Concept-wise Practice

equal-roots MCQ Questions for Class 10

equal-roots se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

92 questions tagged with equal-roots.

Question 61/92 Medium Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

समीकरण \(3x^2-6x+3=0\) का डिस्क्रिमिनेंट (D) क्या है?

What is the discriminant (D) of \(3x^2-6x+3=0\)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

Here \(D=b^2-4ac=36-36=0\). Therefore the two real roots will be equal.

Step 2

Why this answer is correct

The correct answer is A. (0). Here \(D=b^2-4ac=36-36=0\). Therefore the two real roots will be equal.

Step 3

Exam Tip

यहां \(D=b^2-4ac=36-36=0\) है। इसलिए दोनों वास्तविक मूल बराबर होंगे।

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Question 62/92 Medium Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

यदि \(x^2+ax+9=0\) के मूल (3) और (3) हैं तो (a) का मान क्या है?

If the roots of \(x^2+ax+9=0\) are (3) and (3), what is the value of (a)?

Explanation opens after your attempt
Correct Answer

A. (-6)

Step 1

Concept

The sum of roots is (6), and (-a=6). Therefore (a=-6).

Step 2

Why this answer is correct

The correct answer is A. (-6). The sum of roots is (6), and (-a=6). Therefore (a=-6).

Step 3

Exam Tip

मूलों का योग (6) है और (-a=6) होगा। इसलिए (a=-6) है।

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Question 63/92 Medium Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

यदि (D=0) और मूलों का योग (10) है तो प्रत्येक मूल क्या होगा?

If (D=0) and the sum of roots is (10), what will each root be?

Explanation opens after your attempt
Correct Answer

A. (5)

Step 1

Concept

When (D=0), both roots are equal. Therefore each root is \(\frac{10}{2}=5\).

Step 2

Why this answer is correct

The correct answer is A. (5). When (D=0), both roots are equal. Therefore each root is \(\frac{10}{2}=5\).

Step 3

Exam Tip

(D=0) होने पर दोनों मूल बराबर होते हैं। इसलिए प्रत्येक मूल \(\frac{10}{2}=5\) होगा।

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Question 64/92 Medium Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

समीकरण \(x^2+px+16=0\) के दोनों मूल (-4) और (-4) हैं तो (p) का मान क्या है?

If both roots of \(x^2+px+16=0\) are (-4) and (-4), what is the value of (p)?

Explanation opens after your attempt
Correct Answer

A. (8)

Step 1

Concept

The sum of roots is (-8), and (-p=-8). Therefore (p=8).

Step 2

Why this answer is correct

The correct answer is A. (8). The sum of roots is (-8), and (-p=-8). Therefore (p=8).

Step 3

Exam Tip

मूलों का योग (-8) है और (-p=-8) होगा। इसलिए (p=8) है।

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Question 65/92 Medium Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

समीकरण \(x^2-6x+k=0\) के बराबर वास्तविक मूल होने के लिए (k) का मान क्या होगा?

For \(x^2-6x+k=0\) to have equal real roots, what should be the value of (k)?

Explanation opens after your attempt
Correct Answer

A. (9)

Step 1

Concept

For equal roots (D=0). From (36-4k=0), we get (k=9).

Step 2

Why this answer is correct

The correct answer is A. (9). For equal roots (D=0). From (36-4k=0), we get (k=9).

Step 3

Exam Tip

बराबर मूलों के लिए (D=0) होता है। (36-4k=0) से (k=9) मिलता है।

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Question 66/92 Medium Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

समीकरण \(2x^2-4x+2=0\) का डिस्क्रिमिनेंट (D) क्या है?

What is the discriminant (D) of \(2x^2-4x+2=0\)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

Here \(D=b^2-4ac=16-16=0\). Therefore the two real roots will be equal.

Step 2

Why this answer is correct

The correct answer is A. (0). Here \(D=b^2-4ac=16-16=0\). Therefore the two real roots will be equal.

Step 3

Exam Tip

यहां \(D=b^2-4ac=16-16=0\) है। इसलिए दोनों वास्तविक मूल बराबर होंगे।

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Question 67/92 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

यदि किसी मोनिक द्विघात समीकरण के दोनों मूल (5) और (5) हैं तो समीकरण कौन सा है?

If both roots of a monic quadratic equation are (5) and (5), which equation is it?

Explanation opens after your attempt
Correct Answer

A. \(x^2-10x+25=0\)

Step 1

Concept

If both roots are (5), the equation is ((x-5)2=0). Expanding it gives \(x^2-10x+25=0\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2-10x+25=0\). If both roots are (5), the equation is ((x-5)2=0). Expanding it gives \(x^2-10x+25=0\).

Step 3

Exam Tip

दोनों मूल (5) हों तो समीकरण ((x-5)2=0) होगा। इसे खोलने पर \(x^2-10x+25=0\) मिलता है।

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Question 68/92 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

यदि किसी द्विघात समीकरण के मूल (r) और (r) हैं तो उनके गुणनफल का मान क्या होगा?

If the roots of a quadratic equation are (r) and (r), what will be their product?

Explanation opens after your attempt
Correct Answer

C. \(r^2\)

Step 1

Concept

The product of (r) and (r) is \(r^2\). For equal roots, remember sum (2r) and product \(r^2\).

Step 2

Why this answer is correct

The correct answer is C. \(r^2\). The product of (r) and (r) is \(r^2\). For equal roots, remember sum (2r) and product \(r^2\).

Step 3

Exam Tip

(r) और (r) का गुणनफल \(r^2\) होता है। बराबर मूलों में योग (2r) और गुणनफल \(r^2\) याद रखें।

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Question 69/92 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

यदि (D=0) है तो द्विघात समीकरण के वास्तविक मूल कैसे होते हैं?

If (D=0), how are the real roots of a quadratic equation?

Explanation opens after your attempt
Correct Answer

B. दो बराबर वास्तविक मूलTwo equal real roots

Step 1

Concept

When (D=0), the two real roots are equal. Check \(D=b^2-4ac\) for the nature of roots.

Step 2

Why this answer is correct

The correct answer is B. दो बराबर वास्तविक मूल / Two equal real roots. When (D=0), the two real roots are equal. Check \(D=b^2-4ac\) for the nature of roots.

Step 3

Exam Tip

(D=0) होने पर दोनों वास्तविक मूल बराबर होते हैं। मूलों की प्रकृति के लिए \(D=b^2-4ac\) देखें।

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Question 70/92 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

यदि किसी मोनिक द्विघात समीकरण के दोनों मूल (-4) और (-4) हैं तो समीकरण कौन सा है?

If both roots of a monic quadratic equation are (-4) and (-4), which equation is it?

Explanation opens after your attempt
Correct Answer

A. \(x^2+8x+16=0\)

Step 1

Concept

If both roots are (-4), the equation is ((x+4)2=0). Expanding it gives \(x^2+8x+16=0\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2+8x+16=0\). If both roots are (-4), the equation is ((x+4)2=0). Expanding it gives \(x^2+8x+16=0\).

Step 3

Exam Tip

दोनों मूल (-4) हों तो समीकरण ((x+4)2=0) होगा। इसे खोलने पर \(x^2+8x+16=0\) मिलता है।

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Question 71/92 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

यदि किसी मोनिक द्विघात समीकरण के दोनों मूल (7) और (7) हैं तो समीकरण कौन सा है?

If both roots of a monic quadratic equation are (7) and (7) then which equation is it?

Explanation opens after your attempt
Correct Answer

A. \(x^2-14x+49=0\)

Step 1

Concept

With both roots (7) we get ((x-7)2=0) which is \(x^2-14x+49=0\). Form a perfect square from repeated roots.

Step 2

Why this answer is correct

The correct answer is A. \(x^2-14x+49=0\). With both roots (7) we get ((x-7)2=0) which is \(x^2-14x+49=0\). Form a perfect square from repeated roots.

Step 3

Exam Tip

दोनों मूल (7) होने पर ((x-7)2=0) मिलता है जो \(x^2-14x+49=0\) है। दोहराए मूल से पूर्ण वर्ग बनाएं।

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Question 72/92 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

यदि किसी द्विघात समीकरण के दो बराबर वास्तविक मूल हों तो डिस्क्रिमिनेंट (D) का मान कैसा होता है?

If a quadratic equation has two equal real roots then what is the value of discriminant (D)?

Explanation opens after your attempt
Correct Answer

B. (D=0)

Step 1

Concept

For equal real roots (D=0). The discriminant quickly tells the nature of roots.

Step 2

Why this answer is correct

The correct answer is B. (D=0). For equal real roots (D=0). The discriminant quickly tells the nature of roots.

Step 3

Exam Tip

बराबर वास्तविक मूलों के लिए (D=0) होता है। डिस्क्रिमिनेंट से मूलों की प्रकृति जल्दी पता चलती है।

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Question 73/92 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

यदि समीकरण \(x^2+bx+144=0\) के दोनों मूल समान हैं और उनका मान (-12) है, तो (b) क्या है?

If both roots of \(x^2+bx+144=0\) are equal and their value is (-12), what is (b)?

Explanation opens after your attempt
Correct Answer

A. (24)

Step 1

Concept

Both roots are (-12), so the sum is (-24). Here the sum of roots is (-b), so (b=24).

Step 2

Why this answer is correct

The correct answer is A. (24). Both roots are (-12), so the sum is (-24). Here the sum of roots is (-b), so (b=24).

Step 3

Exam Tip

दोनों मूल (-12) हैं, इसलिए योग (-24) है। यहाँ मूलों का योग (-b) है, अतः (b=24)।

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Question 74/92 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

यदि \(x^2-2mx+64=0\) के मूल समान हैं, तो (m) के संभावित मान क्या हैं?

If the roots of \(x^2-2mx+64=0\) are equal, what are the possible values of (m)?

Explanation opens after your attempt
Correct Answer

A. \(m=\pm8\)

Step 1

Concept

For equal roots, (D=0) is needed. Here ((-2m)2-256=0), so \(m=\pm8\).

Step 2

Why this answer is correct

The correct answer is A. \(m=\pm8\). For equal roots, (D=0) is needed. Here ((-2m)2-256=0), so \(m=\pm8\).

Step 3

Exam Tip

समान मूलों के लिए (D=0) चाहिए। यहाँ ((-2m)2-256=0), इसलिए \(m=\pm8\)।

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Question 75/92 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

यदि समीकरण \(x^2+bx+100=0\) के दोनों मूल समान हैं और उनका मान (-10) है, तो (b) क्या है?

If both roots of \(x^2+bx+100=0\) are equal and their value is (-10), what is (b)?

Explanation opens after your attempt
Correct Answer

A. (20)

Step 1

Concept

Both roots are (-10), so the sum is (-20). Here the sum of roots is (-b), so (b=20).

Step 2

Why this answer is correct

The correct answer is A. (20). Both roots are (-10), so the sum is (-20). Here the sum of roots is (-b), so (b=20).

Step 3

Exam Tip

दोनों मूल (-10) हैं, इसलिए योग (-20) है। यहाँ मूलों का योग (-b) है, अतः (b=20)।

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Question 76/92 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

यदि \(x^2-2mx+49=0\) के मूल समान हैं, तो (m) के संभावित मान क्या हैं?

If the roots of \(x^2-2mx+49=0\) are equal, what are the possible values of (m)?

Explanation opens after your attempt
Correct Answer

A. \(m=\pm7\)

Step 1

Concept

For equal roots, (D=0) is needed. Here ((-2m)2-196=0), so \(m=\pm7\).

Step 2

Why this answer is correct

The correct answer is A. \(m=\pm7\). For equal roots, (D=0) is needed. Here ((-2m)2-196=0), so \(m=\pm7\).

Step 3

Exam Tip

समान मूलों के लिए (D=0) चाहिए। यहाँ ((-2m)2-196=0), इसलिए \(m=\pm7\)।

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Question 77/92 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

यदि समीकरण \(x^2+bx+64=0\) के दोनों मूल समान हैं और उनका मान (-8) है, तो (b) क्या है?

If both roots of \(x^2+bx+64=0\) are equal and their value is (-8), what is (b)?

Explanation opens after your attempt
Correct Answer

A. (16)

Step 1

Concept

Both roots are (-8), so the sum is (-16). Here the sum of roots is (-b), so (b=16).

Step 2

Why this answer is correct

The correct answer is A. (16). Both roots are (-8), so the sum is (-16). Here the sum of roots is (-b), so (b=16).

Step 3

Exam Tip

दोनों मूल (-8) हैं, इसलिए योग (-16) है। यहाँ मूलों का योग (-b) है, अतः (b=16)।

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Question 78/92 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

यदि \(x^2-2mx+36=0\) के मूल समान हैं, तो (m) के संभावित मान क्या हैं?

If the roots of \(x^2-2mx+36=0\) are equal, what are the possible values of (m)?

Explanation opens after your attempt
Correct Answer

A. \(m=\pm6\)

Step 1

Concept

For equal roots, (D=0), so ((-2m)2-144=0). This gives \(m^2=36\) and \(m=\pm6\).

Step 2

Why this answer is correct

The correct answer is A. \(m=\pm6\). For equal roots, (D=0), so ((-2m)2-144=0). This gives \(m^2=36\) and \(m=\pm6\).

Step 3

Exam Tip

समान मूलों के लिए (D=0), अतः ((-2m)2-144=0) होगा। इससे \(m^2=36\) और \(m=\pm6\) है।

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Question 79/92 Hard Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

यदि समीकरण \(x^2+bx+49=0\) के दोनों मूल समान हैं और उनका मान (-7) है, तो (b) क्या है?

If both roots of \(x^2+bx+49=0\) are equal and their value is (-7), what is (b)?

Explanation opens after your attempt
Correct Answer

A. (14)

Step 1

Concept

Both roots are (-7), so their sum is (-14). Here the sum of roots is (-b), so (b=14).

Step 2

Why this answer is correct

The correct answer is A. (14). Both roots are (-7), so their sum is (-14). Here the sum of roots is (-b), so (b=14).

Step 3

Exam Tip

दोनों मूल (-7) हैं, इसलिए योग (-14) है। यहाँ मूलों का योग (-b) है, अतः (b=14)।

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Question 80/92 Hard Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

यदि \(x^2-2kx+25=0\) के मूल समान हैं, तो (k) के संभावित मान क्या हैं?

If the roots of \(x^2-2kx+25=0\) are equal, what are the possible values of (k)?

Explanation opens after your attempt
Correct Answer

A. \(k=\pm5\)

Step 1

Concept

For equal roots, (D=0), so ((-2k)2-100=0). This gives \(k^2=25\) and \(k=\pm5\).

Step 2

Why this answer is correct

The correct answer is A. \(k=\pm5\). For equal roots, (D=0), so ((-2k)2-100=0). This gives \(k^2=25\) and \(k=\pm5\).

Step 3

Exam Tip

समान मूलों के लिए (D=0), इसलिए ((-2k)2-100=0) मिलता है। इससे \(k^2=25\) और \(k=\pm5\) है।

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Question 81/92 Hard Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

यदि समीकरण \(x^2+bx+25=0\) के दोनों मूल समान हैं और उनका मान (-5) है, तो (b) क्या है?

If both roots of \(x^2+bx+25=0\) are equal and their value is (-5), what is (b)?

Explanation opens after your attempt
Correct Answer

A. (10)

Step 1

Concept

Both roots are (-5), so their sum is (-10). Here the sum of roots is (-b), so (b=10).

Step 2

Why this answer is correct

The correct answer is A. (10). Both roots are (-5), so their sum is (-10). Here the sum of roots is (-b), so (b=10).

Step 3

Exam Tip

दोनों मूल (-5) हैं, इसलिए योग (-10) है। यहाँ मूलों का योग (-b) है, अतः (b=10)।

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Question 82/92 Hard Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

यदि \(x^2-2kx+16=0\) के मूल समान हैं, तो (k) के संभावित मान क्या हैं?

If the roots of \(x^2-2kx+16=0\) are equal, what are the possible values of (k)?

Explanation opens after your attempt
Correct Answer

A. \(k=\pm4\)

Step 1

Concept

For equal roots, (D=0), so ((-2k)2-64=0). This gives \(k^2=16\) and \(k=\pm4\).

Step 2

Why this answer is correct

The correct answer is A. \(k=\pm4\). For equal roots, (D=0), so ((-2k)2-64=0). This gives \(k^2=16\) and \(k=\pm4\).

Step 3

Exam Tip

समान मूलों के लिए (D=0), इसलिए ((-2k)2-64=0) मिलता है। इससे \(k^2=16\) और \(k=\pm4\) है।

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Question 83/92 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

यदि द्विघात समीकरण \(x^2-18x+k=0\) के मूल समान हैं, तो (k) क्या होगा?

If the roots of \(x^2-18x+k=0\) are equal, what is (k)?

Explanation opens after your attempt
Correct Answer

B. (81)

Step 1

Concept

For equal roots, (D=0), so (324-4k=0) and (k=81). For equal roots, set the discriminant to zero.

Step 2

Why this answer is correct

The correct answer is B. (81). For equal roots, (D=0), so (324-4k=0) and (k=81). For equal roots, set the discriminant to zero.

Step 3

Exam Tip

समान मूलों के लिए (D=0), इसलिए (324-4k=0) और (k=81)। समान मूल की शर्त में विवेचक शून्य रखें।

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Question 84/92 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

यदि \(x^2+ux+64=0\) के मूल (8) और (8) हैं, तो (u) का मान क्या होगा?

If the roots of \(x^2+ux+64=0\) are (8) and (8), what is the value of (u)?

Explanation opens after your attempt
Correct Answer

B. (-16)

Step 1

Concept

The sum of roots is (16), and in \(x^2+ux+64=0\), the sum is (-u). Therefore (u=-16).

Step 2

Why this answer is correct

The correct answer is B. (-16). The sum of roots is (16), and in \(x^2+ux+64=0\), the sum is (-u). Therefore (u=-16).

Step 3

Exam Tip

मूलों का योग (16) है और \(x^2+ux+64=0\) में योग (-u) होता है। इसलिए (u=-16) है।

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Question 85/92 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

समीकरण \(25x^2-20x+4=0\) का विवेचक (D) क्या है?

What is the discriminant (D) of \(25x^2-20x+4=0\)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

Here (D=(-20)2-4\cdot25\cdot4=400-400=0). (D=0) indicates equal roots.

Step 2

Why this answer is correct

The correct answer is A. (0). Here (D=(-20)2-4\cdot25\cdot4=400-400=0). (D=0) indicates equal roots.

Step 3

Exam Tip

यहाँ (D=(-20)2-4\cdot25\cdot4=400-400=0) है। (D=0) समान मूलों का संकेत देता है।

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Question 86/92 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

यदि द्विघात समीकरण \(x^2-14x+k=0\) के मूल समान हैं, तो (k) क्या होगा?

If the roots of \(x^2-14x+k=0\) are equal, what is (k)?

Explanation opens after your attempt
Correct Answer

B. (49)

Step 1

Concept

For equal roots, (D=0), so (196-4k=0) and (k=49). For equal roots, set the discriminant to zero.

Step 2

Why this answer is correct

The correct answer is B. (49). For equal roots, (D=0), so (196-4k=0) and (k=49). For equal roots, set the discriminant to zero.

Step 3

Exam Tip

समान मूलों के लिए (D=0), इसलिए (196-4k=0) और (k=49)। समान मूल की शर्त में विवेचक शून्य रखें।

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Question 87/92 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

यदि \(x^2+rx+36=0\) के मूल (6) और (6) हैं, तो (r) का मान क्या होगा?

If the roots of \(x^2+rx+36=0\) are (6) and (6), what is the value of (r)?

Explanation opens after your attempt
Correct Answer

B. (-12)

Step 1

Concept

The sum of roots is (12), and in \(x^2+rx+36=0\) the sum is (-r). Therefore (r=-12).

Step 2

Why this answer is correct

The correct answer is B. (-12). The sum of roots is (12), and in \(x^2+rx+36=0\) the sum is (-r). Therefore (r=-12).

Step 3

Exam Tip

मूलों का योग (12) है और \(x^2+rx+36=0\) में योग (-r) होता है। इसलिए (r=-12) है।

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Question 88/92 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

समीकरण \(9x^2-12x+4=0\) का विवेचक (D) क्या है?

What is the discriminant (D) of \(9x^2-12x+4=0\)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

Here (D=(-12)2-4\cdot9\cdot4=144-144=0). Even if (b) is negative, \(b^2\) is positive.

Step 2

Why this answer is correct

The correct answer is A. (0). Here (D=(-12)2-4\cdot9\cdot4=144-144=0). Even if (b) is negative, \(b^2\) is positive.

Step 3

Exam Tip

यहाँ (D=(-12)2-4\cdot9\cdot4=144-144=0) है। (b) ऋणात्मक हो तो भी \(b^2\) धनात्मक होता है।

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Question 89/92 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

यदि द्विघात समीकरण \(x^2-6x+k=0\) के मूल समान हैं, तो (k) क्या होगा?

If the roots of \(x^2-6x+k=0\) are equal, what is (k)?

Explanation opens after your attempt
Correct Answer

B. (9)

Step 1

Concept

For equal roots, (D=0), so (36-4k=0) and (k=9). Set the discriminant to zero for equal roots.

Step 2

Why this answer is correct

The correct answer is B. (9). For equal roots, (D=0), so (36-4k=0) and (k=9). Set the discriminant to zero for equal roots.

Step 3

Exam Tip

समान मूलों के लिए (D=0), इसलिए (36-4k=0) और (k=9)। समान मूल की शर्त में विवेचक शून्य रखें।

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Question 90/92 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

यदि \(x^2+px+16=0\) के मूल (4) और (4) हैं, तो (p) का मान क्या होगा?

If the roots of \(x^2+px+16=0\) are (4) and (4), what is the value of (p)?

Explanation opens after your attempt
Correct Answer

B. (-8)

Step 1

Concept

The sum of roots is (8), and in \(x^2+px+16=0\) the sum is (-p). Therefore (p=-8).

Step 2

Why this answer is correct

The correct answer is B. (-8). The sum of roots is (8), and in \(x^2+px+16=0\) the sum is (-p). Therefore (p=-8).

Step 3

Exam Tip

मूलों का योग (8) है और \(x^2+px+16=0\) में योग (-p) होता है। इसलिए (p=-8) है।

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