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What is the nature of the roots of the equation \(3x^2+2\sqrt{3}x+1=0\)?

Answer and explanation

Correct answer: Real and equal

For a quadratic equation \(ax^2+bx+c=0\), the discriminant is \(\Delta=b^2-4ac\). Here, \(a=3, b=2\sqrt{3}, c=1\), so \(\Delta=(2\sqrt{3})^2-4(3)(1)=12-12=0\). A zero discriminant means that the two roots are real and equal. The repeated root is \(x=-\frac{\sqrt{3}}{3}\); therefore, the roots are not distinct. Exam tip: whenever \(\Delta=0\), select ‘real and equal roots’.

Related tags

Quadratic EquationsNature Of RootsDiscriminantEqual RootsMathematicsClass 10 Mcq

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