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In Class 10 Mathematics, under the Real Numbers chapter, Prime Factorisation teaches students to express a composite number as a product of prime numbers. Students practise identifying prime factors and writing factorisations using multiplication and exponents. This foundational skill supports the Fundamental Theorem of Arithmetic and later work with HCF and LCM.
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Medium · Level 12 · real-numbers,common-prime-factors,prime-factorisationView options
Only (2)
Only (3)
(2) and (3)
(5) and (7)
Medium · Level 12 · real-numbers,hcf,prime-factorisationView options
2
3
4
6
Medium · Level 12 · real-numbers,lcm,prime-factorisationView options
3
4
5
8
Medium · Level 12 · real-numbers,prime-factorisation,343View options
(7^2)
(7^3)
(3 \times 7^2)
(49 \times 7)
Medium · Level 12 · real-numbers,even-factors,prime-factorisationView options
12
18
20
24
Medium · Level 12 · real-numbers,odd-factors,prime-factorisationView options
3
4
5
8
Medium · Level 12 · real-numbers,trailing-zeros,general-formView options
(\min(a,b)=5)
(a+b=5)
(a-b=5)
(ab=5)
Medium · Level 12 · real-numbers,number-one,prime-factorisationView options
(1) has no prime factor
(1) is the smallest prime number
(1) is a base in every prime factorisation
The exponent of (1) is always (2)
Medium · Level 12 · real-numbers,fundamental-theorem,prime-factorisationView options
Fundamental theorem of arithmetic
Quadratic formula
Remainder theorem
Triangle area formula
Medium · Level 12 · real-numbers,unknown-exponents,prime-factorisationView options
(a=3, b=3)
(a=4, b=3)
(a=3, b=4)
(a=5, b=2)
Question 1MediumLevel 12
Which prime factors are common in (2^4 \times 3 \times 5) and (2^2 \times 3^3 \times 7)?
Correct answer: C
Step 1: The bases of the first number are (2,3,5). Step 2: The bases of the second number are (2,3,7), so the common primes are (2) and (3). Step 3: For common factors, choose bases present in both numbers.
What will be the exponent of (3) in the HCF of (2^5 \times 3^2 \times 5) and (2^3 \times 3^4 \times 7)?
Correct answer: A
Step 1: In HCF, take the smaller exponent of a common prime. Step 2: The exponents of (3) are (2) and (4), so the smaller exponent is (2). Step 3: For HCF, remember the minimum exponent rule.
What will be the exponent of (2) in the LCM of (2^5 \times 3^2 \times 5) and (2^3 \times 3^4 \times 7)?
Correct answer: C
Step 1: In LCM, take the larger exponent of each prime. Step 2: The exponents of (2) are (5) and (3), so the larger exponent is (5). Step 3: For LCM, choose the maximum exponent.
Step 1: Write (343) as (7 \times 49). Step 2: Since (49=7^2), (343=7^3). Step 3: (49 \times 7) gives the value, but it is not final prime factorisation.
How many factors of (2^3 \times 3^2 \times 5) will be even?
Correct answer: B
Step 1: An even factor must have exponent of (2) at least (1). Step 2: (2) has (3) choices (1,2,3), (3) has (3) choices (0,1,2), and (5) has (2) choices (0,1). Total (18). Step 3: While counting even factors, do not take exponent (0) for (2).
Step 1: In an odd factor, the exponent of (2) must be (0). Step 2: The exponent of (3) can be (0,1,2,3), giving (4) odd factors. Step 3: While counting odd factors, remove (2) completely.
If (N=2^a \times 5^b) has (5) trailing zeros, which statement is correct?
Correct answer: A
Step 1: Trailing zeros are formed by pairs of (2) and (5). Step 2: The number of pairs equals the smaller of (a) and (b). So (\min(a,b)=5). Step 3: For trailing zeros, use the smaller exponent, not the sum.
Which statement about (1) and prime factorisation is correct?
Correct answer: A
Step 1: A prime number has exactly two positive factors. Step 2: (1) has only one positive factor, so it is not prime and has no prime factor. Step 3: Avoid the common mistake of treating (1) as prime.
Which idea explains the uniqueness of prime factorisation?
Correct answer: A
Step 1: Every integer greater than (1) can be written as a product of prime factors. Step 2: This form is unique apart from order, and this comes from the fundamental theorem of arithmetic. Step 3: Remember uniqueness of prime factorisation with this theorem.
If (2^a \times 3^b=432), what are the correct values of (a) and (b)?
Correct answer: B
Step 1: Write (432) as (16 \times 27). Step 2: (16=2^4) and (27=3^3), so (432=2^4 \times 3^3). Hence (a=4, b=3). Step 3: For unknown exponents, split the number into familiar powers.
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