Which is the prime factorisation of 1008?
Step 1: Write (1008=16\times63). Step 2: (16=2^4) and (63=3^2\times7), so (1008=2^4\times3^2\times7). Step 3: Give 63 its complete prime form.
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SubjectsMathematics
अभाज्य गुणनखंडन
In Class 10 Mathematics, under the Real Numbers chapter, Prime Factorisation teaches students to express a composite number as a product of prime numbers. Students practise identifying prime factors and writing factorisations using multiplication and exponents. This foundational skill supports the Fundamental Theorem of Arithmetic and later work with HCF and LCM.
TOPIC PRACTICE
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Step 1: Write (1008=16\times63). Step 2: (16=2^4) and (63=3^2\times7), so (1008=2^4\times3^2\times7). Step 3: Give 63 its complete prime form.
View question detailsStep 1: Write (1155=11\times105). Step 2: (105=3\times5\times7), so (1155=3\times5\times7\times11). Step 3: Since 105 is composite, break it further.
View question detailsStep 1: Write (1176=24\times49). Step 2: (24=2^3\times3) and (49=7^2), so (1176=2^3\times3\times7^2). Step 3: Convert 24 and 49 into prime powers.
View question detailsStep 1: Recognise (1225=35^2). Step 2: Since (35=5\times7), (1225=5^2\times7^2). Step 3: In a square number, prime exponents may be even.
View question detailsStep 1: Write (1296=16\times81). Step 2: (16=2^4) and (81=3^4), so (1296=2^4\times3^4). Step 3: Do not leave 16 and 81 in the final answer.
View question detailsStep 1: Write (1323=27\times49). Step 2: (27=3^3) and (49=7^2), so (1323=3^3\times7^2). Step 3: Both 27 and 49 are composite, so write them as prime powers.
View question detailsStep 1: Write (1440=144\times10). Step 2: (144=2^4\times3^2) and (10=2\times5), so (1440=2^5\times3^2\times5). Step 3: The total power of 2 is 5.
View question detailsStep 1: Write (1470=30\times49). Step 2: (30=2\times3\times5) and (49=7^2), so (1470=2\times3\times5\times7^2). Step 3: Write 49 as (7^2).
View question detailsStep 1: Recognise (1728=12^3). Step 2: Since (12=2^2\times3), (12^3=2^6\times3^3). Step 3: Since 12 is composite, write powers of 2 and 3 in the final form.
View question detailsStep 1: Write (1800=18\times100). Step 2: (18=2\times3^2) and (100=2^2\times5^2), so (1800=2^3\times3^2\times5^2). Step 3: Give complete prime form to both 18 and 100.
View question detailsStep 1: Write (1980=198\times10). Step 2: (198=2\times3^2\times11) and (10=2\times5), so (1980=2^2\times3^2\times5\times11). Step 3: Since 2 appears twice, write (2^2).
View question detailsStep 1: (840=84\times10). Step 2: (84=2^2\times3\times7) and (10=2\times5), so (840=2^3\times3\times5\times7). Step 3: Comparing gives (a=3).
View question detailsStep 1: (945=27\times35). Step 2: (27=3^3) and (35=5\times7), so (945=3^3\times5\times7). Step 3: Comparing gives (b=3).
View question detailsStep 1: (1225=35^2). Step 2: Since (35=5\times7), (1225=5^2\times7^2). Step 3: Comparing with the given form gives (m=2).
View question detailsStep 1: Write (1800=18\times100). Step 2: (18=2\times3^2) and (100=2^2\times5^2), so the total power of 2 is 3. Step 3: Therefore, (p=3).
View question detailsStep 1: Calculate (2^3=8) and (3^2=9). Step 2: (8\times9\times7=504). Step 3: Evaluate prime powers first, then multiply.
View question detailsStep 1: Calculate (2^4=16). Step 2: (16\times3\times11=528). Step 3: While multiplying, complete smaller products first.
View question detailsStep 1: Calculate (2^2=4) and (7^2=49). Step 2: (4\times5\times49=980). Step 3: Finding powers first reduces mistakes.
View question detailsStep 1: Calculate (2^6=64) and (3^3=27). Step 2: (64\times27=1728). Step 3: Simplify higher powers separately first.
View question detailsStep 1: Calculate (2^2=4) and (3^2=9). Step 2: (4\times9\times5\times11=1980). Step 3: Simplifying powers first gives the answer quickly.
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