Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है
SubjectsMathematics
अभाज्य गुणनखंडन
In Class 10 Mathematics, under the Real Numbers chapter, Prime Factorisation teaches students to express a composite number as a product of prime numbers. Students practise identifying prime factors and writing factorisations using multiplication and exponents. This foundational skill supports the Fundamental Theorem of Arithmetic and later work with HCF and LCM.
TOPIC PRACTICE
Up to 20 questions from this page. Select your focus, then start.
Step 1: Write (48510=90\times539). Step 2: (90=2\times3^2\times5) and (539=7^2\times11), so (48510=2\times3^2\times5\times7^2\times11). Step 3: Give prime form to both 90 and 539.
View question detailsStep 1: Write (52920=8\times6615). Step 2: (6615=3^3\times5\times7^2), so (52920=2^3\times3^3\times5\times7^2). Step 3: Give 6615 its complete prime form.
View question detailsStep 1: Write (59290=70\times1331). Step 2: (70=2\times5\times7) and (1331=11^3), so (59290=2\times5\times7\times11^3). Step 3: Change 1331 into (11^3).
View question detailsStep 1: Divide 65536 repeatedly by 2. Step 2: Sixteen factors of 2 give (65536=2^{16}). Step 3: 256 and 16 are composite bases, so write the power of 2 in final form.
View question detailsStep 1: Write (68040=8\times8505). Step 2: (8505=3^5\times5\times7), so (68040=2^3\times3^5\times5\times7). Step 3: Convert 8505 into prime powers.
View question detailsStep 1: Write (76230=630\times121). Step 2: (630=2\times3^2\times5\times7) and (121=11^2), so (76230=2\times3^2\times5\times7\times11^2). Step 3: Break both 630 and 121 completely.
View question detailsStep 1: Write (88200=8\times11025). Step 2: (11025=3^2\times5^2\times7^2), so (88200=2^3\times3^2\times5^2\times7^2). Step 3: Convert 11025 into prime powers.
View question detailsStep 1: Write (95256=8\times11907). Step 2: (11907=3^5\times7^2), so (95256=2^3\times3^5\times7^2). Step 3: Convert 11907 into powers of 3 and 7.
View question detailsStep 1: Write (108900=900\times121). Step 2: (900=2^2\times3^2\times5^2) and (121=11^2), so (108900=2^2\times3^2\times5^2\times11^2). Step 3: This is a square form, so all exponents are even.
View question detailsStep 1: Write (127008=32\times3969). Step 2: (3969=3^4\times7^2), so (127008=2^5\times3^4\times7^2). Step 3: Convert 3969 into prime powers.
View question detailsStep 1: Write (130680=1080\times121). Step 2: (1080=2^3\times3^3\times5) and (121=11^2), so (130680=2^3\times3^3\times5\times11^2). Step 3: Break 1080 and 121 completely.
View question detailsStep 1: (127008=32\times3969). Step 2: (32=2^5) and (3969=3^4\times7^2), so the power of 2 is 5. Step 3: Comparing gives (a=5).
View question detailsStep 1: Write (95256=8\times11907). Step 2: (11907=3^5\times7^2), so (95256=2^3\times3^5\times7^2). Step 3: From the given form, (b=5).
View question detailsStep 1: (108900=900\times121). Step 2: (900=2^2\times3^2\times5^2) and (121=11^2), so the power of 5 is 2. Step 3: Comparing gives (m=2).
View question detailsStep 1: Write (68040=8\times8505). Step 2: (8505=3^5\times5\times7), so the power of 3 is 5. Step 3: Comparing gives (p=5).
View question detailsStep 1: Calculate (2^4=16) and (3^4=81). Step 2: (16\times81\times11=14256). Step 3: Solve powers first, then multiply by 11.
View question detailsStep 1: Calculate (2^5=32) and (3^4=81). Step 2: (32\times81\times7=18144). Step 3: It is better to find higher powers first.
View question detailsStep 1: Calculate (11^2=121). Step 2: (2\times3\times5\times7\times121=25410). Step 3: First take the product of smaller factors as 210, then multiply by 121.
View question detailsStep 1: Calculate (2^6=64), (3^3=27), and (5^2=25). Step 2: (64\times27\times25=43200). Step 3: Simplify all three powers separately.
View question detailsStep 1: Calculate (2^5=32), (3^4=81), and (7^2=49). Step 2: (32\times81\times49=127008). Step 3: Solving powers first keeps multiplication clear.
View question detailsQUIZ COMPLETE
