If (p(x)=mx+n), (p(0)=-4) and (p(3)=11), what is (m+n)?
Answer and explanation
Correct answer: \(1\)
Given \(p(x)=mx+n\). Substituting \(x=0\) gives \(p(0)=n=-4\). Next, substituting \(x=3\) gives \(3m+n=11\). Using \(n=-4\), we get \(3m-4=11\), so \(m=5\). Hence, \(m+n=5+(-4)=1\). Option \(5\) is only the value of \(m\), not of \(m+n\). Exam tip: In such questions, put \(x=0\) first to find the constant term \(n\) quickly.
Frequently asked questions
What is the correct answer to this question?
\(1\)
Why is this the correct answer?
Given \(p(x)=mx+n\). Substituting \(x=0\) gives \(p(0)=n=-4\). Next, substituting \(x=3\) gives \(3m+n=11\). Using \(n=-4\), we get \(3m-4=11\), so \(m=5\). Hence, \(m+n=5+(-4)=1\). Option \(5\) is only the value of \(m\), not of \(m+n\). Exam tip: In such questions, put \(x=0\) first to find the constant term \(n\) quickly.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear polynomials.
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