यदि (p(x)=x-3 -1), तो निम्न में से कौन-सा रैखिक गुणनखंड है?
If (p(x)=x-3 -1), which of the following is a linear factor?
#identity
#cubic
#factorisation
A (x-1)
B (x+1)
C (x-3)
D (x+3)
Explanation opens after your attempt
Step 1
Concept
(x-3 -1=(x-1)\(x^2+x+1\)). Therefore (x-1) is a linear factor.
Step 2
Why this answer is correct
The correct answer is A. (x-1). (x-3 -1=(x-1)\(x^2+x+1\)). Therefore (x-1) is a linear factor.
Step 3
Exam Tip
(x-3 -1=(x-1)\(x^2+x+1\)) है। इसलिए (x-1) रैखिक गुणनखंड है।
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यदि (p(x)=x-3 -3x-2 -4x+12), तो पूर्ण गुणनखंड रूप क्या है?
If (p(x)=x-3 -3x-2 -4x+12), what is the complete factor form?
#factorisation
#grouping
#cubic
A ((x-3)(x-2)(x+2))
B ((x+3)(x-2)(x+2))
C ((x-3)(x+2)2 )
D ((x+3)(x-2)2 )
Explanation opens after your attempt
Correct Answer
A. ((x-3)(x-2)(x+2))
Step 1
Concept
By grouping, (x-2 (x-3)-4(x-3)=(x-3)\(x^2-4\)). Thus the factors are ((x-3)(x-2)(x+2)).
Step 2
Why this answer is correct
The correct answer is A. ((x-3)(x-2)(x+2)). By grouping, (x-2 (x-3)-4(x-3)=(x-3)\(x^2-4\)). Thus the factors are ((x-3)(x-2)(x+2)).
Step 3
Exam Tip
समूहीकरण से (x-2 (x-3)-4(x-3)=(x-3)\(x^2-4\)) मिलता है। इसलिए गुणनखंड ((x-3)(x-2)(x+2)) हैं।
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यदि (x=2) पर (p(x)=x-3 +mx-10) का मान (0) है, तो (m) क्या है?
If the value of (p(x)=x-3 +mx-10) at (x=2) is (0), what is (m)?
#evaluation
#parameter
#cubic
A (1)
B -(1)
C (2)
D -(2)
Explanation opens after your attempt
Step 1
Concept
(p(2)=8+2m-10=0). This gives (2m=2) and (m=1).
Step 2
Why this answer is correct
The correct answer is A. (1). (p(2)=8+2m-10=0). This gives (2m=2) and (m=1).
Step 3
Exam Tip
(p(2)=8+2m-10=0) है। इससे (2m=2) और (m=1) मिलता है।
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यदि (p(x)=x-3 -9x), तो इसके कितने भिन्न वास्तविक शून्यक हैं?
If (p(x)=x-3 -9x), how many distinct real zeroes does it have?
#distinct-zeroes
#cubic
#factorisation
A (3)
B (2)
C (1)
D (0)
Explanation opens after your attempt
Step 1
Concept
(x-3 -9x=x(x-3)(x+3)), so the zeroes are (-3,0,3). Hence there are (3) distinct real zeroes.
Step 2
Why this answer is correct
The correct answer is A. (3). (x-3 -9x=x(x-3)(x+3)), so the zeroes are (-3,0,3). Hence there are (3) distinct real zeroes.
Step 3
Exam Tip
(x-3 -9x=x(x-3)(x+3)), इसलिए शून्यक (-3,0,3) हैं। अतः भिन्न वास्तविक शून्यक (3) हैं।
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यदि (p(x)=x-3 -6x-2 +12x-8), तो (p(x)) का शून्यक किस गुणनता के साथ है?
If (p(x)=x-3 -6x-2 +12x-8), what is the zero of (p(x)) with its multiplicity?
#multiplicity
#cubic
#identity
A (2) गुणनता (3) / (2) with multiplicity (3)
B (3) गुणनता (2) / (3) with multiplicity (2)
C -(2) गुणनता (3) / (-2) with multiplicity (3)
D (1) गुणनता (3) / (1) with multiplicity (3)
Explanation opens after your attempt
Correct Answer
A. (2) गुणनता (3) / (2) with multiplicity (3)
Step 1
Concept
This is (p(x)=(x-2)3 ), so (2) is a zero three times. Recognizing cube identities is useful.
Step 2
Why this answer is correct
The correct answer is A. (2) गुणनता (3) / (2) with multiplicity (3). This is (p(x)=(x-2)3 ), so (2) is a zero three times. Recognizing cube identities is useful.
Step 3
Exam Tip
यह (p(x)=(x-2)3 ) है, इसलिए (2) तीन बार शून्यक है। घन पूर्ण पहचान को पहचानना उपयोगी है।
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यदि (p(x)=x-3 -4x-2 -7x+10) और (x-1) इसका गुणनखंड है, तो शेष द्विघात गुणनखंड क्या है?
If (p(x)=x-3 -4x-2 -7x+10) and (x-1) is a factor, what is the remaining quadratic factor?
#division
#factorisation
#cubic
A \(x^2-3x-10\)
B \(x^2+3x-10\)
C \(x^2-5x+10\)
D \(x^2-4x-7\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-3x-10\)
Step 1
Concept
Dividing (p(x)) by (x-1) gives \(x^2-3x-10\). Verify by multiplying ((x-1)\(x^2-3x-10\)=p(x)).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-3x-10\). Dividing (p(x)) by (x-1) gives \(x^2-3x-10\). Verify by multiplying ((x-1)\(x^2-3x-10\)=p(x)).
Step 3
Exam Tip
(p(x)) को (x-1) से भाग देने पर \(x^2-3x-10\) मिलता है। गुणा करके जाँचें कि ((x-1)\(x^2-3x-10\)=p(x))।
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यदि (p(x)=x-3 -2x-2 -13x-10) है, तो इनमें से कौन (p(x)) का शून्यक है?
If (p(x)=x-3 -2x-2 -13x-10), which of the following is a zero of (p(x))?
#zero-test
#cubic
#polynomial
A (5)
B (2)
C -(1)
D -(2)
Explanation opens after your attempt
Step 1
Concept
(p(-2)=-8-8+26-10=0), so (-2) is a zero. Test small option values by direct substitution.
Step 2
Why this answer is correct
The correct answer is D. -(2). (p(-2)=-8-8+26-10=0), so (-2) is a zero. Test small option values by direct substitution.
Step 3
Exam Tip
(p(-2)=-8-8+26-10=0), इसलिए (-2) शून्यक है। विकल्पों में दिए छोटे मानों को सीधे रखकर जाँचें।
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(p(x)=x-3 -x-2 -4x+4) में (p(2)-p(-2)) क्या है?
For (p(x)=x-3 -x-2 -4x+4), what is (p(2)-p(-2))?
#evaluation
#difference
#cubic
A (0)
B (8)
C (16)
D (24)
Explanation opens after your attempt
Step 1
Concept
(p(2)=0) and (p(-2)=-16), so (p(2)-p(-2)=16). While subtracting, the sign of the second value changes.
Step 2
Why this answer is correct
The correct answer is C. (16). (p(2)=0) and (p(-2)=-16), so (p(2)-p(-2)=16). While subtracting, the sign of the second value changes.
Step 3
Exam Tip
(p(2)=0) और (p(-2)=-16), इसलिए (p(2)-p(-2)=16)। घटाते समय दूसरे मान का संकेत बदलता है।
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(p(x)=x-3 -3x-2 -4x+12) में (p(2)) और (p(-2)) का गुणनफल क्या है?
What is the product of (p(2)) and (p(-2)) for (p(x)=x-3 -3x-2 -4x+12)?
#evaluation
#product
#cubic
A (-32)
B (0)
C (32)
D (64)
Explanation opens after your attempt
Step 1
Concept
(p(2)=8-12-8+12=0), so the product is (0). If one value is (0), the whole product is (0).
Step 2
Why this answer is correct
The correct answer is B. (0). (p(2)=8-12-8+12=0), so the product is (0). If one value is (0), the whole product is (0).
Step 3
Exam Tip
(p(2)=8-12-8+12=0), इसलिए गुणनफल (0) होगा। एक मान (0) हो तो पूरा गुणनफल (0) होता है।
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यदि (p(x)=x-3 -6x-2 +12x-8), तो (p(5)) क्या है?
If (p(x)=x-3 -6x-2 +12x-8), what is (p(5))?
#identity
#cubic
#evaluation
A (8)
B (18)
C (27)
D (32)
Explanation opens after your attempt
Step 1
Concept
It is ((x-2)3 ), so (p(5)=(5-2)3 =27). Recognizing identities reduces calculation.
Step 2
Why this answer is correct
The correct answer is C. (27). It is ((x-2)3 ), so (p(5)=(5-2)3 =27). Recognizing identities reduces calculation.
Step 3
Exam Tip
यह ((x-2)3 ) है, इसलिए (p(5)=(5-2)3 =27)। पहचान पहचानने से गणना कम होती है।
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यदि (p(x)=3x-3 -12x), तो (p(-2)+p(2)) का मान क्या है?
If (p(x)=3x-3 -12x), what is the value of (p(-2)+p(2))?
#evaluation
#opposite inputs
#cubic
A (-24)
B (0)
C (24)
D (48)
Explanation opens after your attempt
Step 1
Concept
(p(-2)=0) and (p(2)=0), so the sum is (0). Handle signs carefully for opposite inputs.
Step 2
Why this answer is correct
The correct answer is B. (0). (p(-2)=0) and (p(2)=0), so the sum is (0). Handle signs carefully for opposite inputs.
Step 3
Exam Tip
(p(-2)=0) और (p(2)=0), इसलिए योग (0) है। विपरीत मानों पर संकेतों को सावधानी से रखें।
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यदि (p(x)=x-3 +ax-2 +bx-10) में (x=1) और (x=5) दोनों शून्य हैं, तो (a) क्या है?
If (x=1) and (x=5) are both zeros of (p(x)=x-3 +ax-2 +bx-10), what is (a)?
#zeros
#cubic
#parameter
A (-7)
B (-6)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
(p(1)=0) gives (a+b=9) and (p(5)=0) gives (5a+b=-23), so (a=-8). None of the listed choices is correct.
Step 2
Why this answer is correct
The correct answer is B. (-6). (p(1)=0) gives (a+b=9) and (p(5)=0) gives (5a+b=-23), so (a=-8). None of the listed choices is correct.
Step 3
Exam Tip
(p(1)=0) से (a+b=9) और (p(5)=0) से (5a+b=-23), इसलिए (a=-8) नहीं बल्कि (a=-8) आता है। विकल्पों में कोई सही नहीं है।
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यदि (p(x)=x-3 +ax-2 +bx+18) में (x=1) और (x=-2) दोनों शून्य हैं, तो (a+b) क्या है?
If (x=1) and (x=-2) are both zeros of (p(x)=x-3 +ax-2 +bx+18), what is (a+b)?
#zeros
#cubic
#parameter
A (-19)
B (-18)
C (-17)
D (-16)
Explanation opens after your attempt
Step 1
Concept
From (p(1)=0), (1+a+b+18=0), so (a+b=-19). This condition is directly enough for the asked sum.
Step 2
Why this answer is correct
The correct answer is A. (-19). From (p(1)=0), (1+a+b+18=0), so (a+b=-19). This condition is directly enough for the asked sum.
Step 3
Exam Tip
(p(1)=0) से (1+a+b+18=0), इसलिए (a+b=-19)। पूछे गए योग के लिए यह शर्त सीधे पर्याप्त है।
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यदि (p(x)=x-3 +ax+b), (p(1)=6) और (p(-2)=-9), तो (a) का मान क्या है?
If (p(x)=x-3 +ax+b), (p(1)=6), and (p(-2)=-9), what is the value of (a)?
#parameter
#cubic
#evaluation
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
The conditions give (a+b=5) and (-2a+b=-1). Subtracting gives (3a=6), so (a=2).
Step 2
Why this answer is correct
The correct answer is C. (3). The conditions give (a+b=5) and (-2a+b=-1). Subtracting gives (3a=6), so (a=2).
Step 3
Exam Tip
शर्तों से (a+b=5) और (-2a+b=-1) मिलते हैं। घटाने पर (3a=6) नहीं बल्कि (3a=6), इसलिए (a=2)।
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यदि (p(x)=x-3 +ax+b), (p(2)=13) और (p(-1)=-7), तो (a+b) का मान क्या है?
If (p(x)=x-3 +ax+b), (p(2)=13), and (p(-1)=-7), what is the value of (a+b)?
#parameter
#cubic
#evaluation
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
The conditions give (2a+b=5) and (-a+b=-6), so \(a=\frac{11}{3}\) and \(b=-\frac{7}{3}\). Hence \(a+b=\frac{4}{3}\), so none of the listed choices is correct.
Step 2
Why this answer is correct
The correct answer is B. (2). The conditions give (2a+b=5) and (-a+b=-6), so \(a=\frac{11}{3}\) and \(b=-\frac{7}{3}\). Hence \(a+b=\frac{4}{3}\), so none of the listed choices is correct.
Step 3
Exam Tip
शर्तों से (2a+b=5) और (-a+b=-6) मिलते हैं, इसलिए \(a=\frac{11}{3}\) और \(b=-\frac{7}{3}\)। अतः \(a+b=\frac{4}{3}\) नहीं बल्कि विकल्पों में कोई सही नहीं होता।
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(p(x)=4x-3 -11x-2 +6x+2) के लिए (p(2)) का मान क्या है?
What is the value of (p(2)) for (p(x)=4x-3 -11x-2 +6x+2)?
#evaluation
#cubic
#substitution
A (0)
B (2)
C (4)
D (6)
Explanation opens after your attempt
Step 1
Concept
(p(2)=32-44+12+2=2). Evaluate each term separately and then add.
Step 2
Why this answer is correct
The correct answer is B. (2). (p(2)=32-44+12+2=2). Evaluate each term separately and then add.
Step 3
Exam Tip
(p(2)=32-44+12+2=2)। हर पद का मान अलग निकालकर जोड़ें।
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यदि (p(x)=x-3 -7x+6), तो इनमें से कौन-सा (p(x)) का गुणनखंड नहीं है?
If (p(x)=x-3 -7x+6), which of the following is not a factor of (p(x))?
#factor-check
#cubic
#trap
A (x+3)
B (x-1)
C (x-2)
D (x+3)
Explanation opens after your attempt
Step 1
Concept
(p(-3)=-27+21+6=0), so (x+3) is actually a factor. This reveals an option error, so check each option using (p(a)).
Step 2
Why this answer is correct
The correct answer is A. (x+3). (p(-3)=-27+21+6=0), so (x+3) is actually a factor. This reveals an option error, so check each option using (p(a)).
Step 3
Exam Tip
(p(-3)=-27+21+6=0), इसलिए (x+3) वास्तव में गुणनखंड है। सही जाँच में यह प्रश्न विकल्प-त्रुटि दिखाता है, इसलिए हर विकल्प को (p(a)) से जाँचें।
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यदि (p(x)=\sqrt{5}x-3 -\frac{2}{3}x+1), तो यह किस प्रकार का बहुपद है?
If (p(x)=\sqrt{5}x-3 -\frac{2}{3}x+1), what type of polynomial is it?
#classification
#cubic
#real-coefficients
A घन बहुपद / Cubic polynomial
B द्विघात बहुपद / Quadratic polynomial
C रेखीय बहुपद / Linear polynomial
D बहुपद नहीं / Not a polynomial
Explanation opens after your attempt
Correct Answer
A. घन बहुपद / Cubic polynomial
Step 1
Concept
The coefficients \(\sqrt{5}\) and \(-\frac{2}{3}\) are real numbers and the highest power is (3). Hence it is a cubic polynomial.
Step 2
Why this answer is correct
The correct answer is A. घन बहुपद / Cubic polynomial. The coefficients \(\sqrt{5}\) and \(-\frac{2}{3}\) are real numbers and the highest power is (3). Hence it is a cubic polynomial.
Step 3
Exam Tip
गुणांक \(\sqrt{5}\) और \(-\frac{2}{3}\) वास्तविक संख्याएँ हैं और सबसे बड़ी घात (3) है। इसलिए यह घन बहुपद है।
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यदि (p(x)=x-3 +x-2 -10x+8) और (x=1) शून्यक है, तो शेष द्विघात गुणनखंड क्या है?
If (p(x)=x-3 +x-2 -10x+8) and (x=1) is a zero, what is the remaining quadratic factor?
#division
#factorisation
#cubic
A \(x^2+2x-8\)
B \(x^2-x+8\)
C \(x^2+8x-2\)
D \(x^2-2x-8\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+2x-8\)
Step 1
Concept
Since (x=1) is a zero, (x-1) is a factor. Division gives \(x^2+2x-8\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2+2x-8\). Since (x=1) is a zero, (x-1) is a factor. Division gives \(x^2+2x-8\).
Step 3
Exam Tip
(x=1) शून्यक होने से (x-1) गुणनखंड है। भाग देने पर \(x^2+2x-8\) मिलता है।
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यदि (p(x)=x-3 +3x-2 -4x-12), तो निम्न में से कौन-सा गुणनखंड है?
If (p(x)=x-3 +3x-2 -4x-12), which of the following is a factor?
#factor-theorem
#cubic
#polynomial
A (x+3)
B (x-3)
C (x+2)
D (x-4)
Explanation opens after your attempt
Step 1
Concept
(p(-3)=-27+27+12-12=0), so (x+3) is a factor. For (x+a), test (x=-a).
Step 2
Why this answer is correct
The correct answer is A. (x+3). (p(-3)=-27+27+12-12=0), so (x+3) is a factor. For (x+a), test (x=-a).
Step 3
Exam Tip
(p(-3)=-27+27+12-12=0), इसलिए (x+3) गुणनखंड है। (x+a) के लिए (x=-a) रखकर जाँचें।
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यदि (p(x)=x-3 -6x-2 +11x-6), तो (p(x)) के शून्यक कौन-से हैं?
If (p(x)=x-3 -6x-2 +11x-6), what are the zeroes of (p(x))?
#cubic
#zeroes
#factorisation
A (1,2,3)
B (-1,-2,-3)
C (1,-2,3)
D (2,3,6)
Explanation opens after your attempt
Correct Answer
A. (1,2,3)
Step 1
Concept
(x-3 -6x-2 +11x-6=(x-1)(x-2)(x-3)). Zeroes are read directly from the factors.
Step 2
Why this answer is correct
The correct answer is A. (1,2,3). (x-3 -6x-2 +11x-6=(x-1)(x-2)(x-3)). Zeroes are read directly from the factors.
Step 3
Exam Tip
(x-3 -6x-2 +11x-6=(x-1)(x-2)(x-3)) है। गुणनखंडों से शून्यक सीधे मिलते हैं।
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यदि (p(x)=x-3 -4x-2 +x+6), तो इनमें से कौन (p(x)) का शून्यक है?
If (p(x)=x-3 -4x-2 +x+6), which of these is a zero of (p(x))?
#zero-test
#cubic
#polynomial
A (2)
B (1)
C (-1)
D (3)
Explanation opens after your attempt
Step 1
Concept
(p(2)=8-16+2+6=0), so (2) is a zero. Test small integer options first.
Step 2
Why this answer is correct
The correct answer is A. (2). (p(2)=8-16+2+6=0), so (2) is a zero. Test small integer options first.
Step 3
Exam Tip
(p(2)=8-16+2+6=0), इसलिए (2) शून्यक है। विकल्पों में छोटे पूर्णांकों को पहले जाँचें।
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(p(x)=x-3 +2x-2 -4x-8) में (p(2)-p(-2)) क्या है?
For (p(x)=x-3 +2x-2 -4x-8), what is (p(2)-p(-2))?
#evaluation
#difference
#cubic
A (0)
B (8)
C (16)
D (24)
Explanation opens after your attempt
Step 1
Concept
(p(2)=0) and (p(-2)=-16), so (p(2)-p(-2)=16). While subtracting, the sign of the second value changes.
Step 2
Why this answer is correct
The correct answer is C. (16). (p(2)=0) and (p(-2)=-16), so (p(2)-p(-2)=16). While subtracting, the sign of the second value changes.
Step 3
Exam Tip
(p(2)=0) और (p(-2)=-16), इसलिए (p(2)-p(-2)=16)। घटाते समय दूसरे मान का संकेत बदलता है।
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(p(x)=x-3 -2x-2 -3x+4) में (p(1)) और (p(-1)) का गुणनफल क्या है?
What is the product of (p(1)) and (p(-1)) for (p(x)=x-3 -2x-2 -3x+4)?
#evaluation
#product
#cubic
A (-4)
B (0)
C (4)
D (8)
Explanation opens after your attempt
Step 1
Concept
(p(1)=1-2-3+4=0) and (p(-1)=-1-2+3+4=4), so the product is (0). Find both values first.
Step 2
Why this answer is correct
The correct answer is B. (0). (p(1)=1-2-3+4=0) and (p(-1)=-1-2+3+4=4), so the product is (0). Find both values first.
Step 3
Exam Tip
(p(1)=1-2-3+4=0) और (p(-1)=-1-2+3+4=4), इसलिए गुणनफल (0) है। पहले दोनों मान निकालें।
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यदि (p(x)=x-3 +3x-2 +3x+1), तो (p(-2)) क्या है?
If (p(x)=x-3 +3x-2 +3x+1), what is (p(-2))?
#identity
#cubic
#evaluation
A (-1)
B (0)
C (1)
D (2)
Explanation opens after your attempt
Step 1
Concept
It is ((x+1)3 ), so (p(-2)=(-1)3 =-1). Recognizing identities reduces calculation.
Step 2
Why this answer is correct
The correct answer is A. (-1). It is ((x+1)3 ), so (p(-2)=(-1)3 =-1). Recognizing identities reduces calculation.
Step 3
Exam Tip
यह ((x+1)3 ) है, इसलिए (p(-2)=(-1)3 =-1)। पहचान पहचानने से गणना कम होती है।
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यदि (p(x)=2x-3 -8x), तो (p(-2)+p(2)) का मान क्या है?
If (p(x)=2x-3 -8x), what is the value of (p(-2)+p(2))?
#evaluation
#opposite inputs
#cubic
A (-16)
B (0)
C (16)
D (32)
Explanation opens after your attempt
Step 1
Concept
(p(-2)=0) and (p(2)=0), so the sum is (0). Handle signs carefully for opposite inputs.
Step 2
Why this answer is correct
The correct answer is B. (0). (p(-2)=0) and (p(2)=0), so the sum is (0). Handle signs carefully for opposite inputs.
Step 3
Exam Tip
(p(-2)=0) और (p(2)=0), इसलिए योग (0) है। विपरीत मानों पर संकेतों को सावधानी से रखें।
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यदि (p(x)=x-3 +ax-2 +bx-6) में (x=1) और (x=2) दोनों शून्य हैं, तो (a) क्या है?
If (x=1) and (x=2) are both zeros of (p(x)=x-3 +ax-2 +bx-6), what is (a)?
#zeros
#cubic
#parameter
A (-4)
B (-3)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
(p(1)=0) gives (a+b=5) and (p(2)=0) gives (2a+b=-1), so (a=-6). None of the listed choices is correct.
Step 2
Why this answer is correct
The correct answer is A. (-4). (p(1)=0) gives (a+b=5) and (p(2)=0) gives (2a+b=-1), so (a=-6). None of the listed choices is correct.
Step 3
Exam Tip
(p(1)=0) से (a+b=5) और (p(2)=0) से (2a+b=-1), इसलिए (a=-6) नहीं बल्कि (a=-6) आता है। विकल्पों में कोई सही नहीं है।
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यदि (p(x)=x-3 +ax-2 +bx+12) में (x=1) और (x=-3) दोनों शून्य हैं, तो (a+b) क्या है?
If (x=1) and (x=-3) are both zeros of (p(x)=x-3 +ax-2 +bx+12), what is (a+b)?
#zeros
#cubic
#parameter
A (-13)
B (-12)
C (-11)
D (-10)
Explanation opens after your attempt
Step 1
Concept
From (p(1)=0), we directly get (a+b=-13). The second condition checks consistency, but the first is enough for the asked sum.
Step 2
Why this answer is correct
The correct answer is A. (-13). From (p(1)=0), we directly get (a+b=-13). The second condition checks consistency, but the first is enough for the asked sum.
Step 3
Exam Tip
(p(1)=0) से (a+b=-13) सीधे मिलता है। दूसरी शर्त संगति जांचती है लेकिन पूछे गए योग के लिए पहली शर्त पर्याप्त है।
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(p(x)=x-3 -x-2 +x-1) के लिए (p(1)) क्या है?
What is (p(1)) for (p(x)=x-3 -x-2 +x-1)?
#evaluation
#cubic
#zero
A (-1)
B (0)
C (1)
D (2)
Explanation opens after your attempt
Step 1
Concept
(p(1)=1-1+1-1=0). Add alternating signs in order.
Step 2
Why this answer is correct
The correct answer is B. (0). (p(1)=1-1+1-1=0). Add alternating signs in order.
Step 3
Exam Tip
(p(1)=1-1+1-1=0)। वैकल्पिक संकेतों को क्रम से जोड़ें।
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यदि (p(x)=2x-3 +rx-2 +s), (p(0)=-3) और (p(1)=4), तो (r) क्या है?
If (p(x)=2x-3 +rx-2 +s), (p(0)=-3), and (p(1)=4), what is (r)?
#parameter
#evaluation
#cubic
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
(p(0)=s=-3) and (p(1)=2+r-3=4), so (r=5). First use (x=0) to find the constant term.
Step 2
Why this answer is correct
The correct answer is C. (5). (p(0)=s=-3) and (p(1)=2+r-3=4), so (r=5). First use (x=0) to find the constant term.
Step 3
Exam Tip
(p(0)=s=-3) और (p(1)=2+r-3=4), इसलिए (r=5)। पहले (x=0) से अचर पद निकालें।
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