Concept-wise Practice

general_condition MCQ Questions for Class 9

general_condition se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

16 questions tagged with general_condition.

किस विकल्प में (p(x)=ax+b) का शून्यक (12) होगा?

In which option will (p(x)=ax+b) have zero (12)?

Explanation opens after your attempt
Correct Answer

B. (b=-12a) और \(a\neq0\)(b=-12a) and \(a\neq0\)

Step 1

Concept

If the zero is (12), then (12a+b=0). So (b=-12a) and \(a\neq0\) are needed.

Step 2

Why this answer is correct

The correct answer is B. (b=-12a) और \(a\neq0\) / (b=-12a) and \(a\neq0\). If the zero is (12), then (12a+b=0). So (b=-12a) and \(a\neq0\) are needed.

Step 3

Exam Tip

शून्यक (12) होने पर (12a+b=0) होगा। इसलिए (b=-12a) और \(a\neq0\) चाहिए।

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किस विकल्प में (p(x)=ax+b) का शून्यक (-11) होगा?

In which option will (p(x)=ax+b) have zero (-11)?

Explanation opens after your attempt
Correct Answer

A. (b=11a) और \(a\neq0\)(b=11a) and \(a\neq0\)

Step 1

Concept

If the zero is (-11), then (-11a+b=0). So (b=11a) and \(a\neq0\) are needed.

Step 2

Why this answer is correct

The correct answer is A. (b=11a) और \(a\neq0\) / (b=11a) and \(a\neq0\). If the zero is (-11), then (-11a+b=0). So (b=11a) and \(a\neq0\) are needed.

Step 3

Exam Tip

शून्यक (-11) होने पर (-11a+b=0) होगा। इसलिए (b=11a) और \(a\neq0\) चाहिए।

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किस विकल्प में (p(x)=ax+b) का शून्यक (10) होगा?

In which option will (p(x)=ax+b) have zero (10)?

Explanation opens after your attempt
Correct Answer

B. (b=-10a) और \(a\neq0\)(b=-10a) and \(a\neq0\)

Step 1

Concept

If the zero is (10), then (10a+b=0). So (b=-10a) and \(a\neq0\) are needed.

Step 2

Why this answer is correct

The correct answer is B. (b=-10a) और \(a\neq0\) / (b=-10a) and \(a\neq0\). If the zero is (10), then (10a+b=0). So (b=-10a) and \(a\neq0\) are needed.

Step 3

Exam Tip

शून्यक (10) होने पर (10a+b=0) होगा। इसलिए (b=-10a) और \(a\neq0\) चाहिए।

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किस विकल्प में (p(x)=ax+b) का शून्यक (-9) होगा?

In which option will (p(x)=ax+b) have zero (-9)?

Explanation opens after your attempt
Correct Answer

A. (b=9a) और \(a\neq0\)(b=9a) and \(a\neq0\)

Step 1

Concept

If the zero is (-9), then (-9a+b=0). So (b=9a) and \(a\neq0\) are needed.

Step 2

Why this answer is correct

The correct answer is A. (b=9a) और \(a\neq0\) / (b=9a) and \(a\neq0\). If the zero is (-9), then (-9a+b=0). So (b=9a) and \(a\neq0\) are needed.

Step 3

Exam Tip

शून्यक (-9) होने पर (-9a+b=0) होगा। इसलिए (b=9a) और \(a\neq0\) चाहिए।

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किस विकल्प में (p(x)=ax+b) का शून्यक (8) होगा?

In which option will (p(x)=ax+b) have zero (8)?

Explanation opens after your attempt
Correct Answer

B. (b=-8a) और \(a\neq0\)(b=-8a) and \(a\neq0\)

Step 1

Concept

If the zero is (8), then (8a+b=0). So (b=-8a) and \(a\neq0\) are needed.

Step 2

Why this answer is correct

The correct answer is B. (b=-8a) और \(a\neq0\) / (b=-8a) and \(a\neq0\). If the zero is (8), then (8a+b=0). So (b=-8a) and \(a\neq0\) are needed.

Step 3

Exam Tip

शून्यक (8) होने पर (8a+b=0) होगा। इसलिए (b=-8a) और \(a\neq0\) चाहिए।

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यदि (p(x)=ax+b) का शून्यक (0) है और (p(x)) रेखीय है, तो कौन सी शर्त जरूरी है?

If the zero of (p(x)=ax+b) is (0) and (p(x)) is linear, which condition is necessary?

Explanation opens after your attempt
Correct Answer

B. (b=0) और \(a\neq0\)(b=0) and \(a\neq0\)

Step 1

Concept

If the zero is (0), then (p(0)=b=0). To remain linear, \(a\neq0\) is also necessary.

Step 2

Why this answer is correct

The correct answer is B. (b=0) और \(a\neq0\) / (b=0) and \(a\neq0\). If the zero is (0), then (p(0)=b=0). To remain linear, \(a\neq0\) is also necessary.

Step 3

Exam Tip

शून्यक (0) होने पर (p(0)=b=0) होना चाहिए। रेखीय रहने के लिए \(a\neq0\) भी जरूरी है।

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किस विकल्प में (p(x)=ax+b) का शून्यक (-7) होगा?

In which option will (p(x)=ax+b) have zero (-7)?

Explanation opens after your attempt
Correct Answer

A. (b=7a) और \(a\neq0\)(b=7a) and \(a\neq0\)

Step 1

Concept

If the zero is (-7), then (-7a+b=0). So (b=7a) and \(a\neq0\) are needed.

Step 2

Why this answer is correct

The correct answer is A. (b=7a) और \(a\neq0\) / (b=7a) and \(a\neq0\). If the zero is (-7), then (-7a+b=0). So (b=7a) and \(a\neq0\) are needed.

Step 3

Exam Tip

शून्यक (-7) होने पर (-7a+b=0) होगा। इसलिए (b=7a) और \(a\neq0\) चाहिए।

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किस विकल्प में (p(x)=ax+b) का शून्यक (6) होगा?

In which option will (p(x)=ax+b) have zero (6)?

Explanation opens after your attempt
Correct Answer

D. (b=-6a) और \(a\neq0\)(b=-6a) and \(a\neq0\)

Step 1

Concept

If the zero is (6), then (6a+b=0). So (b=-6a) and \(a\neq0\) are needed.

Step 2

Why this answer is correct

The correct answer is D. (b=-6a) और \(a\neq0\) / (b=-6a) and \(a\neq0\). If the zero is (6), then (6a+b=0). So (b=-6a) and \(a\neq0\) are needed.

Step 3

Exam Tip

शून्यक (6) होने पर (6a+b=0) होगा। इसलिए (b=-6a) और \(a\neq0\) चाहिए।

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यदि (p(x)=ax+b) का शून्यक (0) है और (p(x)) रेखीय है, तो कौन सी शर्त सही है?

If the zero of (p(x)=ax+b) is (0) and (p(x)) is linear, which condition is correct?

Explanation opens after your attempt
Correct Answer

D. (b=0) और \(a\neq0\)(b=0) and \(a\neq0\)

Step 1

Concept

If the zero is (0), then (p(0)=b=0). To remain linear, \(a\neq0\) is also necessary.

Step 2

Why this answer is correct

The correct answer is D. (b=0) और \(a\neq0\) / (b=0) and \(a\neq0\). If the zero is (0), then (p(0)=b=0). To remain linear, \(a\neq0\) is also necessary.

Step 3

Exam Tip

शून्यक (0) होने पर (p(0)=b=0) होना चाहिए। रेखीय रहने के लिए \(a\neq0\) भी जरूरी है।

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किस विकल्प में (p(x)=ax+b) का शून्यक (-5) होगा?

In which option will (p(x)=ax+b) have zero (-5)?

Explanation opens after your attempt
Correct Answer

A. (b=5a) और \(a\neq0\)(b=5a) and \(a\neq0\)

Step 1

Concept

If the zero is (-5), then (-5a+b=0). So (b=5a) and \(a\neq0\) are needed.

Step 2

Why this answer is correct

The correct answer is A. (b=5a) और \(a\neq0\) / (b=5a) and \(a\neq0\). If the zero is (-5), then (-5a+b=0). So (b=5a) and \(a\neq0\) are needed.

Step 3

Exam Tip

शून्यक (-5) होने पर (-5a+b=0) होगा। इसलिए (b=5a) और \(a\neq0\) चाहिए।

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किस विकल्प में (p(x)=ax+b) का शून्यक (4) होगा?

In which option will (p(x)=ax+b) have zero (4)?

Explanation opens after your attempt
Correct Answer

B. (b=-4a) और \(a\neq0\)(b=-4a) and \(a\neq0\)

Step 1

Concept

If the zero is (4), then (4a+b=0). So (b=-4a) and \(a\neq0\) are needed.

Step 2

Why this answer is correct

The correct answer is B. (b=-4a) और \(a\neq0\) / (b=-4a) and \(a\neq0\). If the zero is (4), then (4a+b=0). So (b=-4a) and \(a\neq0\) are needed.

Step 3

Exam Tip

शून्यक (4) होने पर (4a+b=0) होगा। इसलिए (b=-4a) और \(a\neq0\) चाहिए।

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यदि (p(x)=ax+b) का शून्यक (0) है और बहुपद रेखीय है, तो कौन सी शर्त सही है?

If the zero of (p(x)=ax+b) is (0) and the polynomial is linear, which condition is correct?

Explanation opens after your attempt
Correct Answer

B. (b=0) और \(a\neq0\)(b=0) and \(a\neq0\)

Step 1

Concept

If the zero is (0), then (p(0)=b=0). To remain linear, \(a\neq0\) is also necessary.

Step 2

Why this answer is correct

The correct answer is B. (b=0) और \(a\neq0\) / (b=0) and \(a\neq0\). If the zero is (0), then (p(0)=b=0). To remain linear, \(a\neq0\) is also necessary.

Step 3

Exam Tip

शून्यक (0) होने पर (p(0)=b=0) होना चाहिए। रेखीय रहने के लिए \(a\neq0\) भी जरूरी है।

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किस विकल्प में (p(x)=ax+b) का शून्यक (3) होगा?

In which option will (p(x)=ax+b) have zero (3)?

Explanation opens after your attempt
Correct Answer

A. (b=-3a) और \(a\neq0\)(b=-3a) and \(a\neq0\)

Step 1

Concept

If the zero is (3), then (3a+b=0). So (b=-3a) and \(a\neq0\) are needed.

Step 2

Why this answer is correct

The correct answer is A. (b=-3a) और \(a\neq0\) / (b=-3a) and \(a\neq0\). If the zero is (3), then (3a+b=0). So (b=-3a) and \(a\neq0\) are needed.

Step 3

Exam Tip

शून्यक (3) होने पर (3a+b=0) होगा। इसलिए (b=-3a) और \(a\neq0\) चाहिए।

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किस विकल्प में (p(x)=ax+b) का शून्यक (-2) होगा?

In which option will (p(x)=ax+b) have zero (-2)?

Explanation opens after your attempt
Correct Answer

A. (b=2a) और \(a\neq0\)(b=2a) and \(a\neq0\)

Step 1

Concept

If the zero is (-2), then (-2a+b=0). So (b=2a) and \(a\neq0\) are needed.

Step 2

Why this answer is correct

The correct answer is A. (b=2a) और \(a\neq0\) / (b=2a) and \(a\neq0\). If the zero is (-2), then (-2a+b=0). So (b=2a) and \(a\neq0\) are needed.

Step 3

Exam Tip

शून्यक (-2) होने पर (-2a+b=0) होगा। इसलिए (b=2a) और \(a\neq0\) चाहिए।

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यदि (p(x)=ax+b) का शून्यक (0) है, तो कौन सी शर्त सही है?

If the zero of (p(x)=ax+b) is (0), which condition is correct?

Explanation opens after your attempt
Correct Answer

B. (b=0) और \(a\neq0\)(b=0) and \(a\neq0\)

Step 1

Concept

If the zero is (0), then (p(0)=b=0). To remain linear, \(a\neq0\) is also necessary.

Step 2

Why this answer is correct

The correct answer is B. (b=0) और \(a\neq0\) / (b=0) and \(a\neq0\). If the zero is (0), then (p(0)=b=0). To remain linear, \(a\neq0\) is also necessary.

Step 3

Exam Tip

शून्यक (0) होने पर (p(0)=b=0) होना चाहिए। रेखीय रहने के लिए \(a\neq0\) भी जरूरी है।

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किस विकल्प में (p(x)=ax+b) का शून्यक (-1) होगा?

In which option will (p(x)=ax+b) have zero (-1)?

Explanation opens after your attempt
Correct Answer

C. (b=a) और \(a\neq0\)(b=a) and \(a\neq0\)

Step 1

Concept

If the zero is (-1), then (-a+b=0). So (b=a) and \(a\neq0\) are needed.

Step 2

Why this answer is correct

The correct answer is C. (b=a) और \(a\neq0\) / (b=a) and \(a\neq0\). If the zero is (-1), then (-a+b=0). So (b=a) and \(a\neq0\) are needed.

Step 3

Exam Tip

शून्यक (-1) होने पर (-a+b=0) होगा। इसलिए (b=a) और \(a\neq0\) चाहिए।

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