Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 151-160 of 600 questions.
What is the simplified surd form of \( \sqrt{125} \)?
A. \(5\sqrt{5}\)
\(125=25\times5\) इसलिए \( \sqrt{125}=5\sqrt{5} \)। सबसे बड़ा पूर्ण वर्ग गुणनखंड चुनें। / Since \(125=25\times5\), \( \sqrt{125}=5\sqrt{5} \). Choose the largest perfect-square factor.
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What is obtained by simplifying \( \sqrt{147} \)?
B. \(7\sqrt{3}\)
\(147=49\times3\) इसलिए \( \sqrt{147}=7\sqrt{3} \)। पूर्ण वर्ग को बाहर निकालना मुख्य कदम है। / Since \(147=49\times3\), \( \sqrt{147}=7\sqrt{3} \). Taking out the perfect square is the main step.
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Which is the simplified form of \( \sqrt{192} \)?
C. \(8\sqrt{3}\)
\(192=64\times3\) इसलिए \( \sqrt{192}=8\sqrt{3} \)। करणी में सबसे बड़ा पूर्ण वर्ग खोजें। / Since \(192=64\times3\), \( \sqrt{192}=8\sqrt{3} \). Find the largest perfect square inside the radical.
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What is the simplified form of \(3\sqrt{8}+2\sqrt{18}\)?
A. \(12\sqrt{2}\)
\( \sqrt{8}=2\sqrt{2} \) और \( \sqrt{18}=3\sqrt{2} \) हैं। इसलिए योग \(6\sqrt{2}+6\sqrt{2}=12\sqrt{2}\) है। / \( \sqrt{8}=2\sqrt{2} \) and \( \sqrt{18}=3\sqrt{2} \). So the sum is \(6\sqrt{2}+6\sqrt{2}=12\sqrt{2}\).
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What is the simplified form of \(5\sqrt{12}-\sqrt{75}\)?
A. \(5\sqrt{3}\)
\(5\sqrt{12}=10\sqrt{3}\) और \( \sqrt{75}=5\sqrt{3} \) है। अंतर \(5\sqrt{3}\) होगा। / \(5\sqrt{12}=10\sqrt{3}\) and \( \sqrt{75}=5\sqrt{3} \). The difference is \(5\sqrt{3}\).
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What is the value of ( \sqrt{3}\(2+\sqrt{3}\) )?
A. \(2\sqrt{3}+3\)
वितरण नियम से \( \sqrt{3}\times2+\sqrt{3}\times\sqrt{3}=2\sqrt{3}+3 \)। करणी गुणा में \(\sqrt{a}\sqrt{a}=a\) याद रखें। / By distributive law, \( \sqrt{3}\times2+\sqrt{3}\times\sqrt{3}=2\sqrt{3}+3 \). Remember \( \sqrt{a}\sqrt{a}=a \) in surd multiplication.
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What is the expansion of ( \(2+\sqrt{7}\)2 )?
A. \(11+4\sqrt{7}\)
( (a+b)2=a-2+2ab+b-2 ) लगाएँ। यहाँ \(4+4\sqrt{7}+7=11+4\sqrt{7}\) मिलता है। / Use ( (a+b)2=a-2+2ab+b-2 ). Here \(4+4\sqrt{7}+7=11+4\sqrt{7}\).
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What is the simplified form of ( \(5-\sqrt{6}\)2 )?
A. \(31-10\sqrt{6}\)
( (a-b)2=a-2-2ab+b-2 ) से \(25-10\sqrt{6}+6=31-10\sqrt{6}\) मिलता है। संकेतों पर विशेष ध्यान दें। / Using ( (a-b)2=a-2-2ab+b-2 ), we get \(25-10\sqrt{6}+6=31-10\sqrt{6}\). Pay special attention to signs.
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What is the value of ( \(4+\sqrt{11}\)\(4-\sqrt{11}\) )?
B. (5)
यह संयुग्मी गुणन है। (42-\(\sqrt{11}\)2=16-11=5) होगा। / This is conjugate multiplication. (42-\(\sqrt{11}\)2=16-11=5).
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What is the value of ( \(3+\sqrt{10}\)\(3-\sqrt{10}\) )?
B. ( -1 )
संयुग्मी गुणन से (32-\(\sqrt{10}\)2=9-10=-1) मिलता है। मध्य पद कट जाते हैं। / Conjugate multiplication gives (32-\(\sqrt{10}\)2=9-10=-1). The middle terms cancel.
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