Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 211-220 of 584 questions.
What is the correct conclusion about (8x+3>8x-10)?
B. सभी वास्तविक (x)All real (x)
दोनों तरफ से (8x) घटाने पर (3>-10) मिलता है जो हमेशा सत्य है। इसलिए सभी वास्तविक (x) हल हैं। / Subtracting (8x) from both sides gives (3>-10), which is always true. Therefore all real (x) are solutions.
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What is the correct conclusion for \(5x-6\geq 5x+2\)?
C. कोई हल नहींNo solution
दोनों तरफ से (5x) घटाने पर \(-6\geq 2\) मिलता है जो असत्य है। इसलिए कोई हल नहीं है। / Subtracting (5x) from both sides gives \(-6\geq 2\), which is false. Hence there is no solution.
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If (a>0) and \(ax-7\geq 2\), which form for (x) is correct?
D. \(x\geq \frac{9}{a}\)
\(ax\geq 9\) मिलता है। (a>0) होने से भाग देने पर \(x\geq \frac{9}{a}\) रहेगा। / We get \(ax\geq 9\). Since (a>0), division gives \(x\geq \frac{9}{a}\).
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If (a<0) and (ax+4>10), which form for (x) is correct?
A. \(x<\frac{6}{a}\)
(ax>6) मिलता है। (a<0) से भाग देने पर चिन्ह बदलकर \(x<\frac{6}{a}\) होता है। / We get (ax>6). Dividing by (a<0) reverses the sign to \(x<\frac{6}{a}\).
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Six times a number is greater than (42). What is the correct inequality form?
B. (6x>42)
किसी संख्या को (x) मानें तो उसका (6) गुना (6x) है। अधिक है के लिए (>) प्रयोग होता है। / Let the number be (x), so six times it is (6x). The phrase greater than uses (>).
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When (11) is added to a number, the result is not less than (30). What is the correct solution?
A. \(x\geq 19\)
कथन \(x+11\geq 30\) देता है। इसलिए \(x\geq 19\) सही है। / The statement gives \(x+11\geq 30\). Therefore \(x\geq 19\) is correct.
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If four times a number increased by (3) is at most (35), what is the solution?
B. \(x\leq 8\)
कथन \(4x+3\leq 35\) देता है। इससे \(4x\leq 32\) और \(x\leq 8\) मिलता है। / The statement gives \(4x+3\leq 35\). This gives \(4x\leq 32\) and \(x\leq 8\).
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C. (6)
शर्त \(120-15x\geq 30\) है जिससे \(x\leq 6\) मिलता है। इसलिए अधिकतम पेन (6) हैं। / The condition is \(120-15x\geq 30\), giving \(x\leq 6\). Therefore the maximum number of pens is (6).
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D. (33)
शर्त \(x+19\leq 52\) है। इससे \(x\leq 33\) मिलता है। / The condition is \(x+19\leq 52\). This gives \(x\leq 33\).
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What is the solution of (3(2x-5)-2(x+1)\geq 7)?
B. \(x\geq 6\)
सरल करने पर \(6x-15-2x-2\geq 7\) यानी \(4x-17\geq 7\) मिलता है। इसलिए \(x\geq 6\) है। / Simplifying gives \(6x-15-2x-2\geq 7\), that is \(4x-17\geq 7\). Therefore \(x\geq 6\).
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