What is the correct prime factorisation of 486?
Step 1: Write (486=2\times243). Step 2: Since (243=3^5), (486=2\times3^5). Step 3: Do not leave 243 in the final answer; write it as a power of 3.
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SubjectsMathematics
अभाज्य गुणनखंडन
In Class 10 Mathematics, under the Real Numbers chapter, Prime Factorisation teaches students to express a composite number as a product of prime numbers. Students practise identifying prime factors and writing factorisations using multiplication and exponents. This foundational skill supports the Fundamental Theorem of Arithmetic and later work with HCF and LCM.
TOPIC PRACTICE
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Step 1: Write (486=2\times243). Step 2: Since (243=3^5), (486=2\times3^5). Step 3: Do not leave 243 in the final answer; write it as a power of 3.
View question detailsStep 1: Write (600=6\times100). Step 2: (6=2\times3) and (100=2^2\times5^2), so (600=2^3\times3\times5^2). Step 3: Be careful while counting the total power of 2.
View question detailsStep 1: Write (675=27\times25). Step 2: (27=3^3) and (25=5^2), so (675=3^3\times5^2). Step 3: 27 and 25 are composite, so convert them into prime powers.
View question detailsStep 1: Write (720=72\times10). Step 2: (72=2^3\times3^2) and (10=2\times5), so (720=2^4\times3^2\times5). Step 3: Break 72 completely into prime form.
View question detailsStep 1: Write (756=27\times28). Step 2: (27=3^3) and (28=2^2\times7), so (756=2^2\times3^3\times7). Step 3: Convert 28 into (2^2\times7).
View question detailsStep 1: Recognise (784=28^2). Step 2: Since (28=2^2\times7), (784=2^4\times7^2). Step 3: In a square number, exponents may be even, so check the powers.
View question detailsStep 1: Write (840=84\times10). Step 2: (84=2^2\times3\times7) and (10=2\times5), so (840=2^3\times3\times5\times7). Step 3: Break all composite factors down to primes.
View question detailsStep 1: Write (900=9\times100). Step 2: (9=3^2) and (100=2^2\times5^2), so (900=2^2\times3^2\times5^2). Step 3: 900 is a square number, so even exponents appear.
View question detailsStep 1: Write (945=27\times35). Step 2: (27=3^3) and (35=5\times7), so (945=3^3\times5\times7). Step 3: Do not forget to change 27 into (3^3).
View question detailsStep 1: (1000) can be written as (10^3). Step 2: Since (10=2\times5), (1000=2^3\times5^3). Step 3: 10 is composite, so write 2 and 5 in the final prime form.
View question detailsStep 1: Divide 1024 repeatedly by 2. Step 2: Ten factors of 2 give (1024=2^{10}). Step 3: 4 and 32 are composite, so write the power of 2 in final prime form.
View question detailsStep 1: Write (1155=11\times105). Step 2: (105=3\times5\times7), so (1155=3\times5\times7\times11). Step 3: 105 is composite, so break it further.
View question detailsStep 1: Write (1176=24\times49). Step 2: (24=2^3\times3) and (49=7^2), so (1176=2^3\times3\times7^2). Step 3: Write both 24 and 49 in prime form.
View question detailsStep 1: Recognise (1225=35^2). Step 2: Since (35=5\times7), (1225=5^2\times7^2). Step 3: 35 is composite, so write prime bases 5 and 7.
View question detailsStep 1: Write (1296=16\times81). Step 2: (16=2^4) and (81=3^4), so (1296=2^4\times3^4). Step 3: Convert 16 and 81 into prime powers.
View question detailsStep 1: Write (1323=27\times49). Step 2: (27=3^3) and (49=7^2), so (1323=3^3\times7^2). Step 3: Do not leave 27 and 49 in the final form.
View question detailsStep 1: Write (1440=144\times10). Step 2: (144=2^4\times3^2) and (10=2\times5), so (1440=2^5\times3^2\times5). Step 3: The total power of 2 is 5, so count it carefully.
View question detailsStep 1: Write (1575=225\times7). Step 2: (225=3^2\times5^2), so (1575=3^2\times5^2\times7). Step 3: Convert 225 into prime powers.
View question detailsStep 1: Recognise (1728=12^3). Step 2: Since (12=2^2\times3), (12^3=2^6\times3^3). Step 3: 12 is composite, so write powers of 2 and 3 in the final prime form.
View question detailsStep 1: (1764=42^2). Step 2: Since (42=2\times3\times7), (1764=2^2\times3^2\times7^2). Step 3: In a square number, each prime power should be even.
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