear
#combination
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A (7x-40)
B (23x+16)
C (7x+16)
D (15x-28)
Explanation opens after your attempt
Correct Answer
A. (7x-40)
Step 1
Concept
(3(5x-4)-4(2x+7)=7x-40). Multiply first and then combine like terms.
Step 2
Why this answer is correct
The correct answer is A. (7x-40). (3(5x-4)-4(2x+7)=7x-40). Multiply first and then combine like terms.
Step 3
Exam Tip
(3(5x-4)-4(2x+7)=7x-40) है। पहले गुणा करें फिर समान पद मिलाएं।
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किस मान पर ((2a-3)x-9) का शून्यक (3) होगा?
For which value will the zero of ((2a-3)x-9) be (3)?
#polynomial
#linear
#parameter_zero
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A (a=1)
B (a=3)
C (a=0)
D \(a=\frac{1}{2}\)
Explanation opens after your attempt
Step 1
Concept
If the zero is (3), then (3(2a-3)-9=0). This gives (a=3).
Step 2
Why this answer is correct
The correct answer is B. (a=3). If the zero is (3), then (3(2a-3)-9=0). This gives (a=3).
Step 3
Exam Tip
शून्यक (3) होने पर (3(2a-3)-9=0) होगा। इससे (a=3) मिलता है।
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यदि (p(x)=ax+b) का शून्यक (-4) है और (a=3), तो (b) क्या है?
If the zero of (p(x)=ax+b) is (-4) and (a=3), what is (b)?
#polynomial
#linear
#general_form
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A (12)
B (-12)
C (4)
D (-4)
Explanation opens after your attempt
Step 1
Concept
From (p(-4)=0), (-4a+b=0). Substituting (a=3) gives (b=12).
Step 2
Why this answer is correct
The correct answer is A. (12). From (p(-4)=0), (-4a+b=0). Substituting (a=3) gives (b=12).
Step 3
Exam Tip
(p(-4)=0) से (-4a+b=0) होगा। (a=3) रखने पर (b=12) मिलता है।
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यदि (p(x)=7x+c) और (p(6)=p(2)+28), तो (c) के बारे में क्या सही है?
If (p(x)=7x+c) and (p(6)=p(2)+28), what is correct about (c)?
#polynomial
#linear
#condition_check
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A केवल (c=0) / Only (c=0)
B हर (c) सही है / Every (c) is valid
C ऐसा कोई (c) नहीं / No such (c)
D केवल (c=28) / Only (c=28)
Explanation opens after your attempt
Correct Answer
B. हर (c) सही है / Every (c) is valid
Step 1
Concept
(p(6)-p(2)=(42+c)-(14+c)=28). So the condition is true for every (c).
Step 2
Why this answer is correct
The correct answer is B. हर (c) सही है / Every (c) is valid. (p(6)-p(2)=(42+c)-(14+c)=28). So the condition is true for every (c).
Step 3
Exam Tip
(p(6)-p(2)=(42+c)-(14+c)=28) है। इसलिए शर्त हर (c) पर सही है।
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किस विकल्प में रेखीय बहुपद का शून्यक \(-\frac{4}{9}\) है?
Which option has zero \(-\frac{4}{9}\) for a linear polynomial?
#polynomial
#linear
#fraction_zero
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A (9x-4)
B (4x+9)
C (9x+4)
D \(x+\frac{9}{4}\)
Explanation opens after your attempt
Step 1
Concept
From (9x+4=0), we get \(x=-\frac{4}{9}\). Pay attention to the sign and denominator in fractional zeros.
Step 2
Why this answer is correct
The correct answer is C. (9x+4). From (9x+4=0), we get \(x=-\frac{4}{9}\). Pay attention to the sign and denominator in fractional zeros.
Step 3
Exam Tip
(9x+4=0) से \(x=-\frac{4}{9}\) मिलता है। भिन्न शून्यक में चिन्ह और हर ध्यान रखें।
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यदि (p(x)=\frac{5}{6}x-10), तो किस मान पर (p(x)=0) होगा?
If (p(x)=\frac{5}{6}x-10), for which value will (p(x)=0)?
#polynomial
#linear
#fraction_equation
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A (x=10)
B (x=12)
C (x=15)
D (x=20)
Explanation opens after your attempt
Step 1
Concept
From \(\frac{5}{6}x-10=0\), \(\frac{5}{6}x=10\) and (x=12). With a fractional coefficient, multiply by the reciprocal.
Step 2
Why this answer is correct
The correct answer is B. (x=12). From \(\frac{5}{6}x-10=0\), \(\frac{5}{6}x=10\) and (x=12). With a fractional coefficient, multiply by the reciprocal.
Step 3
Exam Tip
\(\frac{5}{6}x-10=0\) से \(\frac{5}{6}x=10\) और (x=12) मिलता है। भिन्न गुणांक में उलटा गुणा करें।
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यदि (p(x)=x-7) और (q(x)=x+4), तो (p(x)q(x)) की डिग्री क्या है?
If (p(x)=x-7) and (q(x)=x+4), what is the degree of (p(x)q(x))?
#polynomial
#linear
#product_degree
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A (0)
B (1)
C (2)
D (7)
Explanation opens after your attempt
Step 1
Concept
In ((x-7)(x+4)), the highest term is \(x^2\). Therefore the product has degree (2).
Step 2
Why this answer is correct
The correct answer is C. (2). In ((x-7)(x+4)), the highest term is \(x^2\). Therefore the product has degree (2).
Step 3
Exam Tip
((x-7)(x+4)) में उच्चतम पद \(x^2\) है। इसलिए गुणनफल की डिग्री (2) है।
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यदि (p(x)=6x-11), तो (p(x+2)) क्या है?
If (p(x)=6x-11), what is (p(x+2))?
#polynomial
#linear
#composition
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A (6x+1)
B (6x-9)
C (6x+12)
D (x+1)
Explanation opens after your attempt
Step 1
Concept
(p(x+2)=6(x+2)-11=6x+1). Substitute the whole (x+2) in place of (x).
Step 2
Why this answer is correct
The correct answer is A. (6x+1). (p(x+2)=6(x+2)-11=6x+1). Substitute the whole (x+2) in place of (x).
Step 3
Exam Tip
(p(x+2)=6(x+2)-11=6x+1) है। (x) की जगह पूरा (x+2) रखें।
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यदि (p(x)=15-5x), तो (p(2x)) कौन सा है?
If (p(x)=15-5x), which is (p(2x))?
#polynomial
#linear
#substitution
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A (30-5x)
B (15-10x)
C (15-5x)
D (30-10x)
Explanation opens after your attempt
Correct Answer
B. (15-10x)
Step 1
Concept
(p(2x)=15-5(2x)=15-10x). While substituting, use the whole (2x).
Step 2
Why this answer is correct
The correct answer is B. (15-10x). (p(2x)=15-5(2x)=15-10x). While substituting, use the whole (2x).
Step 3
Exam Tip
(p(2x)=15-5(2x)=15-10x) है। प्रतिस्थापन करते समय पूरे (2x) को रखें।
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किस मान पर (\(t^2-5t+6\)x+(t-2)) रेखीय बहुपद नहीं रहेगा?
For which value will (\(t^2-5t+6\)x+(t-2)) not remain a linear polynomial?
#polynomial
#linear
#parameter_condition
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A (t=2) या (t=3) / (t=2) or (t=3)
B (t=0)
C (t=5)
D (t=-2)
Explanation opens after your attempt
Correct Answer
A. (t=2) या (t=3) / (t=2) or (t=3)
Step 1
Concept
For it to be linear, \(t^2-5t+6\neq0\) is needed. From \(t^2-5t+6=0\), (t=2) or (t=3).
Step 2
Why this answer is correct
The correct answer is A. (t=2) या (t=3) / (t=2) or (t=3). For it to be linear, \(t^2-5t+6\neq0\) is needed. From \(t^2-5t+6=0\), (t=2) or (t=3).
Step 3
Exam Tip
रेखीय होने के लिए \(t^2-5t+6\neq0\) चाहिए। \(t^2-5t+6=0\) से (t=2) या (t=3) मिलता है।
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यदि (p(x)=kx-8) और (p(5)=p(-1)), तो (p(x)) रेखीय कब रहेगा?
If (p(x)=kx-8) and (p(5)=p(-1)), when will (p(x)) remain linear?
#polynomial
#linear
#condition_check
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A जब (k=0) / When (k=0)
B जब (k=8) / When (k=8)
C कभी नहीं / Never
D हर (k) पर / For every (k)
Explanation opens after your attempt
Correct Answer
C. कभी नहीं / Never
Step 1
Concept
From (p(5)=p(-1)), (5k-8=-k-8), so (k=0). At (k=0), the polynomial is not linear.
Step 2
Why this answer is correct
The correct answer is C. कभी नहीं / Never. From (p(5)=p(-1)), (5k-8=-k-8), so (k=0). At (k=0), the polynomial is not linear.
Step 3
Exam Tip
(p(5)=p(-1)) से (5k-8=-k-8) और (k=0) मिलता है। (k=0) पर बहुपद रेखीय नहीं रहता।
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यदि (p(x)=ax+b) का शून्यक (0) है और (p(x)) रेखीय है, तो कौन सी शर्त जरूरी है?
If the zero of (p(x)=ax+b) is (0) and (p(x)) is linear, which condition is necessary?
#polynomial
#linear
#general_condition
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A (a=0) और (b=0) / (a=0) and (b=0)
B (b=0) और \(a\neq0\) / (b=0) and \(a\neq0\)
C \(a=b\neq0\)
D (b=1)
Explanation opens after your attempt
Correct Answer
B. (b=0) और \(a\neq0\) / (b=0) and \(a\neq0\)
Step 1
Concept
If the zero is (0), then (p(0)=b=0). To remain linear, \(a\neq0\) is also necessary.
Step 2
Why this answer is correct
The correct answer is B. (b=0) और \(a\neq0\) / (b=0) and \(a\neq0\). If the zero is (0), then (p(0)=b=0). To remain linear, \(a\neq0\) is also necessary.
Step 3
Exam Tip
शून्यक (0) होने पर (p(0)=b=0) होना चाहिए। रेखीय रहने के लिए \(a\neq0\) भी जरूरी है।
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यदि (p(x)=5x+3) और (q(x)=11x-2), तो (q(x)-2p(x)) की डिग्री क्या है?
If (p(x)=5x+3) and (q(x)=11x-2), what is the degree of (q(x)-2p(x))?
#polynomial
#linear
#degree_combination
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A (0)
B (1)
C (2)
D परिभाषित नहीं / Not defined
Explanation opens after your attempt
Step 1
Concept
(q(x)-2p(x)=11x-2-2(5x+3)=x-8). Its degree is (1).
Step 2
Why this answer is correct
The correct answer is B. (1). (q(x)-2p(x)=11x-2-2(5x+3)=x-8). Its degree is (1).
Step 3
Exam Tip
(q(x)-2p(x)=11x-2-2(5x+3)=x-8) है। इसकी डिग्री (1) है।
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किस विकल्प में रेखीय बहुपद का शून्यक \(\frac{19}{7}\) है?
Which option has zero \(\frac{19}{7}\) for a linear polynomial?
#polynomial
#linear
#fraction_zero
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A (7x-19)
B (19x-7)
C (7x+19)
D \(x-\frac{7}{19}\)
Explanation opens after your attempt
Correct Answer
A. (7x-19)
Step 1
Concept
From (7x-19=0), we get \(x=\frac{19}{7}\). Set the polynomial equal to (0) to find the zero.
Step 2
Why this answer is correct
The correct answer is A. (7x-19). From (7x-19=0), we get \(x=\frac{19}{7}\). Set the polynomial equal to (0) to find the zero.
Step 3
Exam Tip
(7x-19=0) से \(x=\frac{19}{7}\) मिलता है। शून्यक के लिए बहुपद को (0) के बराबर रखें।
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यदि (p(x)=8x-13), तो (p(x+1)-p(x)) क्या है?
If (p(x)=8x-13), what is (p(x+1)-p(x))?
#polynomial
#linear
#difference_value
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A (1)
B (8)
C (x+1)
D (8x)
Explanation opens after your attempt
Step 1
Concept
(p(x+1)=8x-5) and (p(x)=8x-13). The difference is (8).
Step 2
Why this answer is correct
The correct answer is B. (8). (p(x+1)=8x-5) and (p(x)=8x-13). The difference is (8).
Step 3
Exam Tip
(p(x+1)=8x-5) और (p(x)=8x-13) है। अंतर (8) मिलता है।
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यदि (p(x)=\lambda x+15) और इसका शून्यक (-5) से बड़ा है, तो \(\lambda>0\) होने पर कौन सी शर्त सही है?
If (p(x)=\lambda x+15) and its zero is greater than (-5), which condition is correct when \(\lambda>0\)?
#polynomial
#linear
#inequality
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A \(0<\lambda<3\)
B \(\lambda=3\)
C \(\lambda>3\)
D \(\lambda<0\)
Explanation opens after your attempt
Correct Answer
C. \(\lambda>3\)
Step 1
Concept
The zero is \(-\frac{15}{\lambda}\). From \(-\frac{15}{\lambda}>-5\) and \(\lambda>0\), we get \(\lambda>3\).
Step 2
Why this answer is correct
The correct answer is C. \(\lambda>3\). The zero is \(-\frac{15}{\lambda}\). From \(-\frac{15}{\lambda}>-5\) and \(\lambda>0\), we get \(\lambda>3\).
Step 3
Exam Tip
शून्यक \(-\frac{15}{\lambda}\) है। \(-\frac{15}{\lambda}>-5\) और \(\lambda>0\) से \(\lambda>3\) मिलता है।
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यदि (p(x)=x+3r) और (q(x)=x-5r), तो (p(x)+q(x)) क्या है?
If (p(x)=x+3r) and (q(x)=x-5r), what is (p(x)+q(x))?
#polynomial
#linear
#parameter_sum
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A (2x-2r)
B (2x+8r)
C (x-2r)
D (8r)
Explanation opens after your attempt
Correct Answer
A. (2x-2r)
Step 1
Concept
On adding, (x+3r+x-5r=2x-2r). Combine the parameter terms too.
Step 2
Why this answer is correct
The correct answer is A. (2x-2r). On adding, (x+3r+x-5r=2x-2r). Combine the parameter terms too.
Step 3
Exam Tip
जोड़ने पर (x+3r+x-5r=2x-2r) मिलता है। पैरामीटर वाले पदों को भी मिलाएं।
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यदि (p(x)=x+3r) और (q(x)=x-5r), तो (p(x)-q(x)) किस प्रकार का बहुपद है?
If (p(x)=x+3r) and (q(x)=x-5r), what type of polynomial is (p(x)-q(x))?
#polynomial
#linear
#constant_result
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A रेखीय बहुपद / Linear polynomial
B नियतांक बहुपद / Constant polynomial
C द्विघात बहुपद / Quadratic polynomial
D शून्य बहुपद / Zero polynomial
Explanation opens after your attempt
Correct Answer
B. नियतांक बहुपद / Constant polynomial
Step 1
Concept
(p(x)-q(x)=8r). With respect to (x), it is a constant polynomial.
Step 2
Why this answer is correct
The correct answer is B. नियतांक बहुपद / Constant polynomial. (p(x)-q(x)=8r). With respect to (x), it is a constant polynomial.
Step 3
Exam Tip
(p(x)-q(x)=8r) है। (x) के संदर्भ में यह नियतांक बहुपद है।
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यदि (p(x)=6x-17), तो (p(p(3))) का सही मान क्या है?
If (p(x)=6x-17), what is the correct value of (p(p(3)))?
#polynomial
#linear
#composition_value
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A (1)
B (-11)
C (3)
D (6)
Explanation opens after your attempt
Step 1
Concept
(p(3)=1) and (p(1)=6-17=-11). Find the inner value first.
Step 2
Why this answer is correct
The correct answer is B. (-11). (p(3)=1) and (p(1)=6-17=-11). Find the inner value first.
Step 3
Exam Tip
(p(3)=1) और (p(1)=6-17=-11) है। अंदर वाले मान को पहले निकालें।
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यदि (p(x)=4x+3), तो (p(p(0))) का मान क्या है?
If (p(x)=4x+3), what is the value of (p(p(0)))?
#polynomial
#linear
#composition_value
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A (3)
B (12)
C (15)
D (18)
Explanation opens after your attempt
Step 1
Concept
(p(0)=3) and (p(3)=15). In composition, find the inner value first.
Step 2
Why this answer is correct
The correct answer is C. (15). (p(0)=3) and (p(3)=15). In composition, find the inner value first.
Step 3
Exam Tip
(p(0)=3) और (p(3)=15) है। रचना में अंदर वाला मान पहले निकालें।
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किस मान पर ((n+4)x+2n-1) का शून्यक (1) होगा?
For which value will the zero of ((n+4)x+2n-1) be (1)?
#polynomial
#linear
#parameter_zero
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A (n=-1)
B (n=1)
C \(n=-\frac{1}{3}\)
D (n=4)
Explanation opens after your attempt
Step 1
Concept
If the zero is (1), then (n+4+2n-1=0). Thus (3n+3=0) and (n=-1).
Step 2
Why this answer is correct
The correct answer is A. (n=-1). If the zero is (1), then (n+4+2n-1=0). Thus (3n+3=0) and (n=-1).
Step 3
Exam Tip
शून्यक (1) होने पर (n+4+2n-1=0) होगा। इससे (3n+3=0) और (n=-1) मिलता है।
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यदि (p(x)=\frac{x}{6}+a) और (p(18)=14), तो (a) का मान क्या है?
If (p(x)=\frac{x}{6}+a) and (p(18)=14), what is the value of (a)?
#polynomial
#linear
#fraction_parameter
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A (9)
B (10)
C (11)
D (14)
Explanation opens after your attempt
Step 1
Concept
From (p(18)=3+a=14), we get (a=11). In fractional form, substitute the value of (x) first.
Step 2
Why this answer is correct
The correct answer is C. (11). From (p(18)=3+a=14), we get (a=11). In fractional form, substitute the value of (x) first.
Step 3
Exam Tip
(p(18)=3+a=14) से (a=11) मिलता है। भिन्न रूप में पहले (x) का मान रखें।
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यदि (p(x)=5x+a) और (q(x)=2x-9), तो (p(x)+q(x)) का शून्यक (2) होने पर (a) क्या है?
If (p(x)=5x+a) and (q(x)=2x-9), what is (a) if the zero of (p(x)+q(x)) is (2)?
#polynomial
#linear
#sum_zero_parameter
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A (-5)
B (-3)
C (0)
D (5)
Explanation opens after your attempt
Step 1
Concept
(p(x)+q(x)=7x+a-9). Substituting (x=2) gives (14+a-9=0), so (a=-5).
Step 2
Why this answer is correct
The correct answer is A. (-5). (p(x)+q(x)=7x+a-9). Substituting (x=2) gives (14+a-9=0), so (a=-5).
Step 3
Exam Tip
(p(x)+q(x)=7x+a-9) है। (x=2) रखने पर (14+a-9=0) से (a=-5) मिलता है।
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किस मान पर (p(x)=(c-3)x+4c) का शून्यक (-2) होगा?
For which value will the zero of (p(x)=(c-3)x+4c) be (-2)?
#polynomial
#linear
#parameter_zero
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A (c=-3)
B (c=3)
C (c=1)
D कोई मान नहीं / No value
Explanation opens after your attempt
Step 1
Concept
From (-2(c-3)+4c=0), we get (2c+6=0). Therefore (c=-3).
Step 2
Why this answer is correct
The correct answer is A. (c=-3). From (-2(c-3)+4c=0), we get (2c+6=0). Therefore (c=-3).
Step 3
Exam Tip
(-2(c-3)+4c=0) से (2c+6=0) मिलता है। इसलिए (c=-3) है।
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यदि (p(x)=(c-1)x+2c) का शून्यक (-2) है, तो कौन सा निष्कर्ष सही है?
If the zero of (p(x)=(c-1)x+2c) is (-2), which conclusion is correct?
#polynomial
#linear
#no_solution
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A (c=1)
B (c=-1)
C कोई (c) नहीं / No (c)
D हर (c) / Every (c)
Explanation opens after your attempt
Correct Answer
C. कोई (c) नहीं / No (c)
Step 1
Concept
From (-2(c-1)+2c=0), we get the impossible result (2=0). Therefore no (c) exists.
Step 2
Why this answer is correct
The correct answer is C. कोई (c) नहीं / No (c). From (-2(c-1)+2c=0), we get the impossible result (2=0). Therefore no (c) exists.
Step 3
Exam Tip
(-2(c-1)+2c=0) से (2=0) जैसा असंभव परिणाम मिलता है। इसलिए कोई (c) नहीं है।
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यदि (p(x)=rx-6) और (p(4)=18), तो (p(-2)) का मान क्या है?
If (p(x)=rx-6) and (p(4)=18), what is the value of (p(-2))?
#polynomial
#linear
#two_step
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A (0)
B (-18)
C (-12)
D (6)
Explanation opens after your attempt
Step 1
Concept
From (4r-6=18), we get (r=6). Therefore (p(-2)=6(-2)-6=-18).
Step 2
Why this answer is correct
The correct answer is B. (-18). From (4r-6=18), we get (r=6). Therefore (p(-2)=6(-2)-6=-18).
Step 3
Exam Tip
(4r-6=18) से (r=6) मिलता है। इसलिए (p(-2)=6(-2)-6=-18) है।
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यदि (p(x)=ax+10) और (p(2)=p(5)-15), तो (a) क्या है?
If (p(x)=ax+10) and (p(2)=p(5)-15), what is (a)?
#polynomial
#linear
#parameter_equation
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A (3)
B (5)
C (10)
D (15)
Explanation opens after your attempt
Step 1
Concept
From (2a+10=(5a+10)-15), we get (2a=5a-15). Therefore (a=5).
Step 2
Why this answer is correct
The correct answer is B. (5). From (2a+10=(5a+10)-15), we get (2a=5a-15). Therefore (a=5).
Step 3
Exam Tip
(2a+10=(5a+10)-15) से (2a=5a-15) मिलता है। इसलिए (a=5) है।
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यदि (p(x)=5x-18), तो (p(a)=a) होने पर (a) क्या है?
If (p(x)=5x-18), what is (a) when (p(a)=a)?
#polynomial
#linear
#fixed_value
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A (3)
B \(\frac{9}{2}\)
C (5)
D (18)
Explanation opens after your attempt
Correct Answer
B. \(\frac{9}{2}\)
Step 1
Concept
(p(a)=5a-18). From (5a-18=a), we get \(a=\frac{9}{2}\).
Step 2
Why this answer is correct
The correct answer is B. \(\frac{9}{2}\). (p(a)=5a-18). From (5a-18=a), we get \(a=\frac{9}{2}\).
Step 3
Exam Tip
(p(a)=5a-18) है। (5a-18=a) से \(a=\frac{9}{2}\) मिलता है।
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यदि (p(x)=mx+n), (p(0)=-4) और (p(3)=11), तो (m+n) क्या है?
If (p(x)=mx+n), (p(0)=-4) and (p(3)=11), what is (m+n)?
#polynomial
#linear
#coefficients
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A (1)
B (5)
C (11)
D (15)
Explanation opens after your attempt
Step 1
Concept
(p(0)=n=-4) and (3m-4=11) gives (m=5). Therefore (m+n=1).
Step 2
Why this answer is correct
The correct answer is A. (1). (p(0)=n=-4) and (3m-4=11) gives (m=5). Therefore (m+n=1).
Step 3
Exam Tip
(p(0)=n=-4) और (3m-4=11) से (m=5) मिलता है। इसलिए (m+n=1) है।
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यदि (p(x)=mx+n), (p(-2)=1) और (p(2)=17), तो (m) क्या है?
If (p(x)=mx+n), (p(-2)=1) and (p(2)=17), what is (m)?
#polynomial
#linear
#slope_parameter
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A (2)
B (4)
C (8)
D (16)
Explanation opens after your attempt
Step 1
Concept
Subtracting the two values gives (p(2)-p(-2)=4m=16). Therefore (m=4).
Step 2
Why this answer is correct
The correct answer is B. (4). Subtracting the two values gives (p(2)-p(-2)=4m=16). Therefore (m=4).
Step 3
Exam Tip
दोनों मान घटाने पर (p(2)-p(-2)=4m=16) मिलता है। इसलिए (m=4) है।
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किस विकल्प में (p(-5)=0) और (p(x)) रेखीय है?
Which option has (p(-5)=0) and (p(x)) is linear?
#polynomial
#linear
#zero_identification
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A (p(x)=x-5)
B (p(x)=5x+5)
C (p(x)=x+5)
D (p(x)=x-2 -25)
Explanation opens after your attempt
Correct Answer
C. (p(x)=x+5)
Step 1
Concept
Substituting (x=-5) in (x+5) gives (0). It is a linear polynomial of degree (1).
Step 2
Why this answer is correct
The correct answer is C. (p(x)=x+5). Substituting (x=-5) in (x+5) gives (0). It is a linear polynomial of degree (1).
Step 3
Exam Tip
(x+5) में (x=-5) रखने पर (0) मिलता है। यह डिग्री (1) वाला रेखीय बहुपद है।
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यदि (p(x)=6x+11), तो (p(x)+p(-x)) क्या है?
If (p(x)=6x+11), what is (p(x)+p(-x))?
#polynomial
#linear
#symmetry
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A (12x+22)
B (22)
C (0)
D (6x+22)
Explanation opens after your attempt
Step 1
Concept
(p(-x)=-6x+11). Adding gives (6x+11-6x+11=22).
Step 2
Why this answer is correct
The correct answer is B. (22). (p(-x)=-6x+11). Adding gives (6x+11-6x+11=22).
Step 3
Exam Tip
(p(-x)=-6x+11) है। जोड़ने पर (6x+11-6x+11=22) मिलता है।
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यदि (p(x)=6x+11), तो (p(x)-p(-x)) क्या है?
If (p(x)=6x+11), what is (p(x)-p(-x))?
#polynomial
#linear
#symmetry
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A (12x)
B (0)
C (22)
D (6x)
Explanation opens after your attempt
Step 1
Concept
(p(-x)=-6x+11). Subtracting gives (6x+11-(-6x+11)=12x).
Step 2
Why this answer is correct
The correct answer is A. (12x). (p(-x)=-6x+11). Subtracting gives (6x+11-(-6x+11)=12x).
Step 3
Exam Tip
(p(-x)=-6x+11) है। घटाने पर (6x+11-(-6x+11)=12x) मिलता है।
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किस मान पर ((s+7)x+4s) का शून्यक (0) होगा?
For which value will the zero of ((s+7)x+4s) be (0)?
#polynomial
#linear
#zero_at_origin
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A (s=0)
B (s=-7)
C (s=7)
D कोई मान नहीं / No value
Explanation opens after your attempt
Step 1
Concept
For the zero to be (0), the constant term (4s=0). At (s=0), the coefficient of (x) is (7), so the polynomial is linear.
Step 2
Why this answer is correct
The correct answer is A. (s=0). For the zero to be (0), the constant term (4s=0). At (s=0), the coefficient of (x) is (7), so the polynomial is linear.
Step 3
Exam Tip
शून्यक (0) होने के लिए नियतांक पद (4s=0) होना चाहिए। (s=0) पर (x) का गुणांक (7) है इसलिए बहुपद रेखीय है।
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यदि (p(x)=5x+a) और (q(x)=7x-a), तो (p(x)+q(x)) का शून्यक (1) होने पर (a) क्या है?
If (p(x)=5x+a) and (q(x)=7x-a), what is (a) if the zero of (p(x)+q(x)) is (1)?
#polynomial
#linear
#no_solution
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A कोई मान नहीं / No value
B (0)
C (1)
D (12)
Explanation opens after your attempt
Correct Answer
A. कोई मान नहीं / No value
Step 1
Concept
(p(x)+q(x)=12x), whose zero is (0). Therefore the zero cannot be (1) for any (a).
Step 2
Why this answer is correct
The correct answer is A. कोई मान नहीं / No value. (p(x)+q(x)=12x), whose zero is (0). Therefore the zero cannot be (1) for any (a).
Step 3
Exam Tip
(p(x)+q(x)=12x) है जिसका शून्यक (0) है। इसलिए शून्यक (1) किसी (a) पर नहीं हो सकता।
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यदि (p(x)=5x+a) और (q(x)=7x-a), तो (q(x)-p(x)) क्या है?
If (p(x)=5x+a) and (q(x)=7x-a), what is (q(x)-p(x))?
#polynomial
#linear
#parameter_difference
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A (12x)
B (2x-2a)
C (2x)
D (2a)
Explanation opens after your attempt
Correct Answer
B. (2x-2a)
Step 1
Concept
(7x-a-(5x+a)=2x-2a). Change the signs inside the bracket while subtracting.
Step 2
Why this answer is correct
The correct answer is B. (2x-2a). (7x-a-(5x+a)=2x-2a). Change the signs inside the bracket while subtracting.
Step 3
Exam Tip
(7x-a-(5x+a)=2x-2a) है। घटाते समय कोष्ठक के चिन्ह बदलें।
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किस विकल्प में ((4x+1)) और ((x-6)) का गुणनफल रेखीय नहीं है?
Which option correctly says that the product of ((4x+1)) and ((x-6)) is not linear?
#polynomial
#linear
#product_reason
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A क्योंकि डिग्री (1) है / Because degree is (1)
B क्योंकि यह नियतांक है / Because it is constant
C क्योंकि यह शून्य है / Because it is zero
D क्योंकि डिग्री (2) है / Because degree is (2)
Explanation opens after your attempt
Correct Answer
D. क्योंकि डिग्री (2) है / Because degree is (2)
Step 1
Concept
In ((4x+1)(x-6)), the highest term is \(4x^2\). So the product has degree (2) and is not linear.
Step 2
Why this answer is correct
The correct answer is D. क्योंकि डिग्री (2) है / Because degree is (2). In ((4x+1)(x-6)), the highest term is \(4x^2\). So the product has degree (2) and is not linear.
Step 3
Exam Tip
((4x+1)(x-6)) में उच्चतम पद \(4x^2\) है। इसलिए गुणनफल की डिग्री (2) है और यह रेखीय नहीं है।
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यदि (p(x)=ax+5) और (p(p(0))=35), तो (a) क्या है?
If (p(x)=ax+5) and (p(p(0))=35), what is (a)?
#polynomial
#linear
#composition_parameter
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A (5)
B (6)
C (7)
D (35)
Explanation opens after your attempt
Step 1
Concept
(p(0)=5) and (p(5)=5a+5). From (5a+5=35), we get (a=6).
Step 2
Why this answer is correct
The correct answer is B. (6). (p(0)=5) and (p(5)=5a+5). From (5a+5=35), we get (a=6).
Step 3
Exam Tip
(p(0)=5) और (p(5)=5a+5) है। (5a+5=35) से (a=6) मिलता है।
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यदि (p(x)=x+a) और (p(p(3))=13), तो (a) का मान क्या है?
If (p(x)=x+a) and (p(p(3))=13), what is the value of (a)?
#polynomial
#linear
#composition_parameter
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A (3)
B (5)
C (10)
D (13)
Explanation opens after your attempt
Step 1
Concept
(p(3)=3+a) and (p(3+a)=3+2a). From (3+2a=13), we get (a=5).
Step 2
Why this answer is correct
The correct answer is B. (5). (p(3)=3+a) and (p(3+a)=3+2a). From (3+2a=13), we get (a=5).
Step 3
Exam Tip
(p(3)=3+a) और (p(3+a)=3+2a) है। (3+2a=13) से (a=5) मिलता है।
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यदि (p(x)=mx+n) और (p(-3)=p(1)), तो (p(x)) रेखीय कब हो सकता है?
If (p(x)=mx+n) and (p(-3)=p(1)), when can (p(x)) be linear?
#polynomial
#linear
#condition_check
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A जब (m=0) / When (m=0)
B जब (n=0) / When (n=0)
C कभी नहीं / Never
D हर (m) पर / For every (m)
Explanation opens after your attempt
Correct Answer
C. कभी नहीं / Never
Step 1
Concept
From (p(-3)=p(1)), (-3m+n=m+n), so (m=0). At (m=0), the polynomial is not linear.
Step 2
Why this answer is correct
The correct answer is C. कभी नहीं / Never. From (p(-3)=p(1)), (-3m+n=m+n), so (m=0). At (m=0), the polynomial is not linear.
Step 3
Exam Tip
(p(-3)=p(1)) से (-3m+n=m+n) और (m=0) मिलता है। (m=0) पर बहुपद रेखीय नहीं रहता।
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किस विकल्प में (p(x)=ax+b) का शून्यक (8) होगा?
In which option will (p(x)=ax+b) have zero (8)?
#polynomial
#linear
#general_condition
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A (b=8a) और \(a\neq0\) / (b=8a) and \(a\neq0\)
B (b=-8a) और \(a\neq0\) / (b=-8a) and \(a\neq0\)
C (a=0)
D (b=0)
Explanation opens after your attempt
Correct Answer
B. (b=-8a) और \(a\neq0\) / (b=-8a) and \(a\neq0\)
Step 1
Concept
If the zero is (8), then (8a+b=0). So (b=-8a) and \(a\neq0\) are needed.
Step 2
Why this answer is correct
The correct answer is B. (b=-8a) और \(a\neq0\) / (b=-8a) and \(a\neq0\). If the zero is (8), then (8a+b=0). So (b=-8a) and \(a\neq0\) are needed.
Step 3
Exam Tip
शून्यक (8) होने पर (8a+b=0) होगा। इसलिए (b=-8a) और \(a\neq0\) चाहिए।
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यदि (p(x)=9x-4), तो (p(x+2)-p(x-1)) क्या है?
If (p(x)=9x-4), what is (p(x+2)-p(x-1))?
#polynomial
#linear
#shift_difference
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A (9)
B (18)
C (27)
D (36)
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Step 1
Concept
(p(x+2)=9x+14) and (p(x-1)=9x-13). The difference is (27).
Step 2
Why this answer is correct
The correct answer is C. (27). (p(x+2)=9x+14) and (p(x-1)=9x-13). The difference is (27).
Step 3
Exam Tip
(p(x+2)=9x+14) और (p(x-1)=9x-13) है। अंतर (27) है।
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यदि (p(x)=7x-20), तो (p(p(3))) का सही मान क्या है?
If (p(x)=7x-20), what is the correct value of (p(p(3)))?
#polynomial
#linear
#composition_value
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A (1)
B (-13)
C (3)
D (7)
Explanation opens after your attempt
Step 1
Concept
(p(3)=1) and (p(1)=7-20=-13). Find the inner value first.
Step 2
Why this answer is correct
The correct answer is B. (-13). (p(3)=1) and (p(1)=7-20=-13). Find the inner value first.
Step 3
Exam Tip
(p(3)=1) और (p(1)=7-20=-13) है। अंदर वाले मान को पहले निकालें।
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यदि (p(x)=10x+a) और (p(p(0))=110), तो (a) का मान क्या है?
If (p(x)=10x+a) and (p(p(0))=110), what is the value of (a)?
#polynomial
#linear
#composition_parameter
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A (10)
B (11)
C (100)
D (110)
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Step 1
Concept
(p(0)=a) and (p(a)=10a+a=11a). From (11a=110), we get (a=10).
Step 2
Why this answer is correct
The correct answer is A. (10). (p(0)=a) and (p(a)=10a+a=11a). From (11a=110), we get (a=10).
Step 3
Exam Tip
(p(0)=a) और (p(a)=10a+a=11a) है। (11a=110) से (a=10) मिलता है।
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यदि (p(x)=mx+n), (p(-1)=3) और (p(4)=23), तो (m+n) क्या है?
If (p(x)=mx+n), (p(-1)=3) and (p(4)=23), what is (m+n)?
#polynomial
#linear
#coefficients
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A (4)
B (7)
C (11)
D (23)
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Step 1
Concept
Subtracting the two values gives (5m=20), so (m=4). From (-m+n=3), (n=7), so (m+n=11).
Step 2
Why this answer is correct
The correct answer is C. (11). Subtracting the two values gives (5m=20), so (m=4). From (-m+n=3), (n=7), so (m+n=11).
Step 3
Exam Tip
दोनों मान घटाने पर (5m=20) से (m=4) मिलता है। (-m+n=3) से (n=7), इसलिए (m+n=11) है।
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यदि (p(x)=11x-6), तो (p(x+1)+p(x-2)) क्या है?
If (p(x)=11x-6), what is (p(x+1)+p(x-2))?
#polynomial
#linear
#shift_sum
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A (22x-12)
B (22x-17)
C (11x-17)
D (22x+17)
Explanation opens after your attempt
Correct Answer
B. (22x-17)
Step 1
Concept
(p(x+1)=11x+5) and (p(x-2)=11x-28). Adding gives (22x-23), not (22x-17).
Step 2
Why this answer is correct
The correct answer is B. (22x-17). (p(x+1)=11x+5) and (p(x-2)=11x-28). Adding gives (22x-23), not (22x-17).
Step 3
Exam Tip
(p(x+1)=11x+5) और (p(x-2)=11x-28) है। जोड़ने पर (22x-23) नहीं, बल्कि (22x-23) मिलता है।
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किस मान पर (\(r^2-5r+6\)x+4) रेखीय बहुपद नहीं रहेगा?
For which value will (\(r^2-5r+6\)x+4) not remain a linear polynomial?
#polynomial
#linear
#parameter_condition
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A (r=2) या (r=3) / (r=2) or (r=3)
B (r=0) या (r=6) / (r=0) or (r=6)
C (r=5) ही / (r=5) only
D कोई मान नहीं / No value
Explanation opens after your attempt
Correct Answer
A. (r=2) या (r=3) / (r=2) or (r=3)
Step 1
Concept
For it not to be linear, the coefficient of (x) must be (0). From \(r^2-5r+6=0\), (r=2) or (r=3).
Step 2
Why this answer is correct
The correct answer is A. (r=2) या (r=3) / (r=2) or (r=3). For it not to be linear, the coefficient of (x) must be (0). From \(r^2-5r+6=0\), (r=2) or (r=3).
Step 3
Exam Tip
रेखीय न रहने के लिए (x) का गुणांक (0) होना चाहिए। \(r^2-5r+6=0\) से (r=2) या (r=3) मिलता है।
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