किस विकल्प में (p(x)=ax+b) का शून्यक (12) होगा?
In which option will (p(x)=ax+b) have zero (12)?
#polynomial
#linear
#general_condition
A (b=12a) और \(a\neq0\) / (b=12a) and \(a\neq0\)
B (b=-12a) और \(a\neq0\) / (b=-12a) and \(a\neq0\)
C (a=0)
D (b=0)
Explanation opens after your attempt
Correct Answer
B. (b=-12a) और \(a\neq0\) / (b=-12a) and \(a\neq0\)
Step 1
Concept
If the zero is (12), then (12a+b=0). So (b=-12a) and \(a\neq0\) are needed.
Step 2
Why this answer is correct
The correct answer is B. (b=-12a) और \(a\neq0\) / (b=-12a) and \(a\neq0\). If the zero is (12), then (12a+b=0). So (b=-12a) and \(a\neq0\) are needed.
Step 3
Exam Tip
शून्यक (12) होने पर (12a+b=0) होगा। इसलिए (b=-12a) और \(a\neq0\) चाहिए।
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किस विकल्प में (p(x)=ax+b) का शून्यक (-11) होगा?
In which option will (p(x)=ax+b) have zero (-11)?
#polynomial
#linear
#general_condition
A (b=11a) और \(a\neq0\) / (b=11a) and \(a\neq0\)
B (b=-11a) और \(a\neq0\) / (b=-11a) and \(a\neq0\)
C (a=0)
D (b=0)
Explanation opens after your attempt
Correct Answer
A. (b=11a) और \(a\neq0\) / (b=11a) and \(a\neq0\)
Step 1
Concept
If the zero is (-11), then (-11a+b=0). So (b=11a) and \(a\neq0\) are needed.
Step 2
Why this answer is correct
The correct answer is A. (b=11a) और \(a\neq0\) / (b=11a) and \(a\neq0\). If the zero is (-11), then (-11a+b=0). So (b=11a) and \(a\neq0\) are needed.
Step 3
Exam Tip
शून्यक (-11) होने पर (-11a+b=0) होगा। इसलिए (b=11a) और \(a\neq0\) चाहिए।
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किस विकल्प में (p(x)=ax+b) का शून्यक (10) होगा?
In which option will (p(x)=ax+b) have zero (10)?
#polynomial
#linear
#general_condition
A (b=10a) और \(a\neq0\) / (b=10a) and \(a\neq0\)
B (b=-10a) और \(a\neq0\) / (b=-10a) and \(a\neq0\)
C (a=0)
D (b=0)
Explanation opens after your attempt
Correct Answer
B. (b=-10a) और \(a\neq0\) / (b=-10a) and \(a\neq0\)
Step 1
Concept
If the zero is (10), then (10a+b=0). So (b=-10a) and \(a\neq0\) are needed.
Step 2
Why this answer is correct
The correct answer is B. (b=-10a) और \(a\neq0\) / (b=-10a) and \(a\neq0\). If the zero is (10), then (10a+b=0). So (b=-10a) and \(a\neq0\) are needed.
Step 3
Exam Tip
शून्यक (10) होने पर (10a+b=0) होगा। इसलिए (b=-10a) और \(a\neq0\) चाहिए।
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किस विकल्प में (p(x)=ax+b) का शून्यक (-9) होगा?
In which option will (p(x)=ax+b) have zero (-9)?
#polynomial
#linear
#general_condition
A (b=9a) और \(a\neq0\) / (b=9a) and \(a\neq0\)
B (b=-9a) और \(a\neq0\) / (b=-9a) and \(a\neq0\)
C (a=0)
D (b=0)
Explanation opens after your attempt
Correct Answer
A. (b=9a) और \(a\neq0\) / (b=9a) and \(a\neq0\)
Step 1
Concept
If the zero is (-9), then (-9a+b=0). So (b=9a) and \(a\neq0\) are needed.
Step 2
Why this answer is correct
The correct answer is A. (b=9a) और \(a\neq0\) / (b=9a) and \(a\neq0\). If the zero is (-9), then (-9a+b=0). So (b=9a) and \(a\neq0\) are needed.
Step 3
Exam Tip
शून्यक (-9) होने पर (-9a+b=0) होगा। इसलिए (b=9a) और \(a\neq0\) चाहिए।
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किस विकल्प में (p(x)=ax+b) का शून्यक (8) होगा?
In which option will (p(x)=ax+b) have zero (8)?
#polynomial
#linear
#general_condition
A (b=8a) और \(a\neq0\) / (b=8a) and \(a\neq0\)
B (b=-8a) और \(a\neq0\) / (b=-8a) and \(a\neq0\)
C (a=0)
D (b=0)
Explanation opens after your attempt
Correct Answer
B. (b=-8a) और \(a\neq0\) / (b=-8a) and \(a\neq0\)
Step 1
Concept
If the zero is (8), then (8a+b=0). So (b=-8a) and \(a\neq0\) are needed.
Step 2
Why this answer is correct
The correct answer is B. (b=-8a) और \(a\neq0\) / (b=-8a) and \(a\neq0\). If the zero is (8), then (8a+b=0). So (b=-8a) and \(a\neq0\) are needed.
Step 3
Exam Tip
शून्यक (8) होने पर (8a+b=0) होगा। इसलिए (b=-8a) और \(a\neq0\) चाहिए।
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यदि (p(x)=ax+b) का शून्यक (0) है और (p(x)) रेखीय है, तो कौन सी शर्त जरूरी है?
If the zero of (p(x)=ax+b) is (0) and (p(x)) is linear, which condition is necessary?
#polynomial
#linear
#general_condition
A (a=0) और (b=0) / (a=0) and (b=0)
B (b=0) और \(a\neq0\) / (b=0) and \(a\neq0\)
C \(a=b\neq0\)
D (b=1)
Explanation opens after your attempt
Correct Answer
B. (b=0) और \(a\neq0\) / (b=0) and \(a\neq0\)
Step 1
Concept
If the zero is (0), then (p(0)=b=0). To remain linear, \(a\neq0\) is also necessary.
Step 2
Why this answer is correct
The correct answer is B. (b=0) और \(a\neq0\) / (b=0) and \(a\neq0\). If the zero is (0), then (p(0)=b=0). To remain linear, \(a\neq0\) is also necessary.
Step 3
Exam Tip
शून्यक (0) होने पर (p(0)=b=0) होना चाहिए। रेखीय रहने के लिए \(a\neq0\) भी जरूरी है।
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किस विकल्प में (p(x)=ax+b) का शून्यक (-7) होगा?
In which option will (p(x)=ax+b) have zero (-7)?
#polynomial
#linear
#general_condition
A (b=7a) और \(a\neq0\) / (b=7a) and \(a\neq0\)
B (b=-7a) और \(a\neq0\) / (b=-7a) and \(a\neq0\)
C (a=0)
D (b=0)
Explanation opens after your attempt
Correct Answer
A. (b=7a) और \(a\neq0\) / (b=7a) and \(a\neq0\)
Step 1
Concept
If the zero is (-7), then (-7a+b=0). So (b=7a) and \(a\neq0\) are needed.
Step 2
Why this answer is correct
The correct answer is A. (b=7a) और \(a\neq0\) / (b=7a) and \(a\neq0\). If the zero is (-7), then (-7a+b=0). So (b=7a) and \(a\neq0\) are needed.
Step 3
Exam Tip
शून्यक (-7) होने पर (-7a+b=0) होगा। इसलिए (b=7a) और \(a\neq0\) चाहिए।
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किस विकल्प में (p(x)=ax+b) का शून्यक (6) होगा?
In which option will (p(x)=ax+b) have zero (6)?
#polynomial
#linear
#general_condition
A (b=6a) और \(a\neq0\) / (b=6a) and \(a\neq0\)
B (a=0)
C (b=0)
D (b=-6a) और \(a\neq0\) / (b=-6a) and \(a\neq0\)
Explanation opens after your attempt
Correct Answer
D. (b=-6a) और \(a\neq0\) / (b=-6a) and \(a\neq0\)
Step 1
Concept
If the zero is (6), then (6a+b=0). So (b=-6a) and \(a\neq0\) are needed.
Step 2
Why this answer is correct
The correct answer is D. (b=-6a) और \(a\neq0\) / (b=-6a) and \(a\neq0\). If the zero is (6), then (6a+b=0). So (b=-6a) and \(a\neq0\) are needed.
Step 3
Exam Tip
शून्यक (6) होने पर (6a+b=0) होगा। इसलिए (b=-6a) और \(a\neq0\) चाहिए।
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यदि (p(x)=ax+b) का शून्यक (0) है और (p(x)) रेखीय है, तो कौन सी शर्त सही है?
If the zero of (p(x)=ax+b) is (0) and (p(x)) is linear, which condition is correct?
#polynomial
#linear
#general_condition
A (a=0) और (b=0) / (a=0) and (b=0)
B \(a=b\neq0\)
C (b=1)
D (b=0) और \(a\neq0\) / (b=0) and \(a\neq0\)
Explanation opens after your attempt
Correct Answer
D. (b=0) और \(a\neq0\) / (b=0) and \(a\neq0\)
Step 1
Concept
If the zero is (0), then (p(0)=b=0). To remain linear, \(a\neq0\) is also necessary.
Step 2
Why this answer is correct
The correct answer is D. (b=0) और \(a\neq0\) / (b=0) and \(a\neq0\). If the zero is (0), then (p(0)=b=0). To remain linear, \(a\neq0\) is also necessary.
Step 3
Exam Tip
शून्यक (0) होने पर (p(0)=b=0) होना चाहिए। रेखीय रहने के लिए \(a\neq0\) भी जरूरी है।
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किस विकल्प में (p(x)=ax+b) का शून्यक (-5) होगा?
In which option will (p(x)=ax+b) have zero (-5)?
#polynomial
#linear
#general_condition
A (b=5a) और \(a\neq0\) / (b=5a) and \(a\neq0\)
B (b=-5a) और \(a\neq0\) / (b=-5a) and \(a\neq0\)
C (a=0)
D (b=0)
Explanation opens after your attempt
Correct Answer
A. (b=5a) और \(a\neq0\) / (b=5a) and \(a\neq0\)
Step 1
Concept
If the zero is (-5), then (-5a+b=0). So (b=5a) and \(a\neq0\) are needed.
Step 2
Why this answer is correct
The correct answer is A. (b=5a) और \(a\neq0\) / (b=5a) and \(a\neq0\). If the zero is (-5), then (-5a+b=0). So (b=5a) and \(a\neq0\) are needed.
Step 3
Exam Tip
शून्यक (-5) होने पर (-5a+b=0) होगा। इसलिए (b=5a) और \(a\neq0\) चाहिए।
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किस विकल्प में (p(x)=ax+b) का शून्यक (4) होगा?
In which option will (p(x)=ax+b) have zero (4)?
#polynomial
#linear
#general_condition
A (b=4a) और \(a\neq0\) / (b=4a) and \(a\neq0\)
B (b=-4a) और \(a\neq0\) / (b=-4a) and \(a\neq0\)
C (a=0)
D (b=0)
Explanation opens after your attempt
Correct Answer
B. (b=-4a) और \(a\neq0\) / (b=-4a) and \(a\neq0\)
Step 1
Concept
If the zero is (4), then (4a+b=0). So (b=-4a) and \(a\neq0\) are needed.
Step 2
Why this answer is correct
The correct answer is B. (b=-4a) और \(a\neq0\) / (b=-4a) and \(a\neq0\). If the zero is (4), then (4a+b=0). So (b=-4a) and \(a\neq0\) are needed.
Step 3
Exam Tip
शून्यक (4) होने पर (4a+b=0) होगा। इसलिए (b=-4a) और \(a\neq0\) चाहिए।
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यदि (p(x)=ax+b) का शून्यक (0) है और बहुपद रेखीय है, तो कौन सी शर्त सही है?
If the zero of (p(x)=ax+b) is (0) and the polynomial is linear, which condition is correct?
#polynomial
#linear
#general_condition
A (a=0) और (b=0) / (a=0) and (b=0)
B (b=0) और \(a\neq0\) / (b=0) and \(a\neq0\)
C \(a=b\neq0\)
D (b=1)
Explanation opens after your attempt
Correct Answer
B. (b=0) और \(a\neq0\) / (b=0) and \(a\neq0\)
Step 1
Concept
If the zero is (0), then (p(0)=b=0). To remain linear, \(a\neq0\) is also necessary.
Step 2
Why this answer is correct
The correct answer is B. (b=0) और \(a\neq0\) / (b=0) and \(a\neq0\). If the zero is (0), then (p(0)=b=0). To remain linear, \(a\neq0\) is also necessary.
Step 3
Exam Tip
शून्यक (0) होने पर (p(0)=b=0) होना चाहिए। रेखीय रहने के लिए \(a\neq0\) भी जरूरी है।
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किस विकल्प में (p(x)=ax+b) का शून्यक (3) होगा?
In which option will (p(x)=ax+b) have zero (3)?
#polynomial
#linear
#general_condition
A (b=-3a) और \(a\neq0\) / (b=-3a) and \(a\neq0\)
B (b=3a) और \(a\neq0\) / (b=3a) and \(a\neq0\)
C (a=0)
D (b=0)
Explanation opens after your attempt
Correct Answer
A. (b=-3a) और \(a\neq0\) / (b=-3a) and \(a\neq0\)
Step 1
Concept
If the zero is (3), then (3a+b=0). So (b=-3a) and \(a\neq0\) are needed.
Step 2
Why this answer is correct
The correct answer is A. (b=-3a) और \(a\neq0\) / (b=-3a) and \(a\neq0\). If the zero is (3), then (3a+b=0). So (b=-3a) and \(a\neq0\) are needed.
Step 3
Exam Tip
शून्यक (3) होने पर (3a+b=0) होगा। इसलिए (b=-3a) और \(a\neq0\) चाहिए।
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किस विकल्प में (p(x)=ax+b) का शून्यक (-2) होगा?
In which option will (p(x)=ax+b) have zero (-2)?
#polynomial
#linear
#general_condition
A (b=2a) और \(a\neq0\) / (b=2a) and \(a\neq0\)
B (b=-2a) और \(a\neq0\) / (b=-2a) and \(a\neq0\)
C (a=0)
D (b=0)
Explanation opens after your attempt
Correct Answer
A. (b=2a) और \(a\neq0\) / (b=2a) and \(a\neq0\)
Step 1
Concept
If the zero is (-2), then (-2a+b=0). So (b=2a) and \(a\neq0\) are needed.
Step 2
Why this answer is correct
The correct answer is A. (b=2a) और \(a\neq0\) / (b=2a) and \(a\neq0\). If the zero is (-2), then (-2a+b=0). So (b=2a) and \(a\neq0\) are needed.
Step 3
Exam Tip
शून्यक (-2) होने पर (-2a+b=0) होगा। इसलिए (b=2a) और \(a\neq0\) चाहिए।
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यदि (p(x)=ax+b) का शून्यक (0) है, तो कौन सी शर्त सही है?
If the zero of (p(x)=ax+b) is (0), which condition is correct?
#polynomial
#linear
#general_condition
A (a=0)
B (b=0) और \(a\neq0\) / (b=0) and \(a\neq0\)
C (a=b)
D (b=1)
Explanation opens after your attempt
Correct Answer
B. (b=0) और \(a\neq0\) / (b=0) and \(a\neq0\)
Step 1
Concept
If the zero is (0), then (p(0)=b=0). To remain linear, \(a\neq0\) is also necessary.
Step 2
Why this answer is correct
The correct answer is B. (b=0) और \(a\neq0\) / (b=0) and \(a\neq0\). If the zero is (0), then (p(0)=b=0). To remain linear, \(a\neq0\) is also necessary.
Step 3
Exam Tip
शून्यक (0) होने पर (p(0)=b=0) होना चाहिए। रेखीय रहने के लिए \(a\neq0\) भी जरूरी है।
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किस विकल्प में (p(x)=ax+b) का शून्यक (-1) होगा?
In which option will (p(x)=ax+b) have zero (-1)?
#polynomial
#linear
#general_condition
A (a=b)
B (b=0)
C (b=a) और \(a\neq0\) / (b=a) and \(a\neq0\)
D (a=0)
Explanation opens after your attempt
Correct Answer
C. (b=a) और \(a\neq0\) / (b=a) and \(a\neq0\)
Step 1
Concept
If the zero is (-1), then (-a+b=0). So (b=a) and \(a\neq0\) are needed.
Step 2
Why this answer is correct
The correct answer is C. (b=a) और \(a\neq0\) / (b=a) and \(a\neq0\). If the zero is (-1), then (-a+b=0). So (b=a) and \(a\neq0\) are needed.
Step 3
Exam Tip
शून्यक (-1) होने पर (-a+b=0) होगा। इसलिए (b=a) और \(a\neq0\) चाहिए।
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