Which is the prime factorisation of 2268?
Step 1: Write (2268=4\times567). Step 2: (4=2^2) and (567=3^4\times7), so (2268=2^2\times3^4\times7). Step 3: Convert 567 into complete prime form.
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SubjectsMathematics
अभाज्य गुणनखंडन
In Class 10 Mathematics, under the Real Numbers chapter, Prime Factorisation teaches students to express a composite number as a product of prime numbers. Students practise identifying prime factors and writing factorisations using multiplication and exponents. This foundational skill supports the Fundamental Theorem of Arithmetic and later work with HCF and LCM.
TOPIC PRACTICE
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Step 1: Write (2268=4\times567). Step 2: (4=2^2) and (567=3^4\times7), so (2268=2^2\times3^4\times7). Step 3: Convert 567 into complete prime form.
View question detailsStep 1: Write (2340=234\times10). Step 2: (234=2\times3^2\times13) and (10=2\times5), so (2340=2^2\times3^2\times5\times13). Step 3: The power of 2 becomes 2.
View question detailsStep 1: Write (2450=2\times1225). Step 2: (1225=5^2\times7^2), so (2450=2\times5^2\times7^2). Step 3: Convert 1225 into prime powers.
View question detailsStep 1: Write (2640=16\times165). Step 2: (16=2^4) and (165=3\times5\times11), so (2640=2^4\times3\times5\times11). Step 3: Break 165 further.
View question detailsStep 1: Write (2835=81\times35). Step 2: (81=3^4) and (35=5\times7), so (2835=3^4\times5\times7). Step 3: Change 81 into (3^4).
View question detailsStep 1: Write (3120=16\times195). Step 2: (16=2^4) and (195=3\times5\times13), so (3120=2^4\times3\times5\times13). Step 3: Give 195 its complete prime form.
View question detailsStep 1: Write (3402=2\times1701). Step 2: (1701=3^5\times7), so (3402=2\times3^5\times7). Step 3: Convert 1701 into prime form using 3 and 7.
View question detailsStep 1: Write (3528=72\times49). Step 2: (72=2^3\times3^2) and (49=7^2), so (3528=2^3\times3^2\times7^2). Step 3: Convert 72 and 49 into prime powers.
View question detailsStep 1: Write (3645=729\times5). Step 2: Since (729=3^6), (3645=3^6\times5). Step 3: 729 should not be left in the final form.
View question detailsStep 1: Write (3888=16\times243). Step 2: (16=2^4) and (243=3^5), so (3888=2^4\times3^5). Step 3: Change 243 into a power of 3.
View question detailsStep 1: Write (3969=81\times49). Step 2: (81=3^4) and (49=7^2), so (3969=3^4\times7^2). Step 3: Write both parts as prime powers.
View question detailsStep 1: Write (2016=32\times63). Step 2: (32=2^5) and (63=3^2\times7), so (2016=2^5\times3^2\times7). Step 3: Comparing gives (a=5).
View question detailsStep 1: (2205=45\times49). Step 2: (45=3^2\times5) and (49=7^2), so (2205=3^2\times5\times7^2). Step 3: Comparing gives (b=2).
View question detailsStep 1: (2450=2\times1225). Step 2: (1225=5^2\times7^2), so (2450=2\times5^2\times7^2). Step 3: Comparing with the given form gives (m=2).
View question detailsStep 1: Write (3888=16\times243). Step 2: (16=2^4) and (243=3^5), so the power of 2 is 4. Step 3: Comparing gives (p=4).
View question detailsStep 1: Calculate (2^3=8) and (3^2=9). Step 2: (8\times9\times11=792). Step 3: First solve the powers, then multiply by 11.
View question detailsStep 1: Calculate (5^2=25). Step 2: (3\times25\times11=825). Step 3: It is useful to simplify the power part first.
View question detailsStep 1: Calculate (2^5=32) and (3^3=27). Step 2: (32\times27=864). Step 3: Simplify both powers separately.
View question detailsStep 1: Calculate (2^2=4). Step 2: (4\times3\times7\times11=924). Step 3: With many factors, multiply in pairs.
View question detailsStep 1: Calculate (2^4=16). Step 2: (16\times3\times5\times13=3120). Step 3: It is easy to first treat (3\times5\times13) as 195 and multiply.
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