What is the prime factorisation of 1536?
Step 1: Write (1536=512\times3). Step 2: (512=2^9), so (1536=2^9\times3). Step 3: Do not keep 512 in the final form; write (2^9).
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SubjectsMathematics
अभाज्य गुणनखंडन
In Class 10 Mathematics, under the Real Numbers chapter, Prime Factorisation teaches students to express a composite number as a product of prime numbers. Students practise identifying prime factors and writing factorisations using multiplication and exponents. This foundational skill supports the Fundamental Theorem of Arithmetic and later work with HCF and LCM.
TOPIC PRACTICE
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Step 1: Write (1536=512\times3). Step 2: (512=2^9), so (1536=2^9\times3). Step 3: Do not keep 512 in the final form; write (2^9).
View question detailsStep 1: Write (1080=108\times10). Step 2: (108=2^2\times3^3) and (10=2\times5), so (1080=2^3\times3^3\times5). Step 3: Count powers of 2 and 3 separately.
View question detailsStep 1: Write (1470=30\times49). Step 2: (30=2\times3\times5) and (49=7^2), so (1470=2\times3\times5\times7^2). Step 3: Convert 49 into (7^2).
View question detailsStep 1: Write (1980=198\times10). Step 2: (198=2\times3^2\times11) and (10=2\times5), so (1980=2^2\times3^2\times5\times11). Step 3: Since 2 appears twice, write (2^2).
View question detailsStep 1: Calculate (2^3=8) and (7^2=49). Step 2: (8\times3\times49=1176). Step 3: Evaluating powers first makes calculation easier.
View question detailsStep 1: (5^2=25) and (7^2=49). Step 2: (25\times49=1225). Step 3: Both powers are 2 in this square form, so multiply carefully.
View question detailsStep 1: Multiply all given prime factors. Step 2: (2\times3\times5\times7\times11=2310). Step 3: When no power is written, each prime is taken once.
View question detailsStep 1: Calculate (2^3=8), (3^2=9), and (5^2=25). Step 2: (8\times9\times25=1800). Step 3: Simplify powers first, then multiply.
View question detailsStep 1: Calculate (2^4=16) and (3^4=81). Step 2: (16\times81=1296). Step 3: Evaluate prime powers and then multiply.
View question detailsStep 1: When a prime repeats, powers are used. Step 2: For example, (2\times2\times2) is written as (2^3). Step 3: This makes the answer short, clear, and easy to read in exams.
View question detailsStep 1: In prime factorisation, a number is written as a product of prime numbers. Step 2: If any composite factor remains, the form is not final. Step 3: In exams, write only prime bases and their powers in the final answer.
View question detailsStep 1: Write (504=8\times63). Step 2: (8=2^3) and (63=3^2\times7), so (504=2^3\times3^2\times7). Step 3: Do not leave composite forms like 8 and 63 in the final answer.
View question detailsStep 1: (528) can be written as (16\times33). Step 2: (16=2^4) and (33=3\times11), so (528=2^4\times3\times11). Step 3: Since 33 is composite, split it into 3 and 11.
View question detailsStep 1: Write (560=16\times35). Step 2: (16=2^4) and (35=5\times7), so (560=2^4\times5\times7). Step 3: Since 35 is composite, write 5 and 7 in the final form.
View question detailsStep 1: Write (630=63\times10). Step 2: (63=3^2\times7) and (10=2\times5), so (630=2\times3^2\times5\times7). Step 3: Do not keep 9 or 35 in the final form.
View question detailsStep 1: (672) can be written as (32\times21). Step 2: (32=2^5) and (21=3\times7), so (672=2^5\times3\times7). Step 3: Since 21 is composite, break it further.
View question detailsStep 1: Write (700=7\times100). Step 2: (100=2^2\times5^2), so (700=2^2\times5^2\times7). Step 3: It is necessary to change 100 into prime powers.
View question detailsStep 1: Write (756=27\times28). Step 2: (27=3^3) and (28=2^2\times7), so (756=2^2\times3^3\times7). Step 3: Give complete prime form to both parts.
View question detailsStep 1: Write (945=27\times35). Step 2: (27=3^3) and (35=5\times7), so (945=3^3\times5\times7). Step 3: Do not forget to change 27 into (3^3).
View question detailsStep 1: Write (980=98\times10). Step 2: (98=2\times7^2) and (10=2\times5), so (980=2^2\times5\times7^2). Step 3: Count the total power of 2 correctly.
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