Which is the correct prime factorisation of (84)?
Step 1: Write (84) as (4 \times 21). Step 2: Since (4=2^2) and (21=3 \times 7), (84=2^2 \times 3 \times 7). Step 3: In exams, multiply back to verify the original number.
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SubjectsMathematics
अभाज्य गुणनखंडन
In Class 10 Mathematics, under the Real Numbers chapter, Prime Factorisation teaches students to express a composite number as a product of prime numbers. Students practise identifying prime factors and writing factorisations using multiplication and exponents. This foundational skill supports the Fundamental Theorem of Arithmetic and later work with HCF and LCM.
TOPIC PRACTICE
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Step 1: Write (84) as (4 \times 21). Step 2: Since (4=2^2) and (21=3 \times 7), (84=2^2 \times 3 \times 7). Step 3: In exams, multiply back to verify the original number.
View question detailsStep 1: Write (126) as (2 \times 63). Step 2: Since (63=3^2 \times 7), (126=2 \times 3^2 \times 7). Step 3: While counting distinct prime factors, do not count exponents as separate numbers.
View question detailsStep 1: Evaluate the powers first. Step 2: (2^3=8) and (3^2=9), so (8 \times 9 \times 5=360). Step 3: In such questions, solve powers before multiplying.
View question detailsStep 1: Split (150) as (15 \times 10). Step 2: (15=3 \times 5) and (10=2 \times 5), so (150=2 \times 3 \times 5^2). Step 3: Writing repeated prime factors as powers keeps the answer neat.
View question detailsStep 1: Evaluate the given power. Step 2: (2^2 \times 3 \times 5=4 \times 3 \times 5=60). Step 3: Multiply completely before selecting the option.
View question detailsStep 1: Write (96) as (32 \times 3). Step 2: Since (32=2^5), (96=2^5 \times 3). Step 3: To find an exponent, divide repeatedly by that prime.
View question detailsStep 1: In prime factorisation, every base must be a prime number. Step 2: (9) is not prime because (9=3^2), so the second option is not prime factorisation. Step 3: Always check each base carefully.
View question detailsStep 1: (2^4=16). Step 2: (16 \times 3=48), so the number is (48). Step 3: Evaluating the power first makes calculation easier.
View question detailsStep 1: (225=15 \times 15). Step 2: Since (15=3 \times 5), (225=3^2 \times 5^2). Step 3: (15^2) shows the value, but it is not prime factorisation because (15) is not prime.
View question detailsStep 1: Prime factorise (72). Step 2: (72=8 \times 9=2^3 \times 3^2), so (a=3). Step 3: For an unknown exponent, compare prime factorisations on both sides.
View question detailsStep 1: Write (180=18 \times 10). Step 2: (18=2 \times 3^2) and (10=2 \times 5), so (180=2^2 \times 3^2 \times 5). Step 3: Focus on the required exponent instead of memorising the whole number.
View question detailsStep 1: (2^3=8) and (5^2=25). Step 2: (8 \times 25=200), so the number is (200). Step 3: Solving powers first makes multiplication simple.
View question detailsStep 1: Write (315=9 \times 35). Step 2: (9=3^2) and (35=5 \times 7), so (315=3^2 \times 5 \times 7). It does not include (2). Step 3: A prime not appearing in the factorisation is not a prime factor of the number.
View question detailsStep 1: Distinct prime factors are identified by the prime bases. Step 2: The bases here are (2) and (3), so there are (2) distinct prime factors. Step 3: The sum of exponents and the count of distinct primes are different ideas.
View question detailsStep 1: Write (400=4 \times 100). Step 2: (4=2^2) and (100=2^2 \times 5^2), so (400=2^4 \times 5^2). Step 3: (4) is not prime, so final factorisation must use only prime bases.
View question detailsStep 1: An even number must have (2) in its prime factorisation. Step 2: Only the third option contains (2), so it forms an even number. Step 3: You do not need to calculate the whole number to check even or odd.
View question detailsStep 1: An odd number does not have (2) as a prime factor. Step 2: The third option has (3,5,7) and no (2), so it forms an odd number. Step 3: If (2) appears, the number is even.
View question detailsStep 1: Add the exponents to find the total frequency of prime factors. Step 2: The exponents are (2,1,2), so the total is (2+1+2=5). Step 3: When no exponent is written, treat it as (1).
View question detailsStep 1: To count total factors, add (1) to each exponent. Step 2: ((3+1)(2+1)=4 \times 3=12). Step 3: Use this method when the number is in prime factorised form.
View question detailsStep 1: Write (90=9 \times 10). Step 2: (9=3^2) and (10=2 \times 5), so (90=2 \times 3^2 \times 5). Step 3: Splitting into easy parts like (9) and (10) is quick.
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