किस मान पर ((n+6)x+4n-3) का शून्यक (1) होगा?
For which value will the zero of ((n+6)x+4n-3) be (1)?
Explanation opens after your attempt
A. \(n=-\frac{3}{5}\)
Concept
If the zero is (1), then (n+6+4n-3=0). Thus (5n+3=0) and \(n=-\frac{3}{5}\).
Why this answer is correct
The correct answer is A. \(n=-\frac{3}{5}\). If the zero is (1), then (n+6+4n-3=0). Thus (5n+3=0) and \(n=-\frac{3}{5}\).
Exam Tip
शून्यक (1) होने पर (n+6+4n-3=0) होगा। इससे (5n+3=0) और \(n=-\frac{3}{5}\) मिलता है।
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