If (p(x)=11x-6), what is (p(x+1)+p(x-2))?
Answer and explanation
Correct answer: \(22x-23\)
Given \(p(x)=11x-6\), we get \(p(x+1)=11(x+1)-6=11x+5\) and \(p(x-2)=11(x-2)-6=11x-28\). Hence, \(p(x+1)+p(x-2)=(11x+5)+(11x-28)=22x-23\). The option \(22x-17\) results from an incorrect addition of the constant terms. Exam tip: simplify each substituted expression separately before adding them.
Frequently asked questions
What is the correct answer to this question?
\(22x-23\)
Why is this the correct answer?
Given \(p(x)=11x-6\), we get \(p(x+1)=11(x+1)-6=11x+5\) and \(p(x-2)=11(x-2)-6=11x-28\). Hence, \(p(x+1)+p(x-2)=(11x+5)+(11x-28)=22x-23\). The option \(22x-17\) results from an incorrect addition of the constant terms. Exam tip: simplify each substituted expression separately before adding them.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear polynomials.
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